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Discuss the similarities and differences between the standard normal distribution and the \(t\) -distribution.

Short Answer

Expert verified
Both distributions are symmetric and bell-shaped. The t-distribution has heavier tails and varies with sample size. The standard normal is fixed with mean 0 and SD 1.

Step by step solution

01

Define the Standard Normal Distribution

The standard normal distribution is a special case of the normal distribution with a mean of 0 and a standard deviation of 1. It follows a bell-shaped curve and is symmetric around the mean.
02

Define the t-Distribution

The t-distribution, also known as Student's t-distribution, is similar to the normal distribution but has heavier tails. It is used in statistics, particularly in hypothesis testing and confidence intervals, when the sample size is small and the population standard deviation is unknown.
03

Similarities

Both distributions are symmetric and bell-shaped. As the sample size increases, the t-distribution approaches the standard normal distribution. Both are centered around zero.
04

Differences

The main difference is that the t-distribution has heavier tails compared to the standard normal distribution, which means it has a higher probability for extreme values. The shape of the t-distribution depends on the degrees of freedom, which is related to the sample size; fewer degrees of freedom result in heavier tails. The standard normal distribution does not change shape with sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

standard normal distribution
The standard normal distribution is a type of normal distribution, but with special characteristics. It has a mean (\textbackslash(mu\textbackslash)) of 0 and a standard deviation (\textbackslash(sigma\textbackslash)) of 1. This makes the data points symmetrically distributed around the mean. The shape of the distribution is a symmetric bell curve.

The formula for the standard normal distribution is:

\[ z = \frac{(X - \mu)}{\sigma} \]

Where:
  • \textbackslash(X\textbackslash) is the value from the dataset.
  • \textbackslash(mu\textbackslash) is the mean.
  • \textbackslash(sigma\textbackslash) is the standard deviation.

The standard normal distribution is important in hypothesis testing and confidence intervals. It helps in converting any normal distribution to the standard form for easier calculations and comparisons.
t-distribution
The t-distribution, or Student's t-distribution, is similar to the standard normal distribution but with some differences. It also has a bell curve and is symmetric around the mean.

However, the t-distribution has heavier tails. This means that there is a higher probability of obtaining values that are far from the center. The shape depends on the degrees of freedom (\textbackslash(df\textbackslash)) which are derived from sample size (\textbackslash(n\textbackslash)).

As sample sizes increase, the t-distribution gets closer to the standard normal distribution. For small sample sizes, it's used when the population standard deviation is unknown.

The formula for t-distribution is:

\[ t = \frac{(X - \mu)}{s/\sqrt{n}} \]

Where:
  • \textbackslash(X\textbackslash) is a sample value.
  • \textbackslash(mu\textbackslash) is the sample mean.
  • \textbackslash(s\textbackslash) is the sample standard deviation.
  • \textbackslash(n\textbackslash) is the sample size.

The t-distribution is used heavily in hypothesis testing and calculating confidence intervals for small samples.
hypothesis testing
Hypothesis testing is a statistical method used to make decisions based on data. It starts with a null hypothesis (H0), which is a statement that no effect or difference is expected, and an alternative hypothesis (H1), which is what we seek to prove.

Here's a simplified process for hypothesis testing:
  • State the null and alternative hypotheses.
  • Select a significance level (usually 0.05).
  • Determine the appropriate test statistic (z or t).
  • Calculate the test statistic and the p-value.
  • Compare the p-value to the significance level.
  • Make a decision: reject or fail to reject the null hypothesis.

The test statistic (z or t) helps determine the probability of the observed result under the null hypothesis. If this probability (p-value) is less than the pre-determined significance level, we reject the null hypothesis in favor of the alternative hypothesis. Hypothesis testing often uses standard normal and t-distributions depending on the sample size and known parameters.
confidence intervals
Confidence intervals provide a range of values within which we expect the population parameter to lie. It's associated with a confidence level, usually 95%, which means if we repeated the sampling method many times, 95% of the intervals would contain the true population parameter.

The general formula to calculate a confidence interval is:

\[ \text{CI} = \bar{X} \boldsymbol{\textpm} Z \times \frac{s}{\text{sqrt{n}}}) \]

Where:
  • \textbackslash(bar{X}\textbackslash) is the sample mean.
  • \textbackslash(Z\textbackslash) is the z-value from the standard normal distribution (or t-value from the t-distribution for small samples).
  • \textbackslash(s\textbackslash) is the sample standard deviation.
  • \textbackslash(n\textbackslash) is the sample size.

For small sample sizes, t-values are used instead of z-values because they account for the extra uncertainty. Confidence intervals are crucial in statistics because they provide an estimated range that is likely to include an unknown population parameter. This helps in making inferences about the population based on sample data.

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Most popular questions from this chapter

Why does the margin of error increase as the level of confidence increases?

A simple random sample of size \(n\) is drawn. The sample mean, \(\bar{x},\) is found to be \(18.4,\) and the sample standard deviation, \(s\), is found to be \(4.5 .\) (a) Construct a \(95 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is 35 (b) Construct a \(95 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is \(50 .\) How does increasing the sample size affect the margin of error, \(E ?\) (c) Construct a \(99 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is \(35 .\) Compare the results to those obtained in part (a). How does increasing the level of confidence affect the margin of error, \(E ?\) (d) If the sample size is \(n=15,\) what conditions must be satisfied to compute the confidence interval?

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A simple random sample of size \(n\) is drawn from a population whose population standard deviation, \(\sigma,\) is known to be \(3.8 .\) The sample mean, \(\bar{x}\), is determined to be \(59.2 .\) (a) Compute the \(90 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is 45 (b) Compute the \(90 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is \(55 .\) How does increasing the sample size affect the margin of error, \(E ?\) (c) Compute the \(98 \%\) confidence interval about \(\mu\) if the sample size, \(n,\) is \(45 .\) Compare the results to those obtained in part (a). How does increasing the level of confidence affect the size of the margin of error, \(E ?\) (d) Can we compute a confidence interval about \(\mu\) based on the information given if the sample size is \(n=15 ?\) Why? If the sample size is \(n=15,\) what must be true regarding the population from which the sample was drawn?

2004 Presidential Election The Gallup Organization conducted a poil of 2014 likely voters just prior to the 2004 presidential election. The results of the survey indicated that George W. Bush would receive \(49 \%\) of the popular vote and John Kerry would receive \(47 \%\) of the popular vote. The margin of error was reported to be \(3 \% .\) The Gallup Organization reported that the race was too close to call. Use the concept of a confidence interval to explain what this means.

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