/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Braking Distances For a car trav... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Braking Distances For a car traveling 30 miles per hour (mph), the distance required to brake to a stop is normally distributed with a mean of 50 feet and a standard deviation of 8 feet. Suppose you are traveling \(30 \mathrm{mph}\) in a residential area and a car moves abruptly into your path at a distance of 60 feet. a. If you apply your brakes, what is the probability that you will brake to a stop within 40 feet or less? Within 50 feet or less? b. If the only way to avoid a collision is to brake to a stop, what is the probability that you will avoid the collision?

Short Answer

Expert verified
Answer: The probability that the car will stop within 40 feet or less is 0.2119, within 50 feet or less is 0.5, and within 60 feet or less to avoid a collision is 0.7881.

Step by step solution

01

Identify given information

The braking distance is normally distributed with a mean of \(\mu = 50\) feet and a standard deviation of \(\sigma = 8\) feet.
02

Calculate the z-score for 40 feet

The z-score formula is given by \(z = \frac{X - \mu}{\sigma}\). Here, \(X = 40\) feet. So, \(z = \frac{40 - 50}{8} = -1.25\).
03

Look up the probability in the z-table

The z-table gives the probability that a value is less than or equal to the given z-score. Look up the z-score of \(-1.25\) in the z-table. The probability is \(0.2119\).
04

Answer the question for 40 feet or less

The probability that the car will stop within 40 feet or less is \(0.2119\). #a. Calculate the probability of stopping within 50 feet or less#
05

Calculate the z-score for 50 feet

With \(X = 50\) feet, the z-score is \(z = \frac{50 - 50}{8} = 0\).
06

Look up the probability in the z-table

The z-score of 0 always corresponds to a probability of \(0.5\) in the z-table.
07

Answer the question for 50 feet or less

The probability that the car will stop within 50 feet or less is \(0.5\). #b. Calculate the probability of stopping within 60 feet or less to avoid collision#
08

Calculate the z-score for 60 feet

With \(X = 60\) feet, the z-score is \(z = \frac{60 - 50}{8} = 1.25\).
09

Look up the probability in the z-table

Look up the z-score of \(1.25\) in the z-table. The probability is \(0.7881\).
10

Answer the question for avoiding collision

The probability that the car will stop within 60 feet or less, avoiding a collision, is \(0.7881\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-score
The concept of a z-score is an essential part of understanding how a value relates to the mean in a set of data that follows a normal distribution. The z-score tells us how many standard deviations a specific value is from the mean of the dataset. In mathematical terms, the z-score is calculated using the formula: \[ z = \frac{X - \mu}{\sigma} \]where:
  • \(X\) is the value of interest,
  • \(\mu\) is the mean of the dataset,
  • \(\sigma\) is the standard deviation of the dataset.
For example, if a car needs to brake within 40 feet and the mean braking distance is 50 feet with a standard deviation of 8 feet, the calculation would be:\[ z = \frac{40 - 50}{8} = -1.25 \]A negative z-score implies that the value is below the mean.
probability
Probability provides a way to quantify the likelihood of an event. In the context of a normal distribution, probability helps determine the chance that a certain outcome falls within a specified range. After obtaining a z-score, we use it to find the probability of a random variable being less than or equal to that value. For instance, in our exercise, the probability of braking to a stop within 40 feet (a z-score of -1.25) is found to be approximately 21.19% or 0.2119. This probability is derived from the normal distribution table, known as the z-table. Likewise, probabilities help understand and plan for different outcomes, like assessing the risk of collision when braking distance varies.
z-table
The z-table is a crucial tool used to find the probability associated with a particular z-score in a standard normal distribution. The table provides the area under the curve to the left of a given z-score. When using a z-table:
  • Locate the z-score in the table by looking up its row and column.
  • The value found in the table represents the probability that a standard normal variable is less than or equal to that z-score.
For example, a z-score of -1.25 corresponds to a probability of 0.2119, indicating that approximately 21.19% of the data lies below this score. Similarly, a z-score of 1.25 relates to a probability of 0.7881, which is used to assess the likelihood of successfully stopping within 60 feet.
standard deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. In the context of normal distribution, it shows how much the individual data points deviate from the mean. A smaller standard deviation means that the data points tend to be closer to the mean, while a larger standard deviation indicates more spread out data. The formula for standard deviation is: \[ \sigma = \sqrt{\frac{\sum (X_i - \mu)^2}{N}} \]where:
  • \(X_i\) are the data points,
  • \(\mu\) is the mean,
  • \(N\) is the number of data points.
In our braking distance scenario, a standard deviation of 8 feet tells us that most braking distances will fall within 8 feet above or below the mean of 50 feet. Understanding standard deviation allows for prediction of how often outcomes will occur within certain ranges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The daily sales total (excepting Saturday) at a small restaurant has a probability distribution that is approximately normal, with a mean \(\mu\) equal to \(\$ 1230\) per day and a standard deviation \(\sigma\) equal to \(\$ 120\) a. What is the probability that the sales will exceed \(\$ 1400\) for a given day? b. The restaurant must have at least \(\$ 1000\) in sales per day to break even. What is the probability that on a given day the restaurant will not break even?

A normal random variable \(x\) has mean \(\mu=5\) and standard deviation \(\sigma=2\). Find the probabilities associated with the following intervals: a. \(1.27.5\) c. \(x \leq 0\)

How Can I Help? Are you helping to save the environment? A USA Today Snapshot found that about \(78 \%\) of Americans believe that recycling trash makes the biggest difference in protecting the environment. \(^{5}\) Suppose a random sample of \(n=50\) adults are polled and asked if they believed that recycling made the biggest difference in protecting our environment. Let us assume that the \(78 \%\) figure is, in fact, correct. What are the probabilities for the following events? a. Fewer than 30 individuals believe that recycling makes the biggest difference? b. More than 40 individuals believe that recycling makes the biggest difference? c. More than 10 individuals believe that recycling does not make the biggest difference?

Find the following probabilities for the standard normal random variable \(z:\) a. \(P(-1.431.34)\) e. \(P(z<-4.32)\)

Used Cars A used-car dealership has found that the length of time before a major repair is required on the cars it sells is normally distributed with a mean equal to 10 months and a standard deviation of 3 months. If the dealer wants only \(5 \%\) of the cars to fail before the end of the guarantee period, for how many months should the cars be guaranteed?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.