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In an Advertising Age white paper concerning the changing role of women as "breadwinners" in the American family, it was reported that according to their survey with JWT, working men reported doing 54 minutes of household chores a day, while working women reported tackling 72 minutes daily. But when examined more closely, Millennial men reported doing just as many household chores as the average working women, 72 minutes, compared to an average of 54 minutes among both Boomer men and Xer men. \({ }^{6}\) The information that follows is adapted from these data and is based on random samples of 1136 men and 795 women. a. Construct a \(95 \%\) confidence interval for the average time all men spend doing household chores. b. Construct a \(95 \%\) confidence interval for the average time women spend doing household chores.

Short Answer

Expert verified
Based on the given survey data and hypothetical standard deviations, we calculated the 95% confidence intervals for the average time spent on household chores by men and women. For men, the 95% confidence interval is approximately (53.1241, 54.8759) minutes, and for women, it is approximately (70.7507, 73.2493) minutes.

Step by step solution

01

Confidence Interval for Men

To construct the 95% confidence interval for the average time all men spend doing household chores, we are given that the sample mean (54 minutes), the sample size (1136 men), and the Z-score (1.96 for a 95% CI). However, the sample standard deviation is not provided. To still be able to help with the exercise, let's consider a hypothetical sample standard deviation, let's say 15 minutes. 1. Calculate the Standard Error: SE = sample_std_dev / sqrt(sample_size) SE = 15 / sqrt(1136) ≈ 0.4469 2. Calculate the Margin of Error: ME = Z-score * SE ME = 1.96 * 0.4469 ≈ 0.8759 3. The confidence interval is (sample_mean - ME, sample_mean + ME), so: CI = (54 - 0.8759, 54 + 0.8759) ≈ (53.1241, 54.8759) For the men, the 95% confidence interval for the average time spent doing household chores is approximately (53.1241, 54.8759) minutes.
02

Confidence Interval for Women

To construct the 95% confidence interval for the average time women spend doing household chores, we are given that the sample mean (72 minutes), the sample size (795 women), and the Z-score (1.96 for a 95% CI). Similar to the previous calculation we will consider a hypothetical sample standard deviation for women, let's say 18 minutes. 1. Calculate the Standard Error: SE = sample_std_dev / sqrt(sample_size) SE = 18 / sqrt(795) ≈ 0.6373 2. Calculate the Margin of Error: ME = Z-score * SE ME = 1.96 * 0.6373 ≈ 1.2493 3. The confidence interval is (sample_mean - ME, sample_mean + ME), so: CI = (72 - 1.2493, 72 + 1.2493) ≈ (70.7507, 73.2493) For the women, the 95% confidence interval for the average time spent doing household chores is approximately (70.7507, 73.2493) minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Inference
Statistical inference is a fundamental concept in statistics that helps us make sense of data collected from samples and to generalize results to a larger population. Imagine you surveyed a small group of people about their preferences. Based on the results, you can make an educated guess or prediction about the preferences of the whole population. This process of making predictions or generalizations is what we call statistical inference.

When working with statistical inference, we are primarily focused on two areas:
  • Estimating population parameters, such as the population mean or proportion, using sample data.
  • Testing hypotheses about population parameters, to support or refute claims about the data.
It assumes that the sample is a true representative of the population, minimizing biases and errors. With statistical inference, you can make data-driven decisions with confidence, even if you cannot study the entire population directly.
Sample Mean
The sample mean is one of the most crucial statistics we can calculate. It serves as an estimate of the true population mean when a full population study is not feasible. Essentially, the sample mean is the average of a set of observations or data points collected from a sample.

Let's revisit our exercise — think of the men surveyed. From the data, we found that on average, they spent 54 minutes on household chores daily. This average, or mean, provides a central point around which we can understand overall trends in the data. It's calculated as:\[\bar{x} = \frac{\sum{X_i}}{n}\]where \( \sum{X_i} \) represents the sum of all sampled values, and \( n \) is the total number of samples.

By calculating the sample mean, we gain insights into the tendencies of the larger population without needing to measure every individual.
Standard Error
The standard error (SE) is vital in understanding how the sample mean reflects the population mean. It's a measure of the variability or dispersion of the sample means we might get if we took multiple samples from our population. Essentially, it tells us how much we can expect the sample mean to fluctuate from the actual population mean.

To calculate the standard error, you divide the sample standard deviation by the square root of the sample size:\[SE = \frac{\text{sample standard deviation}}{\sqrt{n}}\]In our exercise, for instance, using a hypothetical standard deviation of 15 minutes for men, and given that 1136 men were surveyed, the standard error became quite small, indicating we can be quite certain of our mean's accuracy.

This small SE suggests our sample mean is likely close to the true population mean. This precision is crucial in constructing reliable confidence intervals.
Margin of Error
The margin of error (ME) is one of the key components in understanding confidence intervals. It quantifies the range within which we expect the true population parameter to exist. Essentially, it tells us how much "wiggle room" we have around the sample mean.

The margin of error is calculated by multiplying the standard error by the Z-score, which depends on the confidence level we desire (usually 95% or 99%). In our exercise, a confidence level of 95% gives us a Z-score of 1.96. So, for men, with a standard error of approximately 0.4469, the margin of error was calculated as:\[ME = 1.96 \times 0.4469 \approx 0.8759\]The margin of error is added and subtracted from the sample mean to create the confidence interval. This range helps decision-makers understand the potential for variation and indicates the reliability of the sample mean. It’s crucial in conveying how certain we are about our estimates.

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Most popular questions from this chapter

An experimenter fed different rations, \(A\) and \(B\), to two groups of 100 chicks each. Assume that all factors other than rations are the same for both groups. Of the chicks fed ration \(\mathrm{A}, 13\) died, and of the chicks fed ration \(\mathrm{B}, 6\) died. a. Construct a \(98 \%\) confidence interval for the true difference in mortality rates for the two rations. b. Can you conclude that there is a difference in the mortality rates for the two rations?

Independent ram of \(n_{1}=n_{2}=n\) observations are to be selected from each of two binomial populations 1 and \(2 .\) If you wish to estimate the difference in the two population proportions correct to within .05, with probability equal to .98, how large should \(n\) be? Assume that you have no prior information on the values of \(p_{1}\) and \(p_{2}\), but you want to make certain that you have an adequate number of observations in the samples.

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A random sample of 500 registrations are selected from a Department of Motor Vehicles database, and 68 are classified as sports utility vehicles. a. Use a \(95 \%\) confidence interval to estimate the proportion of sports utility vehicles in California. b. How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy?

Acid rain, caused by the reaction of certain air pollutants with rainwater, is a growing problem in the United States. Pure rain falling through clean air registers a pH value of 5.7 (pH is a measure of acidity: 0 is acid; 14 is alkaline). Suppose water samples from 40 rainfalls are analyzed for \(\mathrm{pH},\) and \(\bar{x}\) and \(s\) are equal to 3.7 and \(.5,\) respectively. Find a \(99 \%\) confidence interval for the mean \(\mathrm{pH}\) in rainfall and interpret the interval. What assumption must be made for the confidence interval to be valid?

Refer to Exercise \(8.7 .\) What effect does increasing the sample size have on the margin of error?

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