/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2E In problems 聽1-4聽Use Euler鈥檚... [FREE SOLUTION] | 91影视

91影视

In problems 1-4Use Euler鈥檚 method to approximate the solution to the given initial value problem at the points x = 0.1, 0.2, 0.3, 0.4, and 0.5, using steps of size 0.1 (h = 0.1).

dydx=y(2-y),y(0)=3

Short Answer

Expert verified
xn
0.10.20.30.40.5
yn
2.72.511
2.383
2.291
2.225

Step by step solution

01

Writing the recursive formula

We have, f(x,y)=y2-y,x0=0,y0=3,h=0.1

Then,yn+1=yn+hf(xn,yn)=yn+(0.1)(2yn-yn2)

02

Putting  n=0 to find  y1

y1=y0+(0.1)(2y1-y12)=3+(0.1)(6-9)=3+(-0.3)=2.7

The value of y1=2.7 for x1=0.1

03

Putting  n=1 to find  y2

y2=y1+(0.1)(2y1-y12)=2.7+(0.1)(5.4-7.29)=2.7+(-0.189)=2.511

The value of y2=2.511 for x2=0.2

04

Putting  n=2 to find  y3

y3=y2+(0.1)(2y2-y22)=2.511+(0.1)(5.022-6.305)=2.511+(-0.128)=2.383

The value of y3=2.383 for x3=0.3

05

Putting  n=3 to find  y4

y4=y3+(0.1)(2y3-y32)=2.383+(0.1)(4.766-5.679)=2.383+(-0.091)=2.291

The value of y4=2.291 for x4=0.4

06

Putting  n=4 to find y5

y5=y4+(0.1)(2y4-y42)=2.291+(0.1)(4.582-5.249)=2.291+(-0.066)=2.225

The value of y5=2.225 for x5=0.5

Hence, the solution is

xn
0.1
0.20.30.40.5
yn
2.7
2.511
2.383
2.291
2.225

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In problems 1-6, identify the independent variable, dependent variable, and determine whether the equation is linear or nonlinear.

6-t3(d2vdt2)+3v-lnt=dvdt

In Problems 23-28, determine whether Theorem 1 implies that the given initial value problem has a unique solution.

dxdt+cosx=sint,x()=0

In Problems 14鈥24, you will need a computer and a programmed version of the vectorized classical fourth-order Runge鈥揔utta algorithm. (At the instructor鈥檚 discretion, other algorithms may be used.)鈥

Using the vectorized Runge鈥揔utta algorithm for systems withh=0.175, approximate the solution to the initial value problemx'=2x-y;x(0)=0,y'=3x+6y;y(0)=-2 att=1.

Compare this approximation to the actual solution.

The motion of a set of particles moving along the x鈥慳xis is governed by the differential equation dxdt=t3-x3, where xt denotes the position at time t of the particle.

猞 If a particle is located at x=1 when t=1 , what is its velocity at this time?

猞 Show that the acceleration of a particle is given by d2xdt2=3t2-3t3x2+3x5.

猞 If a particle is located at x=2when t=2.5, can it reach the location x=1at any later time?

[Hint: t3-x3=(t-x)(t2+xt+x2).]

Newton鈥檚 law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t) and the temperature of the body. That is, dTdt=KMt-Ttwhere K is a constant. Let K=0.04min-1and the temperature of the medium be constant, Mt=293kelvins. If the body is initially at 360 kelvins, use Euler鈥檚 method with h = 3.0 min to approximate the temperature of the body after

(a) 30 minutes.

(b) 60 minutes.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.