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Chapter 4: Q24E (page 164)

In Problems 22鈥�25, use the method described in Problem 21 to find a general solution to the given equation.

24. 3z' + 11z = 0

Short Answer

Expert verified

The general solution is z(t)=ce-113t.

Step by step solution

01

Substitute z = ert

The given differential equation is 3z' + 11z = 0

Substitute z = ert and z' = rert,

3(rert) + 11(ert) = 0

(3r + 11)(ert) = 0

3r + 11 = 0

Therefore,

r=-113

02

Find the general solution.

Therefore, the general solution is z(t)=ce-113t.

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