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Use the energy integral lemma to show that every solution to the Duffing equation (18) is bounded; that is yt⩽M, for some M. [Hint: First argue that fory22+y44⩽K some K.]

Short Answer

Expert verified

Therefore, the given statement is true. The solution to the Duffing equation is bounded and that is, y⩽Mfor some M is true.

Step by step solution

01

General form

The Energy Integral Lemma:

Let y(t) be a solution to the differential equation, y=fywhere f(y) is a continuous function that does not depend on y’ or the independent variable t. Let F(y) is an indefinite integral of, fythat is, fy=ddyFy. Then the quantity Et:=12y't2-Fytis constant; i.e. ddtEt=0

Duffing equation: (18)

y+y+y3=y+1+y2y=0… (1)

02

Verify the equations

Given that, the Duffing equation is y+1+y2y=0

Then, y=-y+y3. So, fy=-y+y3

Now find the F(y).

fy=ddyFy-y+y3=ddy-y22-y44Fy=-y22-y44

Then, find the quantity.

E=12y't2-Fyt=12y't2+y22+y44

So,12y't2+y22+y44=constant

03

Verify the equation

Since the above equations are square terms. Then,

12y't2+y22+y44⩾012y't2+y44⩾0

And,

y22⩽Ky2⩽2Ky⩽2K=M

So,y⩽M

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