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91Ó°ÊÓ

In the following exercise, using factorial notation, write the first five terms of the sequence whose general term is given.

an=n+1!n2

Short Answer

Expert verified

The first five terms of the sequence whose general term isan=n+1!n2are2,32,83,152,1445.

Step by step solution

01

Step 1. Given information

Thegeneraltermsforthesequenceisgivenasan=n+1!n2Wehavetofindthefirstfivetermsforthesequence.

02

Step 2. Calculating the terms

n:12345an:a1=1+1!12=2!1=2a2=2+1!22=3!4=3×2×14=32a3=3+1!32=4!9=4×3×2×19=83a4=4+1!42=5!16=5×4×3×2×14=152a5=5+1!52=6!25=6×5×4×3×2×14=1445

03

Step 3. Conclusion

From the above table, we can observe that the first five terms of sequence will be2,32,83,152,1445.

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