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Find a particular solution to the differential equation.

2z''+z=9e2t

Short Answer

Expert verified

The particular solution of the given differential equation iszp(x)=e2t.

Step by step solution

01

firstly, write the auxiliary equation of the given differential equation

The given differential equation is,

2z''+z=9e2t â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€¦(1)

Write the homogeneous differential equation of the equation (1),

2z''+z=0

The auxiliary equation for the above equation,

2m2+1=0

02

Now find the roots of the auxiliary equation 

Solve the auxiliary equation,

2m2+1=0m2=-12m=±i12

The roots of the auxiliary equation are,

m1=i12, â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰m2=-i12

The complementary solution of the given equation is,

Zc(x)=c1cos12t+c2sin12t

03

Final conclusion, find a particular solution to the differential equation

According to the method of undetermined coefficients, assume, the particular solution of equation (1),

zp(x)=Ae2t â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰......(2)

Now find the derivative of the above equation,

zp'(x)=2Ae2tzp''(x)=4Ae2t

From the equation (1),

2zp''+zp=9e2t2(4Ae2t)+Ae2t=9e2t9Ae2t=9e2tA=1

Substitute the value of A in the equation (2),

zp(x)=e2t

Therefore, the particular solution of equation (1),

zp(x)=e2t

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