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Find a general solution to the differential equation.

y''-y=-11t+1

Short Answer

Expert verified

The general solution isy=c1et+c2e-t+11t-1.

Step by step solution

01

Write the auxiliary equation of the given differential equation

The differential equation is,

y''-y=-11t+1 â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€¦(1)

The auxiliary equation for the above equation,

m2-1=0

02

Now find the complementary solution of the given equation is

Solve the auxiliary equation,

m2-1=0m=±1

The roots of the auxiliary equation are,

m1=1, â¶Ä‰â¶Ä‰& â¶Ä‰â¶Ä‰m2=-1

The complementary solution of the given equation is,

yc=c1et+c2e-t

03

Find the particular solution to find a general solution for the equation.

Assume, the particular solution of equation (1),

yp(x)=At+B â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â€¦(2)

Now find the first and second derivatives of the above equation,

yp'(x)=Ayp''(x)=0

Substitute the value of yp(x)andyp"(x)the equation (1),

y''-y=-11t+10-(At+B)=-11t+1-At-B=-11t+1

Comparing all coefficients of the above equation,

-A=-11 â¶Ä‰â‡’A=11-B=1 â¶Ä‰â‡’B=-1

Substitute the value of A and B in the equation (2),

Therefore, the particular solution of equation (1),

yp(x)=At+Byp(x)=11t-1

04

Conclusion.

Therefore, the general solution is,

y=yc(t)+yp(t)y=c1et+c2e-t+11t-1

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