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91Ó°ÊÓ

In the following exercise, using factorial notation, write the first five terms of the sequence whose general term is given.

an=n+1!2n

Short Answer

Expert verified

The first five terms of the sequence whose general term is an=n+1!2nare1,32,4,15,72.

Step by step solution

01

Step 1. Given information

Thegeneraltermsforthesequenceisgivenasan=n+1!2nWehavetofindthefirstfivetermsforthesequence.

02

Step 2. Calculating the terms

Now,Weknow,⇒n!=nn−1n−2n−3...

localid="1645713588188" n:12345an:a1=1+1!2⋅1=2!2=1a2=2+1!2⋅2=3!4=3×2×14=32a3=3+1!2⋅3=4!6=4×3×2×16=4a4=4+1!2⋅4=5!8=5×4×3×2×18=15a5=5+1!2⋅5=6!10=6×5×4×3×2×110=72

03

Step 3. Conclusion

From the above table, we can observe that the first five terms of sequence will be1,32,4,15,72.

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