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Sweet Potato Whitefly Suppose that \(10 \%\) of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in this area are randomly selected, and 25 are found to be infested with whitefly. a. Assuming that the experiment satisfies the conditions of the binomial experiment, do the data indicate that the proportion of infested fields is greater than expected? Use the \(p\) -value approach, and test using a \(5 \%\) significance level. b. If the proportion of infested fields is found to be significantly greater than \(.10,\) why is this of practical significance to the agronomist? What practical conclusions might she draw from the results?

Short Answer

Expert verified
Answer: Yes, the proportion of infested fields is significantly higher than 10% at a 5% significance level.

Step by step solution

01

Determine if the conditions of a binomial experiment are met

For an experiment to be considered a binomial experiment, it must satisfy the following conditions: 1. There are a fixed number of trials (in this case, 100 fields). 2. The trials are independent (since the fields are randomly selected, it can be assumed that infestation in one field does not affect the infestation in another field). 3. There are only two possible outcomes for each trial (infested or not infested). 4. The probability of success (infestation) remains constant for each trial. Since these conditions are met, we can proceed with the hypothesis testing using the binomial distribution.
02

Formulate the null and alternative hypotheses

The null hypothesis \(H_0\) is that the proportion of infested fields is equal to the expected proportion, i.e., \(p = 0.10\). The alternative hypothesis \(H_1\) is that the proportion of infested fields is greater than the expected proportion, i.e., \(p > 0.10\).
03

Calculate the test statistic

Given that we have \(n=100\) fields and \(x=25\) infested fields, the sample proportion \(\hat{p} = \frac{x}{n} = 0.25\). Now, we will calculate the test statistic using the formula: \(z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}\) Where \(p_0 = 0.10\) is the expected proportion and \(n = 100\) is the sample size. Plugging in the numbers: \(z = \frac{(0.25 - 0.10)}{\sqrt{\frac{0.10(1-0.10)}{100}}} = 4.47\)
04

Calculate the \(p\) -value

The \(p\) -value is the probability of obtaining a test statistic at least as extreme as the one calculated, under the null hypothesis. As our alternative hypothesis is \( p > 0.10 \), we will find the probability of \(z>4.47\) from the standard normal (z) table or using statistical software. The \(p\) -value for this test statistic is approximately \(3.925\times 10^{-6}\).
05

Compare the \(p\) -value to the significance level

The given significance level is \(5\%\) (i.e., \(\alpha = 0.05\)). Since the calculated \(p\) -value is smaller than the significance level (\(3.925\times 10^{-6} < 0.05\)), we reject the null hypothesis.
06

Draw the conclusion

Rejecting the null hypothesis indicates that there is significant evidence to support the alternative hypothesis, i.e., the proportion of infested fields is greater than \(10\%\).
07

Practical Significance and Conclusions

If the proportion of infested fields is found to be significantly higher than \(10\%\), it indicates that the sweet potato whitefly problem might be more severe than previously thought. The agronomist may need to investigate further to find the reasons for this higher infestation rate and implement appropriate measures to control the whitefly population and mitigate the damaging effects on the crops. The agronomist may also need to revisit their estimation methods and monitoring practices to ensure they accurately estimate, predict, and address whitefly infestations in the future.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a fundamental concept in probability and statistics used to model experiments with specific characteristics. In the context of the sweet potato whitefly infestation problem, this distribution helps us understand the likelihood of a certain number of fields being infested given a certain probability. The crucial conditions are:
  • A fixed number of trials – here, examining 100 fields.
  • Each trial is independent – the infestation of one field does not affect others because fields are randomly selected.
  • Binary outcomes – a field is either infested or not.
  • A constant probability of success – each field can have the same chance of being infested, which is expected to be \(0.10\).
When these conditions are met, we can apply the binomial model to perform hypothesis testing and make informed decisions.
Significance Level
The significance level, commonly denoted as \(\alpha\), is a critical element of hypothesis testing. It represents the threshold for determining whether the observed data is sufficiently rare under the null hypothesis. For the whitefly problem, a significance level of \(5\%\) (or \(\alpha = 0.05\)) was chosen.

This level tells us the probability of rejecting the null hypothesis when it is actually true. It acts as a boundary for deciding whether our evidence is strong enough to refute the null hypothesis.

A p-value smaller than \(\alpha\) gives us the confidence needed to reject the null hypothesis, as it suggests that the occurrence we observed (25 infested fields) is unlikely by random chance, given the hypothesis of only \(10\%\) infestation.
Null Hypothesis
The null hypothesis, denoted as \(H_0\), serves as the default or standard claim which we test against. In statistical tests, it often posits no effect or difference.

For our exercise, the null hypothesis claims that the true proportion of whitefly-infested fields is equal to the expected proportion, so \(p = 0.10\). This means we assume, unless we gather enough evidence, that only \(10\%\) of fields are infested.

In hypothesis testing, we initially assume the null hypothesis is true. Only if we gather substantial evidence (signified by a p-value less than the chosen significance level), will the null hypothesis be rejected. This critical step ensures that changes or variations observed are not simply due to random chance.
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis, represented as \(H_1\), signifies what we seek to provide evidence for. It offers an alternative explanation or effect that contradicts the null hypothesis.

Here, the alternative hypothesis states that the actual proportion of infested fields is greater than the expected \(10\%\) ( i.e., \(p > 0.10\)). This suggests that the infestation might indeed be more widespread than initially assumed.

In hypothesis testing, the target is to collect enough evidence to support the alternative hypothesis. If our calculated p-value falls below the significance level, we can confidently reject \(H_0\) in favor of \(H_1\), asserting that there is indeed a higher-than-expected infestation rate. The alternative hypothesis thus drives the discovery of new insights or deviations from the norm.

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Most popular questions from this chapter

a. Define \(\alpha\) and \(\beta\) for a statistical test of hypothesis. b. For a fixed sample size \(n\), if the value of \(\alpha\) is decreased, what is the effect on \(\beta\) ? c. In order to decrease both \(\alpha\) and \(\beta\) for a particular alternative value of \(\mu,\) how must the sample size change?

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