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Many companies are testing prospective employees for drug use, with the intent of improving efficiency and reducing absenteeism, accidents, and theft. Opponents claim that this procedure is creating a class of unhirables and that some persons may be placed in this class because the tests themselves are not \(100 \%\) reliable. Suppose a company uses a test that is \(98 \%\) accurate \(-\) that is, it correctly identifies a person as a drug user or nonuser with probability \(98-\) and to reduce the chance of error, each job applicant is required to take two tests. If the outcomes of the two tests on the same person are independent events, what are the probabilities of these events? a. A nonuser fails both tests. b. A drug user is detected (i.e., he or she fails at least one test). c. A drug user passes both tests.

Short Answer

Expert verified
Answer: (a) The probability that a nonuser fails both tests is 0.0004 or 0.04%. (b) The probability that a drug user is detected is 0.02 or 2%. (c) The probability that a drug user passes both tests is 0.0004 or 0.04%.

Step by step solution

01

a. A nonuser fails both tests.

1. Determine the probability that a nonuser fails Test 1: Since the test is 98% accurate, there is a 2% chance that a nonuser will fail, which is equal to \(\frac{2}{100}\). 2. Determine the probability that, given a nonuser fails Test 1, the same nonuser fails Test 2 as well: Since tests are independent events, the probability remains 2%. 3. Multiply the probabilities together to find the probability that a nonuser fails both tests: \(\frac{2}{100} \times \frac{2}{100} = \frac{4}{10000} = 0.0004\). The probability that a nonuser fails both tests is 0.0004, or 0.04%.
02

b. A drug user is detected (i.e., he or she fails at least one test).

1. Determine the probability that a drug user passes Test 1: Since the test is 98% accurate, there is a 2% chance that a drug user will pass, which is equal to \(\frac{2}{100}\). 2. Determine the probability that, given a drug user passes Test 1, the same drug user fails Test 2: This time, there is a 98% chance that the drug user will fail, which is equal to \(\frac{98}{100}\). 3. Multiply the probabilities together to find the probability that a drug user fails at least one test: \(\frac{2}{100} \times \frac{98}{100} = \frac{196}{10000} = 0.0196\). 4. We also need to consider the probability of the drug user failing both tests, which we have already calculated in part a (that chance is 0.0004). 5. Add both probabilities together: \(0.0196 + 0.0004 = 0.02\). The probability that a drug user is detected (i.e., he or she fails at least one test) is 0.02, or 2%.
03

c. A drug user passes both tests.

1. Determine the probability that a drug user passes Test 1: Recall that the test is 98% accurate, so there is a 2% chance that a drug user will pass, which is equal to \(\frac{2}{100}\). 2. Determine the probability that, given a drug user passes Test 1, the same drug user passes Test 2 as well: Since tests are independent events, the probability remains 2%. 3. Multiply the probabilities together to find the probability that a drug user passes both tests: \(\frac{2}{100} \times \frac{2}{100} = \frac{4}{10000} = 0.0004\). The probability that a drug user passes both tests is 0.0004, or 0.04%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics concerned with the analysis of random phenomena. The principal object of probability theory is the probability measure, a function that assigns a number to each event in a sample space, indicating the likelihood of that event occurring.

When we talk about an event's probability, we refer to a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty. In the case of the drug test problem, the probability measure told us that the test was accurate 98% of the time, or with a probability of 0.98.

It's important to note that the accuracy percentage here translates directly to the probability of an outcome. For example, a 2% inaccuracy means there is a 0.02 probability that the test will incorrectly label a user or nonuser. Understanding probability measures, as demonstrated in this drug test scenario, is crucial for various real-world applications, from medical diagnosis to quality control in manufacturing.
Statistical Accuracy
Statistical accuracy pertains to how close a measurement or a test outcome comes to the true value. When we say a drug test is 98% accurate, we imply that it correctly identifies a person as a drug user or a nonuser with a high level of accuracy. However, 100% accuracy in the real world is nearly impossible; there's always a margin of error to consider.

In the provided exercise, the 2% inaccuracy rate must be accounted for not once but twice, as each applicant takes two tests. This compounding of errors is crucial when interpreting statistical data. Errors can compound multiplicatively, as in the example where we calculated the probability of a nonuser failing both tests independently (multiplying the 2% chance each time). This leads us to recognize the importance of conducting multiple tests and the significance of independent verification in reducing the risk of false results.
Independent Events
In probability theory, independent events are scenarios where the occurrence of one event does not influence the probability of another. This concept is key in calculating the combined probability of separate events, like in our drug test problem.

Since the tests are assumed to be independent, the outcome of the first test does not at all affect the outcome of the second test. As shown in the solution, the probability of a nonuser failing both tests is calculated by multiplying the probability of failing the first test (2%) with the probability of failing the second (2%), resulting in a very small chance of a nonuser failing both tests (0.04%).

This assumption of independence is powerful because it simplifies calculations and is a common assumption when events are physically separated or unrelated. However, one must be careful when applying the assumption of independence, as not all events are truly independent in real life, and mistakenly assuming they are can lead to incorrect results.

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Most popular questions from this chapter

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