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An ordinary unbiased 6 -sided die is rolled three times. Find the probability of rolling a) three twos b) at least one two c) exactly one two.

Short Answer

Expert verified
a) \(\frac{1}{216}\); b) \(\frac{91}{216}\); c) \(\frac{75}{216}\).

Step by step solution

01

Calculate the probability of rolling a two

Since the die is unbiased, the probability of rolling a two on one roll is \(\frac{1}{6}\).
02

Calculate the probability of not rolling a two

The probability of not rolling a two (rolling any other number) on one roll is \(\frac{5}{6}\).
03

Find the probability of rolling three twos

To find the probability of rolling three twos, we use the probability of rolling a two for each roll: \(\left(\frac{1}{6}\right)^3 = \frac{1}{216}\).
04

Calculate the probability of at least one two

First, find the probability of not rolling a two in all three rolls: \(\left(\frac{5}{6}\right)^3 = \frac{125}{216}\). Then, subtract this from 1 to find the probability of rolling at least one two: \[1 - \frac{125}{216} = \frac{91}{216}.\]
05

Find the probability of exactly one two

To find the probability of rolling exactly one two in three rolls, consider selecting one roll for the two, and the other two rolls not being a two. There are 3 ways to choose which roll gets the two.The probability is:\[3 \times \left(\frac{1}{6}\right) \times \left(\frac{5}{6}\right)^2 = \frac{75}{216}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rolling Dice
Rolling dice is a classic example often used to illustrate basic probability concepts. When you roll a six-sided die, there are 6 possible outcomes—each side of the die is numbered from 1 to 6. A die is typically used for games of chance, and each outcome is equally likely, provided the die is unbiased.

- **Outcome:** Each roll of a die results in one of six possible outcomes.- **Fairness:** An unbiased die means each number has the same chance of appearing.- **Single Roll Probability:** For any given number, like rolling a "two," the probability is \( \frac{1}{6} \).

The concept of probability when rolling dice can become more complex when the die is rolled multiple times. Each roll is independent, meaning the result of one roll does not affect another. This independence is a key aspect of understanding probability in scenarios involving multiple dice rolls.
Binomial Probability
Binomial probability is a statistical measure that helps us find probabilities in experiments where there are two outcomes and multiple independent trials. In the context of rolling a die thrice to get a particular number, like a "two," we apply binomial probability.

- **Trials:** Each roll of the die counts as one trial in a sequence.- **Successes:** Getting the desired outcome, such as rolling a "two."- **Failures:** Not getting the desired outcome, such as rolling any other number.

Binomial probability helps in calculating the likelihood of a certain number of "successes" in repeated trials. For example, if you want to roll exactly one "two," the probability involves both successes and failures across the rolls. Using the formula: \[ P(X = k) = \binom{n}{k} \times p^k \times (1-p)^{n-k} \] where \(n\) is the number of trials, \(k\) is the number of successes you’re trying to achieve, \(p\) is the probability of success on a single trial. With this formula, calculating the probability of rolling exactly three twos or at least one two becomes systematic and manageable.
Combinatorics
Combinatorics is a branch of mathematics crucial in probability theory, especially when determining different combinations or setups of outcomes. When rolling dice, combinatorics helps in calculating the number of ways an event can happen.

- **Combinations:** The number of ways to choose items from a group, which becomes useful in calculating probabilities when order doesn't matter.- **Applications:** In our dice scenario, think about how many ways we can roll exactly one two in three rolls.- **Formula Usage:** The combination formula \( \binom{n}{k} \) is used where \(n\) is the total number of trials (dice rolls) and \(k\) is the number you'd like as successes.

Let's consider, when you want to roll exactly one "two" in three rolls, there are three possible setups where you get a two on the first, second, or third roll. Using combinatorics, we systematically account for each possible scenario by multiplying the number of ways (which is 3 in this case) by the probability for each successful configuration. This effectively illustrates how combinatorics simplify the process of calculating probabilities for multi-step events in dice rolling scenarios.

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