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Discuss the similarities and differences between the standard normal distribution and the \(t\) -distribution.

Short Answer

Expert verified
Both distributions are symmetric and bell-shaped. The t-distribution has heavier tails and varies with sample size. The standard normal is fixed with mean 0 and SD 1.

Step by step solution

01

Define the Standard Normal Distribution

The standard normal distribution is a special case of the normal distribution with a mean of 0 and a standard deviation of 1. It follows a bell-shaped curve and is symmetric around the mean.
02

Define the t-Distribution

The t-distribution, also known as Student's t-distribution, is similar to the normal distribution but has heavier tails. It is used in statistics, particularly in hypothesis testing and confidence intervals, when the sample size is small and the population standard deviation is unknown.
03

Similarities

Both distributions are symmetric and bell-shaped. As the sample size increases, the t-distribution approaches the standard normal distribution. Both are centered around zero.
04

Differences

The main difference is that the t-distribution has heavier tails compared to the standard normal distribution, which means it has a higher probability for extreme values. The shape of the t-distribution depends on the degrees of freedom, which is related to the sample size; fewer degrees of freedom result in heavier tails. The standard normal distribution does not change shape with sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

standard normal distribution
The standard normal distribution is a type of normal distribution, but with special characteristics. It has a mean (\textbackslash(mu\textbackslash)) of 0 and a standard deviation (\textbackslash(sigma\textbackslash)) of 1. This makes the data points symmetrically distributed around the mean. The shape of the distribution is a symmetric bell curve.

The formula for the standard normal distribution is:

\[ z = \frac{(X - \mu)}{\sigma} \]

Where:
  • \textbackslash(X\textbackslash) is the value from the dataset.
  • \textbackslash(mu\textbackslash) is the mean.
  • \textbackslash(sigma\textbackslash) is the standard deviation.

The standard normal distribution is important in hypothesis testing and confidence intervals. It helps in converting any normal distribution to the standard form for easier calculations and comparisons.
t-distribution
The t-distribution, or Student's t-distribution, is similar to the standard normal distribution but with some differences. It also has a bell curve and is symmetric around the mean.

However, the t-distribution has heavier tails. This means that there is a higher probability of obtaining values that are far from the center. The shape depends on the degrees of freedom (\textbackslash(df\textbackslash)) which are derived from sample size (\textbackslash(n\textbackslash)).

As sample sizes increase, the t-distribution gets closer to the standard normal distribution. For small sample sizes, it's used when the population standard deviation is unknown.

The formula for t-distribution is:

\[ t = \frac{(X - \mu)}{s/\sqrt{n}} \]

Where:
  • \textbackslash(X\textbackslash) is a sample value.
  • \textbackslash(mu\textbackslash) is the sample mean.
  • \textbackslash(s\textbackslash) is the sample standard deviation.
  • \textbackslash(n\textbackslash) is the sample size.

The t-distribution is used heavily in hypothesis testing and calculating confidence intervals for small samples.
hypothesis testing
Hypothesis testing is a statistical method used to make decisions based on data. It starts with a null hypothesis (H0), which is a statement that no effect or difference is expected, and an alternative hypothesis (H1), which is what we seek to prove.

Here's a simplified process for hypothesis testing:
  • State the null and alternative hypotheses.
  • Select a significance level (usually 0.05).
  • Determine the appropriate test statistic (z or t).
  • Calculate the test statistic and the p-value.
  • Compare the p-value to the significance level.
  • Make a decision: reject or fail to reject the null hypothesis.

The test statistic (z or t) helps determine the probability of the observed result under the null hypothesis. If this probability (p-value) is less than the pre-determined significance level, we reject the null hypothesis in favor of the alternative hypothesis. Hypothesis testing often uses standard normal and t-distributions depending on the sample size and known parameters.
confidence intervals
Confidence intervals provide a range of values within which we expect the population parameter to lie. It's associated with a confidence level, usually 95%, which means if we repeated the sampling method many times, 95% of the intervals would contain the true population parameter.

The general formula to calculate a confidence interval is:

\[ \text{CI} = \bar{X} \boldsymbol{\textpm} Z \times \frac{s}{\text{sqrt{n}}}) \]

Where:
  • \textbackslash(bar{X}\textbackslash) is the sample mean.
  • \textbackslash(Z\textbackslash) is the z-value from the standard normal distribution (or t-value from the t-distribution for small samples).
  • \textbackslash(s\textbackslash) is the sample standard deviation.
  • \textbackslash(n\textbackslash) is the sample size.

For small sample sizes, t-values are used instead of z-values because they account for the extra uncertainty. Confidence intervals are crucial in statistics because they provide an estimated range that is likely to include an unknown population parameter. This helps in making inferences about the population based on sample data.

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Most popular questions from this chapter

A student constructs a \(95 \%\) confidence interval for the mean age of students at his college. The lower bound is 21.4 years and the upper bound is 28.8 years. He interprets the interval as, "There is a \(95 \%\) probability that the mean age of a student is between 21.4 years and 28.8 years" What is wrong with this interpretation? What could be done to increase the precision of the interval?

Severe acute respiratory syndrome (or SARS) is a viral respiratory illness. It has the distinction of being the first new communicable disease of the 21st century. Researchers wanted to estimate the incubation period of patients with SARS. Based on interviews with 81 SARS patients, they found that the mean incubation period was 4.6 days with a standard deviation of 15.9 days. Based on this information, construct a \(95 \%\) confidence interval for the mean incubation period of the SARS virus. Interpret the interval. (Source: Gabriel M. Leung et al., The Epidemiology of Severe Acute Respiratory Syndrome in the 2003 Hong Kong Epidemic: An Analysis of All 1755 Patients, Annals of Internal Medicine, \(2004 ; 141: 662-673 .)\)

Construct the appropriate confidence interval. A simple random sample of size \(n=300\) individuals who are currently employed is asked if they work at home at least once per week. Of the 300 employed individuals surveyed, 35 responded that they did work at home at least once per week. Construct a \(99 \%\) confidence interval about the population proportion of employed individuals who work at home at least once per week.

Suppose a certain population, \(A,\) has standard deviation \(\sigma_{A}=5,\) and a second population, \(B,\) has standard deviation \(\sigma_{B}=10 .\) How many times larger than population \(A^{\prime} \mathrm{s}\) sample size does population \(B\) 's need to be to estimate \(\mu\) with the same margin of error? [Hint: Compute \(\left.n_{B} / n_{A} \cdot\right]\)

Construct a confidence interval of the population proportion at the given level of confidence. $$x=540, n=900,96 \% \text { confidence }$$

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