/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 259 In the following exercises , sim... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q. 259 (page 538)

In the following exercises , simplify the expression(j2鈭�8j鈭�27)鈭�(j2+2j鈭�12).

Short Answer

Expert verified

The simplified expression is -10j-15 .

Step by step solution

01

Step 1. Given Information .

The given expression is j2鈥�鈭�鈥�8j鈥�鈭�鈥�27鈥�鈭�j2鈥�+鈥�2j鈥�鈭�鈥�12 .

02

Step 2. Simplify  the  given expression.

Simplify the expression j2鈥�鈭�鈥�8j鈥�鈭�鈥�27鈥�鈭�j2鈥�+鈥�2j鈥�鈭�鈥�12

j2鈥�鈭�鈥�8j鈥�鈭�鈥�27鈥�鈭�j2鈥�+鈥�2j鈥�鈭�鈥�12=j2-8j-27-j2-2j+12j2-8j-27-j2-2j+12=j2-j2-8j-2j-27+12j2-j2-8j-2j-27+12=-10j-15

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Simplifyk-2k8k32

Simplify2pq435p6q2

Find the product of the below expression.

t-92

In the following exercises, multiply the binomials. Use any method.

2t-910t+1

Find the product of the below expression.

m+n2
See all solutions

Recommended explanations on Math Textbooks

Mechanics Maths

Read Explanation

Discrete Mathematics

Read Explanation

Statistics

Read Explanation

Probability and Statistics

Read Explanation

Logic and Functions

Read Explanation

Geometry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.