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91Ó°ÊÓ

In the following exercise, using factorial notation, write the first five terms of the sequence whose general term is given.

an=n2n!

Short Answer

Expert verified

The first five terms of the sequence whose general term isan=n2n!are1,2,32,23,524.

Step by step solution

01

Step 1. Given information

Thegeneraltermsforthesequenceisgivenasan=n2n!Wehavetofindthefirstfivetermsforthesequence.

02

Step 2. Calculating the terms

Now,Weknow,⇒n!=nn−1n−2n−3...

localid="1645632389067" n:12345an:a1=121!=11=1a2=222!=42×1=2a3=323!=93×2 ×1=32a4=424!=164×3×2×1=23a5=525!=255×4×3×2×1=524

03

Step 3. Conclusion

From the above table, we can observe that the first five terms of sequence will be 1,2,32,23,524.

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