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a. Define \(\alpha\) and \(\beta\) for a statistical test of hypothesis. b. For a fixed sample size \(n\), if the value of \(\alpha\) is decreased, what is the effect on \(\beta\) ? c. In order to decrease both \(\alpha\) and \(\beta\) for a particular alternative value of \(\mu,\) how must the sample size change?

Short Answer

Expert verified
Answer: In a statistical hypothesis test, \(\alpha\) represents the probability of rejecting a true null hypothesis (Type I error), while \(\beta\) represents the probability of not rejecting a false null hypothesis (Type II error). If the sample size is fixed and \(\alpha\) is decreased, \(\beta\) will increase. To decrease both \(\alpha\) and \(\beta\) simultaneously, the sample size must be increased.

Step by step solution

01

Definition of \(\alpha\) and \(\beta\)

The \(\alpha\) level (also known as the significance level) is the probability of rejecting a true null hypothesis, which means making a Type I error (false positive). In a hypothesis testing situation, it is often written as \(P(\text{Type I error}) = P(\text{Reject } H_0 \text{ when } H_0 \text{ is true}) = \alpha\). The \(\beta\) is the probability of not rejecting a false null hypothesis, which means making a Type II error (false negative). In a hypothesis testing situation, it is often written as \(P(\text{Type II error}) = P(\text{Fail to reject } H_0 \text{ when } H_0 \text{ is false}) = \beta\).
02

Effect of Decreasing \(\alpha\) on \(\beta\) with Fixed Sample Size

When decreasing the value of \(\alpha\) while keeping the sample size \(n\) fixed, the rejection region becomes smaller, making it harder to reject the null hypothesis. As a result, the probability of rejecting the null hypothesis decreases, which means that the probability of making a Type II error (failing to reject a false null hypothesis) increases. Therefore, for a fixed sample size \(n\), if the value of \(\alpha\) is decreased, \(\beta\) will increase.
03

Effect of Sample Size on \(\alpha\) and \(\beta\)

In order to decrease both \(\alpha\) and \(\beta\) simultaneously for a particular alternative value of \(\mu\), the sample size must be increased. A larger sample size provides more information and increases the power of the test, which is the probability of correctly rejecting a false null hypothesis. Increasing the sample size will allow the region of rejection to become smaller (thus reducing the probability of Type I errors) while also increasing the ability to detect true differences (thus reducing the probability of Type II errors).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I and II Errors
When conducting hypothesis testing in statistics, it is crucial to understand the potential errors that can occur. Type I error, also known as a false positive, happens when the null hypothesis is true, but the test erroneously rejects it. This is signified by the symbol \(\alpha\), which represents the level of significance that we are willing to accept for this type of error. An example of a Type I error would be if a clean athlete tests positive for a banned substance.

On the other hand, a Type II error, or false negative, occurs when the null hypothesis is false but the test fails to reject it. The probability of committing a Type II error is denoted by \(\beta\). For instance, a Type II error is made when a sick patient is incorrectly diagnosed as healthy.

Understanding the balance between these two errors is fundamental. If you set a low \(\alpha\) to avoid Type I errors, you might increase the chances of making Type II errors, since it becomes harder to reject the null hypothesis.
Statistical Significance
The term statistical significance is a measure of whether the results of an experiment can be considered as not likely due to chance. It is closely tied to the \(\alpha\) level, which is the threshold for determining if our observed outcomes are statistically significant. If we obtain a p-value (calculated probability) that is less than our predetermined \(\alpha\), we declare that our results are statistically significant, and we reject the null hypothesis.

For instance, if \(\alpha = 0.05\), we would require less than a 5% chance that the observed data could occur if the null hypothesis were true. If our p-value is 0.03, it's statistically significant, and we reject the null hypothesis, claiming our results are unlikely to be due to random chance alone. The choice of \(\alpha\) influences the credibility of our test and is often set at 0.05, 0.01, or 0.10 based on the field of study and the consequences of errors.
Sample Size
The sample size, denoted as \(n\), plays a pivotal role in hypothesis testing. It refers to the number of observations or data points collected in a study. A larger sample size tends to provide more reliable results because it is more representational of the population, reducing the margin of error and smoothing out anomalies.

In the context of errors, increasing the sample size can improve the accuracy by reducing the probabilities of both Type I and Type II errors. However, it is a trade-off; with a limited budget or time constraints, a larger sample size may not always be feasible. To balance this, researchers must carefully choose an appropriate sample size that aligns with their study's objectives and constraints. This decision is often guided by a power analysis.
Power of the Test
The power of the test is a concept that refers to the test's ability to correctly reject a false null hypothesis. It is the probability that the test will detect a true effect when it is there, written as \(1 - \beta\). The higher the power, the lower the chance of making a Type II error. When designing a study, researchers aim for high power, often 80% or more, which means at most a 20% chance of failing to detect a true effect.

To increase the power, you can increase the sample size, enhance the effect size, or use more sensitive measurements. Each of these has practical implications, such as cost or feasibility. Researchers must thus optimize all aspects of the design to make the most of the resources they have while minimizing the chances of errors and ensuring that the study can yield meaningful results.

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Most popular questions from this chapter

Independent random samples of \(n_{1}=140\) and \(n_{2}=140\) observations were randomly selected from binomial populations 1 and \(2,\) respectively. Sample 1 had 74 successes, and sample 2 had 81 successes. a. Suppose you have no preconceived idea as to which parameter, \(p_{1}\) or \(p_{2}\), is the larger, but you want to detect only a difference between the two parameters if one exists. What should you choose as the alternative hypothesis for a statistical test? The null hypothesis? b. Calculate the standard error of the difference in the two sample proportions, \(\left(\hat{p}_{1}-\hat{p}_{2}\right) .\) Make sure to use the pooled estimate for the common value of \(p\). c. Calculate the test statistic that you would use for the test in part a. Based on your knowledge of the standard normal distribution, is this a likely or unlikely observation, assuming that \(H_{0}\) is true and the two population proportions are the same? d. \(p\) -value approach: Find the \(p\) -value for the test. Test for a significant difference in the population proportions at the \(1 \%\) significance level. e. Critical value approach: Find the rejection region when \(\alpha=.01 .\) Do the data provide sufficient evidence to indicate a difference in the population proportions?

Childhood Obesity According to PARADE magazine's "What America Eats" survey involving \(n=1015\) adults, almost half of parents say their children's weight is fine. \({ }^{8}\) Only \(9 \%\) of parents describe their children as overweight. However, the American Obesity Association says the number of overweight children and teens is at least \(15 \%\). Suppose that the number of parents in the sample is \(n=750\) and the number of parents who describe their children as overweight is \(x=68\) a. How would you proceed to test the hypothesis that the proportion of parents who describe their children as overweight is less than the actual proportion reported by the American Obesity Association? b. What conclusion are you able to draw from these data at the \(\alpha=.05\) level of significance? c. What is the \(p\) -value associated with this test?

Find the \(p\) -value for the following large-sample \(z\) tests: a. A right-tailed test with observed \(z=1.15\) b. A two-tailed test with observed \(z=-2.78\) c. A left-tailed test with observed \(z=-1.81\)

Adolescents and Social Stress In a study to compare ethnic differences in adolescents' social stress, researchers recruited subjects from three middle schools in Houston, Texas. \({ }^{21}\) Social stress among four ethnic groups was measured using the Social Attitudinal Familial and Environment Scale for Children (SAFE-C). In addition, demographic information abou the 316 students was collected using self-administered questionnaires. A tabulation of student responses to a question regarding their socioeconomic status (SES) compared with other families in which the students chose one of five responses (much worse off, somewhat worse off, about the same, better off, or much better off) resulted in the tabulation that follows. a. Do these data support the hypothesis that the proportion of adolescent African Americans who state that their SES is "about the same" exceeds that for adolescent Hispanic Americans? b. Find the \(p\) -value for the test. c. If you plan to test using \(\alpha=.05,\) what is your conclusion?

Cure for the Common Cold? An experiment was planned to compare the mean time (in days) required to recover from a common cold for persons given a daily dose of 4 milligrams (mg) of vitamin C versus those who were not given a vitamin supplement. Suppose that 35 adults were randomly selected for each treatment category and that the mean recovery times and standard deviations for the two groups were as follows: $$\begin{array}{lcc} & \begin{array}{l}\text { No Vitamin } \\\\\text { Supplement }\end{array} & \begin{array}{l}4 \mathrm{mg} \\\\\text { Vitamin }\end{array} \\\\\hline \text { Sample Size } & 35 & 35 \\\\\text { Sample Mean } & 6.9 & 5.8 \\\\\text { Sample Standard Deviation } & 2.9 & 1.2\end{array}$$

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