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Use the annihilator method to show that iff(x)in (4) has the formf(x)=acosβx+bsinβx,

then equation (4) has a particular solution of the form

(18)yp(x)=xs{Acosβx+Bsinβx} ,where sis chosen to be the smallest nonnegative integer such thatx3cosβxandx3sinβxare not solutions to the corresponding homogeneous equation

Short Answer

Expert verified

yp=xs(Acosβx+Bsinβx)is the form of particular solution.

Step by step solution

01

Definition

A linear differential operatorAis said to annihilate a functionfif A[f](x)=0     --(2)for all. That is, A annihilates fiffis a solution to the homogeneous linear differential equation (2) on(-∞,∞).

02

For particular solution

Equation (4) is given byany(n)+an-1yn-1+……..+a0y=f

Also givenf(x)=acosβx+bsinβx

Then,anDn+an-1Dn-1+……..+a0y=acosβx+bsinβx

So,sinβxcosβx is annihilated byD2+β2

So,D2+β2anDn+an-1Dn-1+……..+a0y=0

For particular solution i.e;ypcheck ifcosβx,sinβxare solutions to homogeneous, particular solution is different than homogeneous solution choose

yp=xs(Acosβx+Bsinβx)

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