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Suppose that a disease is inherited via an autosomal recessive mode of inheritance. The implications of this mode of inheritance are that the children in a family each have a probability of 1 in 4 of inheriting the disease.What is the probability that in a family with two children, both siblings are affected?

Short Answer

Expert verified
The probability both siblings are affected is 1/16.

Step by step solution

01

Understanding Autosomal Recessive Inheritance

In an autosomal recessive inheritance pattern, a child must inherit two copies of a recessive allele, one from each parent, to be affected by the disease. Each child has a 1 in 4 chance (\(\frac{1}{4}\)) of being affected.
02

Calculating the Probability for Two Children

To find the probability that two children are both affected, we need to consider the probability for each child separately and then multiply these probabilities. For the first child to be affected, the probability is \( \frac{1}{4} \). Similarly, for the second child to be affected, the probability is also \( \frac{1}{4} \).
03

Combining Probabilities for Both Children

Since the probabilities of each child being affected are independent events, we multiply them: \( \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \). This gives us the probability that both children are affected.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Calculating probabilities involves determining the likelihood of an event happening. For genetic conditions like autosomal recessive diseases, this involves basic arithmetic using fractions or decimals.
In the exercise, we are tasked with finding out the chance that two siblings would both be affected by a disease passed down through an autosomal recessive inheritance.
Let's break this down.

**Step-by-Step Probability Calculation**
If each child has a 1 in 4 chance of having the disease, we represent this probability as \( \frac{1}{4} \). For two children to both have the disease, we multiply their independent probabilities together.
This is because, in probability, when two events are independent, we compute the overall probability by multiplying the individual probabilities:
  • First child: \( \frac{1}{4} \)
  • Second child: \( \frac{1}{4} \)
By multiplying these probabilities, \( \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \), we get \( \frac{1}{16} \), meaning both children have a 1 in 16 chance of being affected. This makes it clear how multiplying the probabilities can give us the solution for combined outcomes.
Genetic Probability
Genetic probability refers to determining the likelihood of inheriting certain traits based on genetic inheritance patterns. For autosomal recessive diseases, understanding the genetic probability helps in assessing risks within families.

**Understanding Genetic Probability**
Genetic probability can seem complex initially, but it's based on predictable patterns. This exercise highlights a typical scenario for genetic probabilities due to autosomal recessive inheritance. In this context:
  • The probability describes how genes are passed from parents to children.
  • A recessive allele must be inherited from both parents for a child to exhibit the trait or disease.
The probability that we calculated for two siblings was based on the premise that the mode of inheritance is autosomal recessive, hence each child individually has the same steady chance. Predicting genetic outcomes helps in understanding family risks related to genetic conditions.
When dealing with genetic probability, it's crucial to consider how gene inheritance laws, like Mendelian principles, influence these chances of traits or conditions being expressed.
Recessive Allele
A recessive allele is a variant of a gene that must be inherited from both parents for its traits to be displayed. This type of allele does not produce traits unless paired with another recessive allele.

**Defining Recessive Alleles**
The key points about recessive alleles are:
  • They are only expressed when present in two copies (homozygous).
  • If only one allele is present, the individual is simply a carrier and usually does not exhibit the traits.
Autosomal recessive inheritance requires both parents to contribute a recessive allele for a child to have the disease or trait. With a 25% probability per child, described in this exercise, the child carries the disease if both parents are carriers with one recessive allele each.

Understanding recessive alleles is essential in grasping how certain genetic conditions are passed through families. Knowledge of whether an allele is recessive or dominant allows families to better understand their genetic health risks.

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Most popular questions from this chapter

The ankle-arm blood-pressure index (AAl) is defined as the ratio of ankle systolic blood pressure/arm systolic blood pressure and is used for the diagnosis of lower extremity arterial disease. A study was conducted to investigate whether the AAl can be used as a screening test for atherosclerotic diseases in general [20]. The subjects were 446 male workers in a copper smelter in Japan. Each subject had an AAl determination as well as an electrocardiogram (ECG). From the ECG, an S-T segment depression was defined as an S-T segment \(\geq 0.1 \mathrm{mV}\) below the baseline in at least 1 of 12 leads in a resting ECG. S-T segment depression is often used as one characterization of an abnormal ECG. The data in Table 3.22 were presented relating AAl to S-T segment depression. Suppose the reproducibility of the AAl test were improved using better technology. Would the sensitivity of the test increase, decrease, or remain the same? why?

Suppose that a disease is inherited via an autosomal recessive mode of inheritance. The implications of this mode of inheritance are that the children in a family each have a probability of 1 in 4 of inheriting the disease.What is the probability that neither sibling is affected?

Mayo Clinic investigators have tracked coronary-heartdisease (CHD) mortality in Olmstead County, Minnesota, for the past 20 years [17] . Mayo Clinic physicians provided virtually all medical care to Olmstead County residents. Deaths from CHD were subdivided into those that occurred in hospital and those that occurred out of hospital. Inhospital death rates are thought to be influenced mainly by advances in medical care. Out-of-hospital death rates are thought to be influenced mainly by changes in risk-factor levels over time. For men, out-of-hospital CHD death rates were 280 cases per 100,000 men per year and in-hospital CHD death rates were 120 cases per 100,000 men per year in \(1998 .\) For women, out-of-hospital CHD death rates were 100 cases per 100,000 women per year; in-hospital CHD death rates were 40 cases per 100,000 women per vear in 1998. If 50\% of the Olmstead County population is male and \(50 \%\) is female, what was the overall CHD mortality rate in Olmstead County in \(1998 ?\) The investigators reported that for both men and women, inhospital CHD death rates were declining at a rate of \(5.3 \%\) per year, whereas out-of- hospital CHD death rates were declining by \(1.8 \%\) per year.

Suppose that a disease is inherited via a dominant mode of inheritance and that only one of the two parents is affected with the disease. The implications of this mode of inheritance are that the probability is 1 in 2 that any particular offspring will get the disease. If \(A, B\) are two events such that \(A=\\{\) older child is affected \(\\}, B=\\{y \text { ounger child is affected }\\}\), then are the events \(A, B\) independent?

The familial aggregation of respiratory disease is a wellestablished clinical phenomenon. However, whether this aggregation is due to genetic or environmental factors or both is somewhat controversial. An investigator wishes to study a particular environmental factor, namely the relationship of cigarette-smoking habits in the parents to the presence or absence of asthma in their oldest child age 5 to 9 years living in the household (referred to below as their offspring). Suppose the investigator finds that (1) if both the mother and father are current smokers, then the probability of their offspring having asthma is \(.15 ;(2)\) if the mother is a current smoker and the father is not, then the probability of their offspring having asthma is \(.13 ;(3)\) if the father is a current smoker and the mother is not, then the probability of their offspring having asthma is \(.05 ;\) and (4) if neither parent is a current smoker, then the probability of their offspring having asthma is .04.Suppose the smoking habits of the parents are independent and the probability that the mother is a current smoker is \(.4,\) whereas the probability that the father is a current smoker is .5. What is the probability that both the father and mother are current smokers?

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