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The article "Linkage Studies of the Tomato" (Transactions of the Royal Canadian Institute [1931]:1-19) reported the accompanying data on phenotypes resulting from crossing tall cut-leaf tomatoes with dwarf potato-leaf tomatoes. There are four possible phenotypes: (1) tall cut-leaf, (2) tall potato-leaf, (3) dwarf cutleaf, and (4) dwarf potato-leaf. $$ \begin{array}{c|cccc} & {\text { Phenotype }} \\ & 1 & 2 & 3 & 4 \\ \hline \text { Frequency } & 926 & 288 & 293 & 104 \\ \hline \end{array} $$ Mendel's laws of inheritance imply that \(p_{1}=9 / 16, p_{2}=\) \(3 / 16, p_{3}=3 / 16\), and \(p_{4}=1 / 16\). Are the data from this experiment consistent with Mendel's laws? Use a .01 significance level.

Short Answer

Expert verified
To determine whether the data is consistent with Mendel's laws, a chi-square goodness-of-fit test needs to be conducted and the calculated chi-square test statistic should be compared with the critical value from the chi-square distribution table.

Step by step solution

01

Define Null and Alternative Hypotheses

The null hypothesis (H0) states that the data is consistent with Mendel's laws, i.e. the observed proportions match the expected proportions. The alternative hypothesis (H1) states that the data is not consistent with Mendel's laws, i.e. the observed proportions differ from the expected proportions.
02

Calculate Expected Frequencies

To calculate the expected frequencies, multiply the total number of observations by the expected proportions, \(p_1\), \(p_2\), \(p_3\) and \(p_4\). The total number of observations is the sum of the observed frequencies (926+288+293+104 = 1611). Therefore, \(E_1 = 1611 * (9/16)\), \(E_2 = 1611 * (3/16)\), \(E_3 = 1611 * (3/16)\), \(E_4 = 1611 * (1/16)\).
03

Calculate Test Statistic

The chi-square test statistic is calculated using the formula \(\chi^2 = \sum( (O-E)^2 / E )\), where O are the observed frequencies and E are the expected frequencies. Plug in the above values to get: \(\chi^2 = ((926-E_1)^2 / E_1) + ((288-E_2)^2 / E_2) + ((293-E_3)^2 / E_3) + ((104-E_4)^2 / E_4)\)
04

Determine Significance

Refer to a chi-square distribution table with 3 degrees of freedom (since there are 4 categories, the degrees of freedom is 4-1=3). The critical value for a 0.01 significance level is approximately 11.34. If the calculated chi-square statistic is greater than 11.34, reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mendel's Laws of Inheritance
Mendel's Laws form the foundation of genetic inheritance studies. Gregor Mendel, through his experiments with pea plants, discovered that traits are passed from parents to offspring in predictable ways. These laws are primarily:
  • **Law of Segregation**: Each organism carries two alleles for each trait, which separate during the formation of gametes, resulting in offspring inheriting one allele from each parent.
  • **Law of Independent Assortment**: Alleles of different traits are distributed to gametes independently of one another, which means the inheritance of one trait generally doesn鈥檛 affect the inheritance of another.
In the textbook problem, Mendel's laws predict specific proportions for each of the four phenotypes of tomatoes, based on the inheritance patterns of two pairs of alleles. The expected ratios provided are a direct application of Mendel's insights. For example, 9/16 for the first phenotype reflects complex interactions of dominant and recessive alleles.
Understanding the Null Hypothesis
The null hypothesis ( H_0 ) is a fundamental concept in statistics, serving as a default position that there is no effect or no difference. In the context of the chi-square test, it allows us to assess whether any observed deviations from expected frequencies are due to random chance.
In this exercise, the null hypothesis posits that the observed tomato phenotypes occur in proportions predicted by Mendel's laws, suggesting no real departure from these theoretical ratios.
The alternative hypothesis ( H_1 ) would claim the opposite, that the observed data do not fit the expected distribution, potentially indicating influences beyond simple Mendelian genetics.
Testing the null hypothesis helps determine whether any observed discrepancies are statistically significant or if they could simply be the result of random variation in the sample data.
Calculating Expected Frequencies
Expected frequencies are calculated under the assumption that the null hypothesis is true, providing a theoretical distribution to compare against observed data. For this problem, you calculate expected frequencies using the total number of observations and Mendel's expected proportions:
  • For phenotype 1, expect: \( E_1 = 1611 \times \frac{9}{16} \)
  • For phenotype 2, expect: \( E_2 = 1611 \times \frac{3}{16} \)
  • For phenotype 3, expect: \( E_3 = 1611 \times \frac{3}{16} \)
  • For phenotype 4, expect: \( E_4 = 1611 \times \frac{1}{16} \)
These computations give you the expected frequencies or counts for each phenotype if Mendel's law applies perfectly to the sample. Comparing these expected frequencies with observed ones helps determine if deviations are significant.
Significance Level in Hypothesis Testing
The significance level, often denoted as \( \alpha \), is a threshold set by the researcher to decide if an observed effect is statistically significant. A common significance level is 0.01, as used in this problem. It defines the probability of rejecting the null hypothesis when it is actually true.
Here's a simple breakdown:
  • A significance level of 0.01 means there's a 1% risk of concluding that Mendel's laws do not apply if they actually do.
  • The critical value, for example, 11.34 in this case, is derived from the chi-square distribution with appropriate degrees of freedom. It marks the boundary beyond which the null hypothesis would be rejected.
By comparing the calculated chi-square statistic to this critical value, the researcher determines whether the deviation from expected frequencies is significant enough to reject H_0. Understanding and correctly applying this concept is crucial for valid statistical inference.

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Most popular questions from this chapter

The authors of the paper 鈥淩acial Stereotypes in Children's Television Commercials鈥 (Journal of Advertising Research [2008]: 80-93) counted the number of times that characters of different ethnicities appeared in commercials aired on Philadelphia television stations, resulting in the data in the accompanying table. $$ \begin{array}{l|cccc} \hline \text { Ethnicity } & \begin{array}{l} \text { African- } \\ \text { American } \end{array} & \text { Asian } & \text { Caucasian } & \text { Hispanic } \\ \hline \begin{array}{c} \text { Observed } \\ \text { Frequency } \end{array} & 57 & 11 & 330 & 6 \\ \hline \end{array} $$ Based on the 2000 Census, the proportion of the U.S. population falling into each of these four ethnic groups are \(.177\) for African-American, \(.032\) for Asian, \(.734\) for Caucasian, and \(.057\) for Hispanic. Do the data provide sufficient evidence to conclude that the proportions appearing in commercials are not the same as the census proportions? Test the relevant hypotheses using a significance level of .01.

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