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91Ó°ÊÓ

Forfunctionsf(x)=5x2−4x−1andg(x)=x2+3x+8,find(a)(f+g)(x)(b)(f+g)(3)(c)(f−g)(x)(d)(f−g)(−2).

Short Answer

Expert verified

The value is

(a)(f+g)(x)=6x2−x+7(b)(f+g)(3)=58(c)(f−g)(x)=4x2−7x−9(d)(f−g)(−2)=21

Step by step solution

01

Step 1. Given information 

Thegivenfunctionsaref(x)=5x2−4x−1g(x)=x2+3x+8(a)(f+g)(x)(b)(f+g)(3)(c)(f−g)(x)(d)(f−g)(−2)

02

Step 2. Solve for part (a) 

Weknow(f+g)(x)=fx+gxSubstitutethefunctionsfxandgx⇒(f+g)(x)=5x2−4x−1+x2+3x+8=5x2−4x−1+x2+3x+8Rewritewithoutparentheses=5x2+x2−4x+3x−1+8Putliketermstogether=6x2−x+7

03

Step 3. Solve for part (b) 

Wehave(f+g)(x)=6x2−x+7⇒(f+g)(3)=632−3+7Substitutex=3=69−3+7=54−3+7=58

04

Step 4. Solve for part (c) 

Weknow(f−g)(x)=fx−gxSubstitutethefunctionsfxandgx⇒(f−g)(x)=5x2−4x−1−x2+3x+8=5x2−4x−1−x2−3x−8Rewritewithoutparentheses=5x2−x2−4x−3x−1−8Putliketermstogether=4x2−7x−9

05

Step 4. Solve for part (d) 

Wehave(f−g)(x)=4x2−7x−9⇒(f−g)(−2)=4x2−7x−9Substitutex=2=422−7−2−9=44+14−9=16+14−9=21

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