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Find a general solution y'''+y''+3y'-5y=0

Short Answer

Expert verified

The general solution of the given equationy'''+y''+3y'-5y=0isy(t)=C1et+C2e-tcos(2t)+C3e-tsin(2t).

Step by step solution

01

Using rational root theorem.

First, one needs to find the auxiliary equation and solve it. One hasr3+r2+3r-5=0.

You can use the rational root theorem.

The first divisor of role="math" localid="1654073691473" 5 is role="math" localid="1654073695156" 1if will be one solution of the equation and (r-1) will be a factor.

Indeed, you have 13+12+3-5=0

Now you can dividerole="math" localid="1654073800144" r3+r2+3r-5byrole="math" localid="1654073795414" r-1 to getr2+2r+5.

02

Finding factors and roots.

The equation can be factored as (r-1)(r2+2r+5)=0.

Since r2+2r+5=0

r=-2±22-4×1×5r=-1±2i

The roots of the auxiliary equation are r=1,r=-1+2iand r=-1-2i

Thus, the general solution of the differential equation is:y(t)=C1et+C2e-tcos(2t)+C3e-tsin(2t)

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