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Suppose a certain population, \(A,\) has standard deviation \(\sigma_{A}=5,\) and a second population, \(B,\) has standard deviation \(\sigma_{B}=10 .\) How many times larger than population \(A^{\prime} \mathrm{s}\) sample size does population \(B\) 's need to be to estimate \(\mu\) with the same margin of error? [Hint: Compute \(\left.n_{B} / n_{A} \cdot\right]\)

Short Answer

Expert verified
Population B's sample size needs to be four times larger than population A's sample size.

Step by step solution

01

- Givens and Formulas

Identify the given values and important formulas. For population A: \(\sigma_{A}=5\) For population B: \(\sigma_{B}=10\). The relationship to find is \(n_{B}/n_{A}\).
02

- Margin of Error Formula

The margin of error (ME) for a population is estimated by the formula: \[ \text{ME} = z \frac{\text{Standard Deviation}}{\text{sqrt(n)}} \]
03

- Set Up the Equation

Since the margin of error must be the same for both populations, set up the equation such that the ME for both populations are equal: \[ z \frac{\text{Standard Deviation of A}}{\text{sqrt(n_A)}} = z \frac{\text{Standard Deviation of B}}{\text{sqrt(n_B)}} \]
04

- Solve for n_B / n_A

Cancel out the common terms (z) and solve for the ratio \(_B/n_A\): \[ \frac{\sigma_{A}}{\text{sqrt(n_A)}} = \frac{\sigma_{B}}{\text{sqrt(n_B)}} \] Simplifying, we find: \[ \frac{5}{\text{sqrt(n_A)}} = \frac{10}{\text{sqrt(n_B)}} \] Cross-multiplying: \[ 5 \times \text{sqrt(n_B)} = 10 \times \text{sqrt(n_A)} \] Divide both sides by 5: \[ \text{sqrt(n_B)} = 2 \times \text{sqrt(n_A)} \] Square both sides to eliminate the square root: \[ n_B = 4n_A \]}

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation is a measure of the amount of variation or dispersion in a set of values. It shows how much the numbers in a data set deviate from the mean (average) value. A high standard deviation indicates that the data points are spread out over a wider range of values, while a low standard deviation indicates that they are clustered closely around the mean.
For example, in the given problem, population A has a standard deviation of 5, which means its data points are closer to the mean than those of population B, which has a standard deviation of 10. This concept is crucial because it affects how we compare sample sizes and calculate the margin of error for different populations.
Margin of Error
The margin of error provides a range within which we expect the true population parameter to fall. It accounts for variability in the data and helps gauge the accuracy of the sample estimate.
The formula for the margin of error is:
\[ \text{ME} = z \frac{\text{Standard Deviation}}{\sqrt{n}} \]
Here, \( z \) is the z-score corresponding to the desired confidence level, the standard deviation measures variability, and \( n \) is the sample size. For example, if you want to be 95% confident in your estimate, you'd use a z-score of approximately 1.96.
Understanding the margin of error is key because it directly impacts the level of certainty we have in our sample estimates. In the problem, ensuring the same margin of error for both populations A and B is crucial for accurate comparison.
Population Statistics
Population statistics deal with analyzing and interpreting data from an entire group of subjects (population). When we can't measure an entire population, we use a sample, which is a subset of the population, to make inferences about the population.
Common measures in population statistics include the mean, standard deviation, and variance. These metrics help us understand the central tendency and variability within a population.
For instance, in the exercise, the populations A and B have different standard deviations (5 and 10, respectively). This suggests different levels of variability, impacting how large each sample needs to be to achieve reliable estimations with the same margin of error.
Sample Size Calculation
Sample size calculation is the process of determining the number of observations or data points needed for a sample to accurately estimate a population parameter. Several factors influence this calculation, including the desired margin of error, the variability of the population (standard deviation), and the confidence level.
In our given exercise, we needed to compare sample sizes using their standard deviations. The formula for the margin of error helped us set up an equation to solve for the required ratio of sample sizes (\( n_B/n_A \)). Through a series of algebraic steps, we derived that: \[ n_B = 4n_A \].
This means that to achieve the same margin of error, population B needs to have a sample size four times larger than that of population A. Understanding these calculations is vital for designing effective and efficient studies in statistics.

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Most popular questions from this chapter

State the circumstances under which we construct a \(t\) interval. What are the circumstances under which we construct a Z-interval?

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