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The auxiliary equation for the given differential equation has complex roots. Find a general solution 4y''-4y'+26y=0.

Short Answer

Expert verified

The auxiliary equation for the given differential equation4y''-4y'+26y=0 has complex roots and its general solution isrole="math" localid="1654065502147" y(t)=e12tc1cos5t2+c2sin5t2.

Step by step solution

01

Complex conjugate roots.

If the auxiliary equation has complex conjugate roots α±iβ, then the general solution is given as:

y(t)=c1eαtcosβt+c2eαtsinβt.

02

Finding the roots of the auxiliary equation.

Given differential equation is4y''-4y'+26y=0.

Then the auxiliary equation is4r2-4r+26=0

The roots of the auxiliary equation are:

role="math" localid="1654065783488" r=4±42-4×4×262×4r=4±16-4168r=4±20i8r=12±5i2

03

Final answer.

Therefore, the general solution is:

y(t)=e×t(c1cos5t2+c2sin5t2)y(t)=et(c1cos5t2+c2sin5t2)

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