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The American Journal of Sports Medicine published a study of 810 women collegiate rugby players who have a history of knee injuries. For these athletes, the two common knee injuries investigated were medial cruciate ligament (MCL) sprains and anterior cruciate ligament (ACL) tears. \(^{8}\) For backfield players, it was found that \(39 \%\) had MCL sprains and \(61 \%\) had ACL tears. For forwards, it was found that \(33 \%\) had MCL sprains and \(67 \%\) had ACL tears. Since a rugby team consists of eight forwards and seven backs, you can assume that \(47 \%\) of the players with knee injuries are backs and \(53 \%\) are forwards. a. Find the unconditional probability that a rugby player selected at random from this group of players has experienced an MCL sprain. b. Given that you have selected a player who has an MCL sprain, what is the probability that the player is a forward? c. Given that you have selected a player who has an ACL tear, what is the probability that the player is a back?

Short Answer

Expert verified
Based on the given probabilities of knee injuries in rugby players, we found: a. The unconditional probability of a player experiencing an MCL sprain is approximately 0.3582 (35.82%). b. The probability that a player with an MCL sprain is a forward is approximately 0.4873 (48.73%). c. The probability that a player with an ACL tear is a back is approximately 0.4469 (44.69%).

Step by step solution

01

Write given probabilities in the form of conditional probabilities

We'll begin by writing the given probabilities in terms of conditional probabilities 1. P(MCL | Back) = 0.39 (Probability of an MCL sprain given the player is from the backfield) 2. P(ACL | Back) = 0.61 (Probability of an ACL tear given the player is from the backfield) 3. P(MCL | Forward) = 0.33 (Probability of an MCL sprain given the player is a forward) 4. P(ACL | Forward) = 0.67 (Probability of an ACL tear given the player is a forward) 5. P(Back) = 0.47 (Probability that the player is from the backfield) 6. P(Forward) = 0.53 (Probability that the player is a forward)
02

Find unconditional probability of a player experiencing an MCL sprain

We can find the unconditional probability of a rugby player experiencing an MCL sprain using the Law of Total Probability: P(MCL) = P(MCL | Back) * P(Back) + P(MCL | Forward) * P(Forward) P(MCL) = (0.39 * 0.47) + (0.33 * 0.53) P(MCL) = 0.1833 + 0.1749 P(MCL) ≈ 0.3582 So, the unconditional probability that a rugby player selected at random from this group of players has experienced an MCL sprain is approximately 0.3582 (35.82%).
03

Find the probability that a player with an MCL sprain is a forward

We will use Bayes' theorem to find the probability of a player being a forward given they have an MCL sprain: P(Forward | MCL) = (P(MCL | Forward) * P(Forward)) / P(MCL) P(Forward | MCL) = (0.33 * 0.53) / 0.3582 P(Forward | MCL) ≈ 0.4873 So, given that a player has an MCL sprain, the probability that the player is a forward is approximately 0.4873 (48.73%).
04

Find the probability that a player with an ACL tear is a back

We will again use Bayes' theorem to find the probability of a player being from the backfield given they have an ACL tear: P(Back | ACL) = (P(ACL | Back) * P(Back)) / P(ACL) First, we need to find the unconditional probability of an ACL tear, P(ACL), using the Law of Total Probability: P(ACL) = P(ACL | Back) * P(Back) + P(ACL | Forward) * P(Forward) P(ACL) = (0.61 * 0.47) + (0.67 * 0.53) P(ACL) = 0.2867 + 0.3551 P(ACL) ≈ 0.6418 Now, we can find P(Back | ACL): P(Back | ACL) = (P(ACL | Back) * P(Back)) / P(ACL) P(Back | ACL) = (0.61 * 0.47) / 0.6418 P(Back | ACL) ≈ 0.4469 So, given that a player has an ACL tear, the probability that the player is from the backfield is approximately 0.4469 (44.69%).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Understanding conditional probability is essential when dealing with dependent events in statistics. It is defined as the probability of an event occurring, given that another event has already occurred. This concept is crucial in real-world scenarios where the outcome of one event influences the likelihood of another. For example, let's consider a classroom with both male and female students. If we want to calculate the probability of choosing a student who has glasses given that the student is female, we're looking for a conditional probability.

To express this mathematically, the conditional probability of event A given event B has occurred is written as P(A|B) and is calculated by dividing the probability of both events happening together, P(A and B), by the probability of B. If we were discussing knee injuries among rugby players, the probability of selecting a player with an MCL sprain given they are a forward would be P(MCL|Forward).

To calculate this in the context of our rugby scenario from the textbook solution, we used the given data to determine that the probability of having an MCL sprain given the player is a forward is 33%, or 0.33.
Bayes' Theorem
Bayes' Theorem is a powerful formula used to update prior knowledge of conditions using new information. It can flip conditional probabilities, allowing us to find the probability of the initial event given the outcome. In essence, if we want to reverse a conditional probability from P(A|B) to P(B|A), Bayes' theorem provides the means to do so.

The theorem can be represented as:\[\begin{equation} P(B|A) = \frac{P(A|B)P(B)}{P(A)},\end{equation}\]where P(A) is the total probability of A occurring, irrespective of B. This is where the Law of Total Probability comes into play, as it's essential to find P(A) to use Bayes' theorem. In our rugby player example, by applying the Law of Total Probability to the individual probabilities of having an MCL sprain for backs and forwards, we established P(MCL) as approximately 35.82%. With this, using the Bayes' formula, we calculated that the probability of a rugby player being a forward given that they've experienced a MCL sprain is about 48.73%.
Law of Total Probability
The Law of Total Probability ensures we consider all possible outcomes of an event to determine its overall likelihood. It's especially handy when we can break down a broader event into distinct, non-overlapping scenarios. Mathematically, it is expressed as:\[\begin{equation} P(A) = \sum( P(A|B_i)P(B_i))\end{equation}\]where B_i are all the possible conditions that complete a full set of alternatives for A occurring. To find the unconditional probability of an event, you sum up the probabilities of the event happening under each condition multiplied by the probability of the condition itself.

When we applied this law to calculate the unconditional probability of a rugby player having an MCL sprain, we summed up the probabilities of a player having an MCL sprain if they were a back and if they were a forward, weighted by the proportion of backs and forwards in the team, respectively. This calculation gave us the overall probability of a rugby player having an MCL sprain, irrespective of their position on the team.

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