/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Suppose that a disease is inheri... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that a disease is inherited via an autosomal recessive mode of inheritance. The implications of this mode of inheritance are that the children in a family each have a probability of 1 in 4 of inheriting the disease.What is the probability that exactly one sibling is affected?

Short Answer

Expert verified
The probability that exactly one sibling is affected is 0.421875.

Step by step solution

01

Understanding the Problem

The problem involves a genetic disease with an autosomal recessive mode of inheritance. Each child has a 1 in 4 chance, or probability of 0.25, of being affected by this disease. We need to calculate the probability that exactly one out of several siblings is affected.
02

Setting Up the Scenario

Let's assume there are 4 siblings (without loss of generality for illustrating binomial probability distribution). Each has an independent probability of 0.25 of being affected and 0.75 of not being affected.
03

Applying the Binomial Probability Formula

We use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]where \( n = 4 \) (number of trials i.e., siblings), \( k = 1 \) (number of successes i.e., affected siblings), and \( p = 0.25 \) (probability of success).
04

Calculating the Binomial Coefficient

Calculate the binomial coefficient \( \binom{4}{1} \), which represents the number of ways to choose 1 affected sibling out of 4: \[ \binom{4}{1} = 4 \]
05

Substituting Values into the Formula

Substitute the known values into the formula: \[ P(X = 1) = 4 \times 0.25^1 \times 0.75^{3} \]This calculation involves raising probabilities to respective powers and multiplying by the binomial coefficient.
06

Performing the Calculations

Calculate each part of the equation: \[ 0.25^1 = 0.25 \]\[ 0.75^3 = 0.421875 \]Now, multiply everything: \[ P(X = 1) = 4 \times 0.25 \times 0.421875 = 0.421875 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Autosomal Recessive Inheritance
Autosomal recessive inheritance is a mode through which genetic disorders are passed down through families. This type of inheritance means that an individual must inherit two copies of a defective gene, one from each parent, to be affected by the disorder. In this case, both parents are usually carriers, each possessing one normal and one mutant allele, but they themselves might not show any symptoms of the disorder.
If a child inherits the mutant allele from both parents, that child will exhibit the disorder. Let's break it down:
  • Affected individuals have two recessive alleles.
  • Carriers have one recessive and one normal allele, typically without any symptoms.
  • If both parents are carriers, there is a 1 in 4 chance (25%) with each pregnancy that a child will be affected, a 50% chance that a child will be a carrier, and a 1 in 4 chance that the child will inherit normal alleles from both parents.
Understanding this helps explain the probability of a child inheriting certain genetic traits, as outlined in the problem where each sibling has a 0.25 chance of being affected by the disorder.
Genetic Probability
Genetic probability deals with calculating the likelihood of inheriting particular traits or disorders. When evaluating the probability of genetic outcomes within a family, several factors, such as inheritance patterns and the number of siblings, should be considered.
For autosomal recessive diseases, assessing genetic probability involves understanding each child's independent chance of inheriting two recessive alleles, which is 0.25 or 25%.
To find the probability that exactly one sibling is affected by a disorder within a group of, say, four siblings, you assess the combinations and permutations of genetic inheritance. Here, understanding that each sibling's outcome is independent but follows the same set of probabilities is important. This includes recognizing the independence of genetic events within siblings – the outcome for one does not affect the probabilities for the others.
Binomial Coefficient
The binomial coefficient is a mathematical concept used to calculate the number of ways to choose a specific number of successes from a larger set of trials. In genetics, it helps determine the probability of certain inheritance patterns among siblings.
The formula for a binomial coefficient is written as \( \binom{n}{k} \), where \( n \) is the total number of events and \( k \) is the number of successful events you are interested in.
For example, if there are 4 siblings (total trials) and you want to find the probability of exactly one being affected by a recessive disorder (success), you compute the binomial coefficient as \( \binom{4}{1} \). This evaluates to 4, indicating there are 4 possible ways for exactly one sibling to be affected.
By calculating the binomial coefficient along with the probability powers, you can assess the overall probability using the formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] This helps in determining the precise likelihood of different genetic outcomes like those examined in the exercise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a family with a mother, father, and two children. Let \(A_{1}=\left\\{\text { mother has influenzal, } A_{2}=\\{ \text { father has influenzal, }\right.\) \(A_{3}=\left\\{\text { first child has influenzal, } A_{4}=\\{ \text { second child has influ- }\right.\) enzal, \(B=\) lat least one child has influenzal, \(C=\) lat least one parent has influenzal, and \(D=\\{\) at least one person in the family has influenzal.What does \(A_{3} \cap B\) mean?

Consider a family with a mother, father, and two children. Let \(A_{1}=\left\\{\text { mother has influenzal, } A_{2}=\\{ \text { father has influenzal, }\right.\) \(A_{3}=\left\\{\text { first child has influenzal, } A_{4}=\\{ \text { second child has influ- }\right.\) enzal, \(B=\) lat least one child has influenzal, \(C=\) lat least one parent has influenzal, and \(D=\\{\) at least one person in the family has influenzal. Represent \(\bar{D}\) in terms of \(B\) and \(C .\)

Suppose that a disease is inherited via an autosomal recessive mode of inheritance. The implications of this mode of inheritance are that the children in a family each have a probability of 1 in 4 of inheriting the disease.What is the probability that neither sibling is affected?

The ankle-arm blood-pressure index (AAl) is defined as the ratio of ankle systolic blood pressure/arm systolic blood pressure and is used for the diagnosis of lower extremity arterial disease. A study was conducted to investigate whether the AAl can be used as a screening test for atherosclerotic diseases in general [20]. The subjects were 446 male workers in a copper smelter in Japan. Each subject had an AAl determination as well as an electrocardiogram (ECG). From the ECG, an S-T segment depression was defined as an S-T segment \(\geq 0.1 \mathrm{mV}\) below the baseline in at least 1 of 12 leads in a resting ECG. S-T segment depression is often used as one characterization of an abnormal ECG. The data in Table 3.22 were presented relating AAl to S-T segment depression. Suppose the reproducibility of the AAl test were improved using better technology. Would the sensitivity of the test increase, decrease, or remain the same? why?

Suppose that a disease is inherited via a sex-linked mode of inheritance. The implications of this mode of inheritance are that each male offspring has a \(50 \%\) chance of inheriting the disease, whereas the female offspring have no chance of getting the disease.What is the probability that neither sibling is affected?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.