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Find the following probabilities for the standard normal random variable \(z:\) a. \(P(-1.431.34)\) e. \(P(z<-4.32)\)

Short Answer

Expert verified
In summary, for a given standard normal random variable Z, we have the following probabilities of different intervals: a. The probability that Z lies between -1.43 and 0.68 is 0.6753. b. The probability that Z lies between 0.58 and 1.74 is 0.2410. c. The probability that Z lies between -1.55 and -0.44 is 0.2689. d. The probability that Z is greater than 1.34 is 0.0901. e. The probability that Z is less than -4.32 is approximately 0.

Step by step solution

01

Understand and setup the problem

We are given the standard normal random variable \(z\), which has a mean (\(\mu\)) of 0 and a standard deviation (\(\sigma\)) of 1. We need to find the probabilities for different intervals or values of \(z\), using the Z-table or a calculator.
02

Find the probability for a given range using the Z-table or calculator

To find the probability for a given range, we'll use the Z-table or calculator to find the cumulative probability up to the given value, which corresponds to the area under the curve to the left of that value. For a range, we'll calculate the cumulative probability at each endpoint, and then subtract the lower endpoint probability from the higher endpoint probability. For example, to find the probability \(P(a
03

a. Find \(P(-1.43

To find this probability, we'll use the formula mentioned above: \(P(-1.43
04

b. Find \(P(.58

Using the formula: \(P(.58
05

c. Find \(P(-1.55

Using the formula: \(P(-1.55
06

d. Find \(P(z>1.34)\)

To find a probability for values greater than a given value, we'll find the cumulative probability at that value and subtract it from 1: \(P(z>1.34) = 1 - P(z<1.34)\) Using the Z-table or calculator: \(P(z<1.34) = 0.9099\) Subtracting this probability: \(P(z>1.34) = 1 - 0.9099 = 0.0901\)
07

e. Find \(P(z

Similarly, to find a probability for values smaller than a given value, we'll find the cumulative probability at that value: \(P(z<-4.32) = P(z<-4.32)\) Using the Z-table or calculator: \(P(z<-4.32) \approx 0\) As a result, we have the probabilities for each case: a. \(P(-1.431.34) = 0.0901\) e. \(P(z<-4.32) \approx 0\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-table
A Z-table is a valuable tool in statistics when dealing with standard normal distribution. It helps in finding the probability that a particular value falls below (or above) a certain point along the standard normal curve. This table essentially provides the cumulative probability associated with a standard normal curve at any given z-score.

The standard normal distribution is perfectly symmetrical about the mean of 0, with a standard deviation of 1. Probabilities are located by z-score, which quantifies how many standard deviations a point is from the mean. If you are searching for the probability that a particular z-score is achieved or not surpassed, you will look up the z-score in the Z-table, which will return the cumulative probability for that score.

When you analyze a Z-table, notice the rows represent the first two digits of the z-score and the columns represent the second decimal. For example, if you want the cumulative probability of a z-score of 1.34, you would find the row for 1.3 and the column under 0.04, yielding the combined cumulative probability. This intuitive indexing makes Z-tables a wonderful aid in probability calculation.
Probability Calculation
Probability calculation in statistics allows us to reason about uncertain events, specifically using a framework where probabilities are assigned to various outcomes. In a standard normal distribution, probability calculations involve determining how likely a data point falls within a certain range of the distribution.

Probability is calculated by analyzing the area under the curve on a graph of the distribution. To find the probability that a variable will fall between, greater than, or less than certain values on the standard normal curve, we either directly look at values from the Z-table or use a direct formula expression.

For example, for finding \( P(a c) \) by subtracting the cumulative probability \( P(z < c) \) from 1. Calculations like these are fundamental when interpreting statistical data grounded in the normal distribution.
Cumulative Probability
Cumulative probability refers to the total probability that a random variable falls within a certain range, starting from the smallest value of the distribution up to a specific point. In the context of the standard normal distribution, it is equivalent to the area under the curve to the left of a certain z-score.

Cumulative probability is a building block in understanding how probabilities stack up as more area under the curve is considered. By definition, if you have a point of interest on the distribution, the cumulative probability will provide the likelihood that any instance observed is less than or equal to that point.

In practical use, cumulative probability is obtained through the Z-table for a standard normal distribution. The cumulative probability serves as an indicator of how extreme a particular z-score is relative to the rest of the distribution. This allows for deeper analysis on any data point's percentile rank or its likelihood of occurrence, which is essential for making decisions based on statistical models.
Probability Intervals
Probability intervals help us understand the likelihood that a random variable falls within a certain range on the standard normal distribution. These intervals are defined by two z-scores along the distribution curve. For instance, when we need to find the probability for \( -1.43 < z < 0.68 \), we are dealing with a probability interval.

This probability is calculated using the cumulative probabilities of both endpoints. The probability that the random variable falls between these points is obtained by subtracting the cumulative probability at the lower endpoint from that at the higher endpoint. This subtraction gives the area between the two z-scores and thus the probability.

Utilizing probability intervals helps in assessing events in terms of quantitative likelihoods. It moves beyond single point probabilities, providing a broader picture of the likelihood of occurrences over a range. This concept is particularly valuable when assessing ranges of significance in hypothesis testing or when understanding outcomes within driven constraints.

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Most popular questions from this chapter

Human Heights Human heights are one of many biological random variables that can be modeled by the normal distribution. Assume that the heights of American men have a mean of 69.5 inches and a standard deviation of 3.5 inches. a. What proportion of all men will be taller than \(6^{\prime} 0^{\prime \prime} ?\) (HINT: Convert the measurements to inches.) b. What is the probability that a randomly selected man will be between \(5^{\prime} 8^{\prime \prime}\) and \(6^{\prime} 1^{\prime \prime}\) tall? c. President Barack Obama is 6'1". Is this an unusual height? d. Of the 43 presidents elected from 1789 through 2008,18 were \(6^{\prime} 0^{\prime \prime}\) or taller. \(^{1}\) Would you consider this to be unusual, given the proportion found in part a?

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Calculate the area under the standard normal curve to the left of these values: a. \(z=1.6\) b. \(z=1.83\) c. \(z=.90\) d. \(z=4.18\)

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