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For functionsf(x)=2x2−4x+3and g(x)=x2−2x−6 find:(a)(f+g)(x)(b)(f+g)(3)(c)(f−g)(x)(d)(f−g)(−2)

Short Answer

Expert verified

The value is

(a)(f+g)(x)=3x2−6x−3(b)(f+g)(3)=6(c)(f−g)(x)=x2−2x+9(d)(f−g)(−2)=17

Step by step solution

01

Step 1. Given information

Thegivenfunctionsaref(x)=2x2−4x+3g(x)=x2−2x−6

We have to find

(a)(f+g)(x)(b)(f+g)(3)(c)(f−g)(x)(d)(f−g)(−2)

02

Step 2. Solve for part (a)

Weknow(f+g)(x)=fx+gxSubstitutethefunctionsfxandgx⇒(f+g)(x)=2x2−4x+3+x2−2x−6=2x2−4x+3+x2−2x−6Rewritewithoutparentheses=2x2+x2−4x−2x+3−6Putliketermstogether=3x2−6x−3

03

Step 3. Solve for part (b)

Wehave(f+g)(x)=3x2−6x−3⇒(f+g)(3)=332−63−3Substitutex=3=39−18−3=27−18−3=6

04

Step 4. Solve for part (c)

Weknow(f−g)(x)=fx−gxSubstitutethefunctionsfxandgx⇒(f−g)(x)=2x2−4x+3−x2−2x−6=2x2−4x+3−x2+2x+6Rewritewithoutparentheses=2x2−x2−4x+2x+3+6Putliketermstogether=x2−2x+9

05

Step 5. Solve for part (d)

Wehave(f−g)(x)=x2−2x+9⇒(f−g)(−2)=−22−2−2+9Substitutex=−2=4+4+9=17

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