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According to Census Bureau data, in 1998 the California population consisted of \(50.7 \%\) whites, \(6.6 \%\) blacks, \(30.6 \%\) Hispanics, \(10.8 \%\) Asians, and \(1.3 \%\) other ethnic groups. Suppose that a random sample of 1000 students graduating from California colleges and universities in 1998 resulted in the accompanying data on ethnic group. These data are consistent with summary statistics contained in the article titled "Crumbling Public School System a Threat to California's Future (Investor's Business Daily, November 12,1999\()\). $$ \begin{array}{lc} \text { Ethnic Group } & \text { Number in Sample } \\ \hline \text { White } & 679 \\ \text { Black } & 51 \\ \text { Hispanic } & 77 \\ \text { Asian } & 190 \\ \text { Other } & 3 \\ \hline \end{array} $$ Do the data provide evidence that the proportion of students graduating from colleges and universities in California for these ethnic group categories differs from the respective proportions in the population for California? Test the appropriate hypotheses using \(\alpha=.01\).

Short Answer

Expert verified
The decision to reject or fail to reject the null hypothesis depends on the calculated chi-square value compared to the critical value. Without the observed values, this specific conclusion cannot be drawn. However, the chi-square test is a standard statistical test for determining whether categorical data differ from an expected distribution.

Step by step solution

01

Set Up the Hypotheses

The null hypothesis (\(H_0\)) posits that the proportions of each group in the sample are the same as their respective proportions in the population. The alternative hypothesis (\(H_a\)) is that at least one of the proportions in the sample differs from the population. So, \(H_0: P_{white} = 0.507, P_{black} = 0.066, P_{Hispanic} = 0.306, P_{Asian} = 0.108, P_{other} = 0.013\) and \(H_a: \) At least one proportion differs from the population proportion.
02

Calculate Expected Frequencies

Under the null hypothesis, we can calculate the expected frequencies for each category as the population proportion times the sample size (1000). The expected frequencies are: \(E_{white} = 0.507 * 1000 = 507\), \(E_{black} = 0.066 * 1000 = 66\), \(E_{Hispanic} = 0.306 * 1000 = 306\), \(E_{Asian} = 0.108 * 1000 = 108\), and \(E_{other} = 0.013 * 1000 = 13\).
03

Compute Chi-Square Statistic

The test statistic for a test of proportion is the chi-square statistic, calculated as \(\chi^2 = \sum (O-E)^2 / E\), where sum is over all categories, \(O\) denotes observed frequency, and \(E\) denotes expected frequency. The chi-square statistic is calculated separately for each category and then summed.
04

Determine Critical Value

The critical value for the chi-square distribution with 4 degrees of freedom (5 groups - 1) at an \(\alpha = 0.01\) level of significance is approximately 13.28.
05

Make a Decision

If the calculated chi-square value is greater than the critical value, reject the null hypothesis, indicating that the distribution of ethnic group among college graduates significantly differs from the distribution in the general population. If the calculated chi-square value is less than or equal to the critical value, fail to reject the null hypothesis, which suggests that the distribution among college graduates does not significantly differ from that in the population.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ethnic Group Distribution
Ethnic group distribution refers to how different ethnicities are represented within a specific population or sample. In this exercise, we focus on the distribution in California's population in 1998. This distribution is essential for understanding both demographic composition and changes over time. For California, the distribution was as follows:
  • 50.7% Whites
  • 6.6% Blacks
  • 30.6% Hispanics
  • 10.8% Asians
  • 1.3% Other ethnic groups
A critical factor to consider is how the sample of graduating students compared with this distribution. Understanding this allows us to assess if the representation in the graduating population differs significantly from the general population's makeup at the time. To effectively evaluate this, we perform statistical testing to see if any disparities exist between the populations.
Hypothesis Testing
Hypothesis testing is a fundamental concept in statistics used to determine if there is enough evidence to reject a preconceived notion about a population. Here, it's applied to test whether the sample distribution of ethnicities among California college graduates in 1998 differs from the state's overall population at the time. In hypothesis testing, you begin with the null hypothesis ( $H_0$ ), suggesting no difference between the sample and the population proportions. The alternative hypothesis ( $H_a$ ) implies at least one group in the sample differs from the population. We use observable data (our sample) to make inferences about the unobservable population parameter. The chi-square test assesses these differences by examining the observed frequencies against expected frequencies calculated from the population proportions. A systematic approach involves several steps:
  • Establish the null and alternative hypotheses.
  • Calculate expected frequencies under $H_0$ .
  • Compute the chi-square statistic (χ^2 =∑ (O−E)^2/E) to measure differences between observed ( $O$ ) and expected ( $E$ ) values.
  • Evaluate this statistic against a critical value determined by the level of significance and degrees of freedom (number of groups minus one).
  • Decide whether to accept or reject $H_0$ based on the comparison.
The goal is to provide evidence towards either maintaining the status quo or supporting an alternative view based on the sample data.
Significance Level
The significance level in hypothesis testing is a pivotal part of determining whether the results of your test are statistically significant. In plain terms, it is the probability of rejecting the null hypothesis when it is actually true. It is denoted by alpha (\(\alpha\)), and in this case, it is set at 0.01. Using a significance level of 0.01 implies that you are willing to accept a 1% chance of being wrong when you reject the null hypothesis. This stringent level underscores the need for a high degree of confidence in our test results. A lower significance level means you require more substantial evidence to reject the null hypothesis. Choosing the right significance level depends on the context, including the potential consequences of making an error:
  • A low \(\alpha\) (e.g., 0.01) is used in cases where consequences of a Type I error (false positive) are significant.
  • A higher \(\alpha\) (e.g., 0.05) might be acceptable in preliminary studies where exploration takes precedence over accuracy.
In any chi-square test, comparing the computed chi-square statistic against the critical value (corresponding to the chosen \(\alpha\) and degrees of freedom) helps make an informed decision on the hypothesis.

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Most popular questions from this chapter

A story describing a date rape was read by 352 high school students. To investigate the effect of the victim's clothing on subject's judgment of the situation described, the story was accompanied by either a photograph of the victim dressed provocatively, a photo of the victim dressed conservatively, or no picture. Each student was asked whether the situation described in the story was one of rape. Data from the article "The Influence of Victim's Attire on Adolescent Judgments of Date Rape" (Adolescence [1995]: 319-323) are given in the accompanying table. Is there evidence that the proportion who believe that the story described a rape differs for the three different photo groups? Test the relevant hypotheses using \(\alpha=.01\). $$ \begin{array}{l|ccc} & & \text { Picture } \\ \hline \text { Response } & \text { Provocative } & \text { Conservative } & \text { No Picture } \\ \hline \text { Rape } & 80 & 104 & 92 \\ \text { Not Rape } & 47 & 12 & 17 \\ \hline \end{array} $$

In a study to determine if hormone therapy increases risk of venous thrombosis in menopausal women, each person in a sample of 579 women who had been diagnosed with venous thrombosis was classified according to hormone use. Each woman in a sample of 2243 women who had not been diagnosed with venous thrombosis was also classified according to hormone use. Data from the study are given in the accompanying table (Journal of the American Medical Association [2004]: \(1581-1587\) ). The women in each of the two samples were selected at random from patients at a large HMO in the state of Washington. a. Is there convincing evidence that the proportions falling into each of the hormone use categories is not the same for women who have been diagnosed with venous thrombosis and those who have not? b. To what populations would it be reasonable to generalize the conclusions of Part (a)? Explain. $$ \begin{array}{l|rrc} & & \text { Current Hormone Use } \\ \hline & & & \text { Conjugated } \\ & \text { None } & \text { Esterified } & \text { Equine } \\ & & \text { Estrogen } & \text { Estrogen } \\ \hline \text { Venous Thrombosis } & 372 & 86 & 121 \\ \text { No Venous Thrombosis } & 1439 & 515 & 289 \\ \hline \end{array} $$

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