/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 When coastal power stations take... [FREE SOLUTION] | 91影视

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When coastal power stations take in large quantities of cooling water, it is inevitable that a number of fish are drawn in with the water. Various methods have been designed to screen out the fish. The article "Multiple \(\mathrm{Re}-\) gression Analysis for Forecasting Critical Fish Influxes at Power Station Intakes" (Journal of Applied Ecology [1983]: 33-42) examined intake fish catch at an English power plant and several other variables thought to affect fish intake: $$ \begin{aligned} y &=\text { fish intake (number of fish) } \\ x_{1} &=\text { water temperature }\left({ }^{\circ} \mathrm{C}\right) \\ x_{2} &=\text { number of pumps running } \\ x_{3} &=\text { sea state }(\text { values } 0,1,2, \text { or } 3) \\ x_{4} &=\text { speed }(\text { knots }) \end{aligned} $$ Part of the data given in the article were used to obtain the estimated regression equation $$ \hat{y}=92-2.18 x_{1}-19.20 x_{2}-9.38 x_{3}+2.32 x_{4} $$ (based on \(n=26\) ). SSRegr \(=1486.9\) and SSResid = \(2230.2\) were also calculated. a. Interpret the values of \(b_{1}\) and \(b_{4}\). b. What proportion of observed variation in fish intake can be explained by the model relationship? c. Estimate the value of \(\sigma\). d. Calculate adjusted \(R^{2}\). How does it compare to \(R^{2}\) itself?

Short Answer

Expert verified
Part a: \(b_1\) represents a decrease of 2.18 in fish intake for every increase in water temperature while keeping other factors constant, and \(b_4\) represents an increase of 2.32 in fish intake for every increment in speed, keeping other factors constant. Part b: Approximately 40% of the variation in fish intake can be explained by the variables in this regression model. Part c: \(\sigma\) can be estimated using the provided formula and given SSResid value. Part d: Adjusted \(R^{2}\) can be estimated using the given formula and then compared to \(R^{2}\). The detailed values for \(\sigma\) and Adjusted \(R^{2}\) can be calculated using a calculator or software.

Step by step solution

01

Interpretation of \(b_{1}\) and \(b_{4}\) Values

For every unit increase in water temperature (x鈧), fish intake (y) decreases by 2.18, assuming all other variables are constant. Similarly, for every unit increase in speed (x鈧), fish intake (y) increases by 2.32, assuming all other variables are constant. This tells us about the effects of water temperature and speed on fish intake at the power plant.
02

Calculation of \(R^{2}\) and Interpretation

\(R^{2}\), the coefficient of determination, is calculated from the formula \[R^{2} = \frac{SSRegr}{SSTotal}= \frac{SSRegr}{SSRegr + SSResid} \] So, \(R^{2}\) = 1486.9 / (1486.9 + 2230.2) = 0.3998, or approximately 0.4. This means 40% of the variation in fish intake can be explained by this model.
03

Estimation of \(\sigma\)

The value of \(\sigma\) (standard deviation of the residuals) can be estimated by the formula \[ \sigma = \sqrt{\frac{SSResid}{n-p-1}}\] where, n is the sample size and p is the number of predictors. Thus, \(\sigma\) = \(\sqrt{\frac{2230.2}{26 - 4 - 1}}\). Place these values into a calculator to get an estimation of \(\sigma\).
04

Calculation and Comparison of Adjusted \(R^{2}\)

The adjustment in the \(R^{2}\) value takes the number of predictors into account, which is better for comparison purposes if models have different numbers of predictors. It is calculated as follows: \[Adjusted \ R^{2} = 1 - (1 - R^{2})\frac{n-1}{n-p-1}\] where n is the number of observations and p is the number of predictors. Inserting the known values, the calculation of adjusted \(R^{2}\) can be made, and then it can be compared with \(R^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Coefficients
In a multiple regression analysis, regression coefficients are pivotal in understanding how each predictor variable impacts the dependent variable. These coefficients indicate the expected change in the dependent variable for a one-unit change in the predictor, holding all other predictors constant.

For the given regression equation \[ \hat{y} = 92 - 2.18 x_{1} - 19.20 x_{2} - 9.38 x_{3} + 2.32 x_{4} \]let's interpret the coefficients:
  • **Water Temperature (\(x_{1}\)**): The coefficient -2.18 suggests that as the water temperature increases by 1 degree Celsius, the fish intake decreases by 2.18 fish, assuming all other factors remain unchanged.
  • **Speed (\(x_{4}\)): The coefficient 2.32 shows that an increase in speed by 1 knot results in an increase of 2.32 fish in the intake, with other conditions held fixed.
These coefficients help predict how each factor influences the fish intake, aiding in strategic planning and operational decisions at the power station.
Coefficient of Determination
The Coefficient of Determination, denoted as \(R^2\), is a measure that provides insights into how well the regression model explains the variability of the dependent variable. In simpler terms, it tells us the proportion of variation in the outcome that is predictable from the predictors.

The formula used for calculating \(R^2\) is:\[R^{2} = \frac{SSRegr}{SSTotal} = \frac{SSRegr}{SSRegr + SSResid} \]For the given dataset, \(R^{2}\) = 0.4, indicating that 40% of the variance in fish intake can be attributed to the model.

This value suggests a moderate fit, meaning that while some variation is captured, there is still a significant portion (60%) that is unexplained by the model. This insight can guide further refinement of the model by potentially introducing new variables or insights.
Standard Deviation of Residuals
The Standard Deviation of Residuals, often represented as \(\sigma\), is a measure of how much the observed values deviate from the values predicted by the regression model. In essence, it informs us about the typical size of the prediction errors.

Calculating \(\sigma\) involves the formula:\[ \sigma = \sqrt{\frac{SSResid}{n-p-1}} \]
where \(n\) equals the sample size, and \(p\) is the number of predictors in the model. In this example, substituting the provided values gives:\[ \sigma = \sqrt{\frac{2230.2}{26 - 4 - 1}} \]

Calculating this yields an estimate for \(\sigma\), which provides a useful metric of the regression model's precision. A smaller \(\sigma\) suggests that the model predictions are close to the actual data, while a larger \(\sigma\) would mean more significant prediction errors.
Adjusted R-squared
The Adjusted \(R^2\) is an improved version of the standard \(R^2\), which takes into account the number of predictors in the model. Adjusted \(R^2\) is particularly useful when comparing models with a different number of predictors, as it provides a more accurate assessment by penalizing the inclusion of unnecessary predictors.

The formula for Adjusted \(R^2\) is: \[Adjusted \ R^{2} = 1 - (1 - R^{2})\frac{n-1}{n-p-1}\]Using this formula and the given values, let's substitute and solve:\[Adjusted \ R^{2} = 1 - (1 - 0.4)\frac{26-1}{26-4-1}\]

The Adjusted \(R^2\) will always be less than or equal to \(R^2\). This example allows us to see how much the predictive power of the model decreases when accounting for the number of predictors used. It becomes a valuable tool in minimizing overfitting and ensuring model simplicity.

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Most popular questions from this chapter

Suppose that a multiple regression data set consists of \(n=15\) observations. For what values of \(k\), the number of model predictors, would the corresponding model with \(R^{2}=.90\) be judged useful at significance level \(.05 ?\) Does such a large \(R^{2}\) value necessarily imply a useful model? Explain.

The article "Readability of Liquid Crystal Displays: A Response Surface" (Human Factors \([1983]: 185-190\) ) used a multiple regression model with four independent variables, where \(y=\) error percentage for subjects reading a four-digit liquid crystal display $$ \begin{aligned} &\left.x_{1}=\text { level of backlight (from } 0 \text { to } 122 \mathrm{~cd} / \mathrm{m}\right) \\ &x_{2}=\text { character subtense }\left(\text { from } .025^{\circ} \text { to } 1.34^{\circ}\right) \end{aligned} $$ \(x_{3}=\) viewing angle \(\left(\right.\) from \(0^{\circ}\) to \(60^{\circ}\) ) \(x_{4}=\) level of ambient light (from 20 to \(1500 \mathrm{~lx}\) ) The model equation suggested in the article is $$ y=1.52+.02 x_{1}-1.40 x_{2}+.02 x_{3}-.0006 x_{4}+e $$ a. Assume that this is the correct equation. What is the mean value of \(y\) when \(x_{1}=10, x_{2}=.5, x_{3}=50\), and \(x_{4}=100 ?\) b. What mean error percentage is associated with a backlight level of 20 , character subtense of \(.5\), viewing angle of 10, and ambient light level of 30 ? c. Interpret the values of \(\beta_{2}\) and \(\beta_{3}\)

The article "The Undrained Strength of Some Thawed Permafrost Soils" (Canadian Geotechnical Journal \([1979]: 420-427\) ) contained the accompanying data (see page 778 ) on \(y=\) shear strength of sandy soil \((\mathrm{kPa})\), \(x_{1}=\) depth \((\mathrm{m})\), and \(x_{2}=\) water content \((\%) .\) The predicted values and residuals were computed using the estimated regression equation $$ \begin{aligned} \hat{y}=&-151.36-16.22 x_{1}+13.48 x_{2}+.094 x_{3}-.253 x_{4} \\ &+.492 x_{5} \\ \text { where } x_{3} &=x_{1}^{2}, x_{4}=x_{2}^{2}, \text { and } x_{5}=x_{1} x_{2} \end{aligned} $$ $$ \begin{array}{clrrrrr} \text { Product } & \text { Material } & \text { Height } & \begin{array}{l} \text { Maximum } \\ \text { Width } \end{array} & \begin{array}{l} \text { Minimum } \\ \text { Width } \end{array} & \text { Elongation } & \text { Volume } \\ \hline 1 & \text { glass } & 7.7 & 2.50 & 1.80 & 1.50 & 125 \\ 2 & \text { glass } & 6.2 & 2.90 & 2.70 & 1.07 & 135 \\ 3 & \text { glass } & 8.5 & 2.15 & 2.00 & 1.98 & 175 \\ 4 & \text { glass } & 10.4 & 2.90 & 2.60 & 1.79 & 285 \\ 5 & \text { plastic } & 8.0 & 3.20 & 3.15 & 1.25 & 330 \\ 6 & \text { glass } & 8.7 & 2.00 & 1.80 & 2.17 & 90 \\ 7 & \text { glass } & 10.2 & 1.60 & 1.50 & 3.19 & 120 \\ 8 & \text { plastic } & 10.5 & 4.80 & 3.80 & 1.09 & 520 \\ 9 & \text { plastic } & 3.4 & 5.90 & 5.00 & 0.29 & 330 \\ 10 & \text { plastic } & 6.9 & 5.80 & 4.75 & 0.59 & 570\\\ 11 & \text { tin } & 10.9 & 2.90 & 2.80 & 1.88 & 340 \\ 12 & \text { plastic } & 9.7 & 2.45 & 2.10 & 1.98 & 175 \\ 13 & \text { glass } & 10.1 & 2.60 & 2.20 & 1.94 & 240 \\ 14 & \text { glass } & 13.0 & 2.60 & 2.60 & 2.50 & 240 \\ 15 & \text { glass } & 13.0 & 2.70 & 2.60 & 2.41 & 360 \\ 16 & \text { glass } & 11.0 & 3.10 & 2.90 & 1.77 & 310 \\ 17 & \text { cardboard } & 8.7 & 5.10 & 5.10 & 0.85 & 635 \\ 18 & \text { cardboard } & 17.1 & 10.20 & 10.20 & 0.84 & 1250 \\ 19 & \text { glass } & 16.5 & 3.50 & 3.50 & 2.36 & 650 \\ 20 & \text { glass } & 16.5 & 2.70 & 1.20 & 3.06 & 305 \\ 21 & \text { glass } & 9.7 & 3.00 & 1.70 & 1.62 & 315 \\ 22 & \text { glass } & 17.8 & 2.70 & 1.75 & 3.30 & 305 \\ 23 & \text { glass } & 14.0 & 2.50 & 1.70 & 2.80 & 245 \\ 24 & \text { glass } & 13.6 & 2.40 & 1.20 & 2.83 & 200 \\ 25 & \text { plastic } & 27.9 & 4.40 & 1.20 & 3.17 & 1205 \\ 26 & \text { tin } & 19.5 & 7.50 & 7.50 & 1.30 & 2330 \\ 27 & \text { tin } & 13.8 & 4.25 & 4.25 & 1.62 & 730 \end{array} $$ $$ \begin{array}{rrrrr} {\boldsymbol{y}} & {\boldsymbol{x}_{1}} & \boldsymbol{x}_{2} & \text { Predicted } \boldsymbol{y} & {\text { Residual }} \\ \hline 14.7 & 8.9 & 31.5 & 23.35 & -8.65 \\ 48.0 & 36.6 & 27.0 & 46.38 & 1.62 \\ 25.6 & 36.8 & 25.9 & 27.13 & -1.53 \\ 10.0 & 6.1 & 39.1 & 10.99 & -0.99 \\ 16.0 & 6.9 & 39.2 & 14.10 & 1.90 \\ 16.8 & 6.9 & 38.3 & 16.54 & 0.26 \\ 20.7 & 7.3 & 33.9 & 23.34 & -2.64 \\ 38.8 & 8.4 & 33.8 & 25.43 & 13.37 \\ 16.9 & 6.5 & 27.9 & 15.63 & 1.27 \\ 27.0 & 8.0 & 33.1 & 24.29 & 2.71 \\ 16.0 & 4.5 & 26.3 & 15.36 & 0.64 \\ 24.9 & 9.9 & 37.8 & 29.61 & -4.71 \\ 7.3 & 2.9 & 34.6 & 15.38 & -8.08 \\ 12.8 & 2.0 & 36.4 & 7.96 & 4.84 \\ \hline \end{array} $$ a. Use the given information to compute SSResid, SSTo, and SSRegr. b. Calculate \(R^{2}\) for this regression model. How would you interpret this value? c. Use the value of \(R^{2}\) from Part (b) and a .05 level of significance to conduct the appropriate model utility test.

The relationship between yield of maize, date of planting, and planting density was investigated in the article "Development of a Model for Use in Maize Replant Decisions" (Agronomy Journal [1980]: 459-464). Let \(\begin{aligned} y &=\text { percent maize yield } \\ x_{1} &=\text { planting date }(\text { days after April 20 }) \\ x_{2} &=\text { planting density (plants/ha) } \end{aligned}\) The regression model with both quadratic terms \((y=\alpha+\) \(\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3}+\beta_{4} x_{4}+e\) where \(x_{3}=x_{1}^{2}\) and \(x_{4}=x_{2}^{2}\) ) provides a good description of the relationship between \(y\) and the independent variables. a. If \(\alpha=21.09, \beta_{1}=.653, \beta_{2}=.0022, \beta_{3}=-.0206\), and \(\beta_{4}=.00004\), what is the population regression function? b. Use the regression function in Part (a) to determine the mean yield for a plot planted on May 6 with a density of 41,180 plants/ha. c. Would the mean yield be higher for a planting date of May 6 or May 22 (for the same density)? d. Is it legitimate to interpret \(\beta_{1}=.653\) as the true average change in yield when planting date increases by one day and the values of the other three predictors are held fixed? Why or why not?

The article "The Value and the Limitations of High-Speed Turbo-Exhausters for the Removal of Tar-Fog from Carburetted Water-Gas" (Society of Chemical Industry Journal \([1946]: 166-168)\) presented data on \(y=\operatorname{tar}\) content (grains/100 \(\mathrm{ft}^{3}\) ) of a gas stream as a function of \(x_{1}=\) rotor speed \((\mathrm{rev} / \mathrm{min})\) and \(x_{2}=\) gas inlet temperature \(\left({ }^{\circ} \mathrm{F}\right) .\) A regression model using \(x_{1}, x_{2}, x_{3}=x_{2}^{2}\) and \(x_{4}=x_{1} x_{2}\) was suggested: $$ \begin{aligned} \text { mean } y \text { value }=& 86.8-.123 x_{1}+5.09 x_{2}-.0709 x_{3} \\ &+.001 x_{4} \end{aligned} $$ a. According to this model, what is the mean \(y\) value if \(x_{1}=3200\) and \(x_{2}=57 ?\) b. For this particular model, does it make sense to interpret the value of any individual \(\beta_{i}\left(\beta_{1}, \beta_{2}, \beta_{3}\right.\), or \(\left.\beta_{4}\right)\) in the way we have previously suggested? Explain.

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