/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 How much do Americans sleep each... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How much do Americans sleep each night? Based on a random sample of 1120 Americans 15 years of age or older, the mean amount of sleep per night is 8.17 hours according to the American Time Use Survey conducted by the Bureau of Labor Statistics. Assuming the population standard deviation for amount of sleep per night is 1.2 hours, construct and interpret a \(95 \%\) confidence interval for the mean amount of sleep per night of Americans 15 years of age or older.

Short Answer

Expert verified
The 95% confidence interval for the mean amount of sleep per night is [8.07 hours, 8.27 hours].

Step by step solution

01

Identify the Given Information

The sample size (123120) is 1120, the sample mean (=X⎯X⎯) is 8.17 hours, the population standard deviation (σσ) is 1.2 hours, and the confidence level is 95%.
02

Determine the Z-Score for a 95% Confidence Interval

For a 95% confidence interval, the Z-score (ZZ) corresponding to this confidence level is approximately 1.96.
03

Calculate the Standard Error of the Mean

The standard error of the mean (SESE) is calculated using the formula: SE=σ/√nSubstitute in the given values: SE=1.2/√1120Calculate the result.
04

Calculate the Margin of Error

The margin of error (E) is calculated using the formula: E=Z×SESubstitute in the Z-score and the standard error values from the previous steps: E=1.96×(1.2 /√1120)Calculate the result.
05

Construct the Confidence Interval

The confidence interval is calculated using the formula: [ X⎯ −E, X⎯+E ]Substitute in the sample mean and margin of error values from the previous steps: [ 8.17−E, 8.17+E ]Calculate the results to find the lower and upper limits of the confidence interval.
06

Interpret the Confidence Interval

Interpret the resulting confidence interval: We can be 95% confident that the true mean amount of sleep per night for Americans aged 15 years or older falls within this interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

statistical analysis
Statistical analysis is a crucial tool in understanding and interpreting data. In the context of the sleep study, it helps us draw conclusions about how much sleep Americans get each night based on a sample of the population. During this process, we use various statistical methods to calculate and interpret a confidence interval. This interval allows us to estimate the range within which the true mean sleep duration for all Americans likely falls. Key steps include identifying the sample mean, determining the population standard deviation, and using a Z-score for the desired confidence level. This structured approach ensures our results are both reliable and reproducible.
confidence interval
A confidence interval provides a range of values within which we expect the true population parameter to fall. In our study, we constructed a 95% confidence interval for the mean amount of sleep among Americans aged 15 and older. This means that if we were to take many random samples and construct a confidence interval for each, 95% of those intervals would contain the true mean.
To determine the interval, we start by calculating the standard error (SE), which is found by dividing the population standard deviation by the square root of the sample size. The margin of error (E) is then found by multiplying the Z-score corresponding to our confidence level (1.96 for 95%) by the standard error. The final confidence interval is the sample mean plus and minus the margin of error.
sleep study
In this sleep study, researchers aimed to understand the sleeping habits of Americans. By collecting data from a sample of 1120 individuals aged 15 years or older, they calculated an average sleep duration of 8.17 hours per night.
Such studies are vital because they provide insights into the health and wellness of a population. Understanding sleep patterns can influence public health policies, workplace productivity standards, and general well-being guidelines. The randomly selected sample ensures that the study results are representative of the broader population, reducing the biases that could affect the findings if the sample were unrepresentative.
population standard deviation
The population standard deviation is a measure of the dispersion or spread of sleep duration in this study. It tells us how much individual sleep times vary from the average. For our sleep study, the population standard deviation is given as 1.2 hours.
This value is crucial because it helps calculate the standard error of the mean, which in turn is used to construct the confidence interval. A smaller standard deviation would suggest that most people sleep around the average of 8.17 hours, while a larger standard deviation would indicate a wider range of sleep durations.
margin of error
The margin of error quantifies the uncertainty of an estimate. In our calculation, the margin of error provides a buffer around our sample mean, accounting for potential sampling variability.
We calculated the margin of error using the formula: E = Z × SE, where Z is the Z-score for our confidence level (1.96 for 95%) and SE is the standard error. The margin of error tells us how far off our sample mean might be from the true population mean. In our sleep study, this margin ensures that we have a reliable estimate of American sleep habits within a specified range, enhancing the study's credibility and usefulness.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Lipitor The drug Lipitor" is meant to lower cholesterol levPels In a clinical trial of 863 patients who received \(10-\mathrm{mg}\) doses of Lipitor daily, 47 reported a headache as a side effect. (a) Obtain a point estimate for the population proportion of Lipitor users who will experience a headache as a side effect. (b) Verify that the requirements for constructing a confidence interval about \(\hat{p}\) are satisfied. (c) Construct a \(90 \%\) confidence interval for the population proportion of Lipitor users who will report a headache as a side effect. (d) Interpret the confidence interval.

Severe acute respiratory syndrome (or SARS) is a viral respiratory illness. It has the distinction of being the first new communicable disease of the 21st century. Researchers wanted to estimate the incubation period of patients with SARS. Based on interviews with 81 SARS patients, they found that the mean incubation period was 4.6 days with a standard deviation of 15.9 days. Based on this information, construct a \(95 \%\) confidence interval for the mean incubation period of the SARS virus. Interpret the interval. (Source: Gabriel M. Leung et al., The Epidemiology of Severe Acute Respiratory Syndrome in the 2003 Hong Kong Epidemic: An Analysis of All 1755 Patients, Annals of Internal Medicine, \(2004 ; 141: 662-673 .)\)

After watching a drama that seemed to last a long time, a student wondered how long the typical drama lasted. She obtained a random sample of 30 dramas and found the mean length of the movies to be 138.3 minutes. Assume the population standard deviation length of a drama is 27.3 minutes. (a) An analysis of the data indicated that the distribution of lengths of dramas is skewed right. Why does the student have to have a large sample size? (b) Construct and interpret a \(99 \%\) confidence interval for the mean length of a drama.

A Gallup poll conducted May \(20-22,2005\) asked Americans how many books, either hardback or paperback, they read during the previous year. How many subjects are needed to estimate the number of books Americans read the previous year within one book with \(95 \%\) confidence? Initial survey results indicate that \(\sigma=16.6\) books.

IQ scores based on the Wechsler Intelligence Scale for Children (WISC) are known to be normally distributed with \(\mu=100\) and \(\sigma=15\) (a) Simulate obtaining 20 samples of size \(n=15\) from this population. (b) Obtain the sample mean and standard deviation for each of the 20 samples. (c) Construct \(95 \%\) t-intervals for each of the 20 samples. (d) How many of the intervals do you expect to include the population mean? How many actually contain the population mean?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.