/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A random sample of \(n=900\) obs... [FREE SOLUTION] | 91Ó°ÊÓ

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A random sample of \(n=900\) observations from a binomial population produced \(x=655\) successes. Estimate the binomial proportion \(p\) and calculate the margin of error.

Short Answer

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Question: Using a sample of 900 with 655 successes, estimate the proportion of the binomial population with a 95% confidence interval. Calculate the margin of error for this estimation. Answer: The estimated binomial proportion (p) with a 95% confidence interval is approximately $$\frac{655}{900} \pm 1.96*\sqrt{\frac{\frac{655}{900}(1 - \frac{655}{900})}{900}}$$.

Step by step solution

01

Calculate the sample proportion, \(\hat{p}\)

To calculate the sample proportion, we divide the number of successes by the sample size: $$\hat{p} = \frac{x}{n}$$ Plugging in the values given in the exercise, we have: $$\hat{p} = \frac{655}{900}$$
02

Calculate the standard error

Using the sample proportion \(\hat{p}\) and the sample size \(n\), we can evaluate the standard error for the binomial proportion. The formula is: $$SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}$$ Substituting the values from Step 1, we have:$$SE = \sqrt{\frac{\frac{655}{900}(1 - \frac{655}{900})}{900}}$$
03

Find the margin of error

To calculate the margin of error, we need to multiply the standard error by the z-score for the desired level of confidence. For a 95\% confidence interval, the z-score is approximately 1.96. Plugging the calculated standard error into the margin of error formula, we get: $$Margin\_of\_Error = Z\_*SE$$ $$Margin\_of\_Error=1.96*\sqrt{\frac{\frac{655}{900}(1 - \frac{655}{900})}{900}}$$ Now that we have calculated the sample proportion \(\hat{p}\) and the margin of error, we can estimate the binomial proportion \(p\) with a confidence interval by following the final step.
04

Estimate the binomial proportion \(p\)

To estimate \(p\), we need to create a confidence interval using the sample proportion \(\hat{p}\) and the margin of error. The lower bound of the interval is \(\hat{p} - Margin\_of\_Error\), while the upper bound is \(\hat{p} + Margin\_of\_Error\). From Step 1, we found \(\hat{p}=\frac{655}{900}\). From Steps 2 and 3, we found the margin of error to be \(1.96*\sqrt{\frac{\frac{655}{900}(1 - \frac{655}{900})}{900}}\). So the binomial proportion \(p\) estimate with a 95\% confidence interval can be expressed as: $$p \approx \hat{p} \pm Margin\_of\_Error = \frac{655}{900} \pm 1.96*\sqrt{\frac{\frac{655}{900}(1 - \frac{655}{900})}{900}}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion, denoted as \( \hat{p} \), is an estimate of the true proportion of successes in a population based on a sample. To calculate it, you divide the number of successful outcomes \( x \) by the total number of observations \( n \) in your sample. This ratio gives a snapshot of the proportion that may exist in the larger population.
For instance, if you have collected data from 900 people and 655 of them represent a successful outcome, the sample proportion \( \hat{p} \) would be:
  • \( \hat{p} = \frac{655}{900} \)
  • This represents approximately 0.7278 or 72.78% of your sample experiencing success.
This statistic forms the foundation of estimating the true binomial proportion \( p \). It is derived from real data and guides further calculations.
Standard Error
Standard Error (SE) provides a measure of the variability or dispersion of a sample statistic in relation to the true population parameter. In the context of estimating a binomial proportion, the standard error helps understand how much \( \hat{p} \) may vary from the actual proportion \( p \) due to random sampling error.
The formula for standard error is:
  • \[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \]
Where:
  • \( \hat{p} \) is the sample proportion,
  • \( n \) is the sample size.
This measures the average distance the sample proportion \( \hat{p} \) would fall from the true population proportion if we were to take multiple samples.
In our example, it helps us gauge the reliability of \( \hat{p} = \frac{655}{900} \), providing a mathematical basis to decide how close this sample proportion is likely to be to the actual population proportion.
Margin of Error
The Margin of Error quantifies the extent of the uncertainty or potential error in an estimate due to sampling variability. It reflects the range within which the true population proportion \( p \) is expected to lie, at a certain confidence level, considering the observed sample proportion \( \hat{p} \).
To calculate it, we multiply the standard error by the critical value from the standard normal distribution (z-score) corresponding to the desired confidence level:
  • \[ Margin\_of\_Error = Z \times SE \]
For a 95% confidence interval, the z-score is typically about 1.96.
In the example, this calculation informs us about the extent of error we might expect from our sample estimate:\[ Margin\_of\_Error = 1.96 \times \text{SE} \]
This helps create a more informed confidence interval, establishing bounds within which the true population proportion is likely found.
Confidence Interval
A Confidence Interval provides a range of values which likely includes the true population parameter, here the binomial proportion \( p \). It combines the sample proportion \( \hat{p} \) with the margin of error to convey this uncertainty.
The confidence interval is calculated with:
  • Lower limit: \( \hat{p} - Margin\_of\_Error \)
  • Upper limit: \( \hat{p} + Margin\_of\_Error \)
This range reflects the precision of \( \hat{p} \), implying that with a certain level of confidence (commonly 95%), the interval bounds will contain the true proportion \( p \) in the population.
For our example:
  • The lower bound is \( \frac{655}{900} - 1.96 \times SE \)
  • The upper bound is \( \frac{655}{900} + 1.96 \times SE \)
This statistical method reassures us that the true proportion is around our estimated \( \hat{p} \), offering a reliable insight into population behaviors, even when we can only observe a sample.

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Most popular questions from this chapter

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