/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 The power \(P\) required for lev... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The power \(P\) required for level flight by an airplane is a function of the speed \(u\) of flight. Consideration of drag on the plane yields the model $$ P=\frac{u^{3}}{a}+\frac{b}{u}. $$ Here \(a\) and \(b\) are constants that depend on the characteristics of the airplane. This model may also be applied to the flight of a bird such as the budgerigar (a type of parakeet), where we take \(a=7800\) and \(b=600\). Here the flight speed \(u\) is measured in kilometers per hour, and the power \(P\) is the rate of oxygen consumption in cubic centimeters per gram per hour. \({ }^{68}\) a. Make a graph of \(P\) as a function of \(u\) for the budgerigar. Include flight speeds between 25 and 45 kilometers per hour. b. Calculate \(P(39)\) and explain what your answer means in practical terms. c. At what flight speed is the required power minimized?

Short Answer

Expert verified
a. Graph shows dependence of power on speed; b. P(39) ≈ 22.991 cm³/g/hr means oxygen consumption at speed 39 km/h; c. Power minimized at ~35 km/h.

Step by step solution

01

Understanding the Model

The model for the power required for level flight is given by the equation \( P = \frac{u^3}{a} + \frac{b}{u} \). Here, \( a = 7800 \) and \( b = 600 \), specifically for the budgerigar. The variable \( u \) represents the flight speed in kilometers per hour. Our task is to analyze this function for different parts of the problem.
02

Graphing the Function

To graph \( P(u) = \frac{u^3}{7800} + \frac{600}{u} \) for \( u \) values from 25 to 45 km/h, calculate \( P(u) \) at several points in this range and plot these values to visualize the function. The graph will help in understanding how power changes with speed and identify trends such as critical points.
03

Calculating P(39)

Substitute \( u = 39 \) into the formula: \( P(39) = \frac{39^3}{7800} + \frac{600}{39} \). Calculate \( 39^3 = 59,319 \). Evaluate \( \frac{59,319}{7800} \approx 7.606 \) and \( \frac{600}{39} \approx 15.385 \). Thus, \( P(39) \approx 7.606 + 15.385 \approx 22.991 \) cm³/g/hr.
04

Practical Meaning of P(39)

The calculation \( P(39) \approx 22.991 \) cm³/g/hr indicates that at a speed of 39 km/h, the budgerigar consumes approximately 22.991 cubic centimeters of oxygen per gram of body weight per hour. This consumption rate reflects the energy required for it to maintain this particular flight speed.
05

Minimizing Required Power

To find the speed \( u \) at which power is minimized, take the derivative of \( P(u) \), set it equal to zero, and solve for \( u \). The derivative is \( P'(u) = \frac{3u^2}{7800} - \frac{600}{u^2} \). Set \( P'(u) = 0 \) to find the critical points: \( \frac{3u^4}{7800} = 600 \). Simplify to get \( 3u^4 = 4,680,000 \), then solve \( u^4 = 1,560,000 \), and then \( u = \sqrt[4]{1,560,000} \approx 34.96 \). So, the minimum power occurs at about 35 km/h.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level Flight Dynamics
The concept of level flight dynamics is essential for understanding how an airplane can maintain a steady altitude without climbing or descending. In level flight, all the forces acting on the airplane, such as lift, weight, thrust, and drag, must be balanced. A steady flight path requires that lift and thrust align with weight and drag, respectively.
When an airplane or bird like a budgerigar flies, it needs to maintain the right speed to keep these forces in harmony. The speed influences the aerodynamic forces acting on the body. If the speed is too low, insufficient lift is generated, causing the aircraft to descend. Conversely, if the speed is too high, excessive drag opposes forward motion, requiring more power. Understanding these dynamics is vital to control and ensure efficient flight with the appropriate consumption of energy.
Power Consumption Modeling
The power consumption model for flight provides insight into the energy demands based on flight speed. The equation given as \( P = \frac{u^3}{a} + \frac{b}{u} \) demonstrates the relationship between speed \( u \) and power \( P \), incorporating constants \( a \) and \( b \) to account for vehicle or bird characteristics.
This model combines two essential components: the power needed to overcome drag, \( \frac{u^3}{a} \), and the power required to sustain lift, \( \frac{b}{u} \). As speed increases, overcoming drag becomes more significant, thereby increasing power demands, while sustaining lift might decrease due to requiring less relative lift. Therefore, this model is a valuable tool in predicting power consumption for various speeds, allowing us to optimize flight efficiency.
Mathematical Optimization
Optimizing mathematical functions is a critical step in solving many physics and engineering problems. This involves finding the point where a particular function reaches its minimum or maximum value. In the context of flight, we use optimization to determine the speed at which power consumption is minimized.
Calculating this involves taking the derivative of the power function and finding where the derivative equals zero. With \( P'(u) = \frac{3u^2}{7800} - \frac{600}{u^2} \), we solve \( P'(u) = 0 \) to locate the critical points, then verify whether these are minima or maxima. Through this process, we identify that the budgerigar achieves its minimum power at approximately 35 km/h. This speed represents the most energy-efficient manner to sustain flight with minimal oxygen consumption.
Aerodynamics in Biology
Aerodynamics is not just for airplanes; it plays a significant role in the biology of flight in birds. In birds like the budgerigar, adaptations for flight have resulted in body shapes that minimize drag and allow for efficient energy use. The relationship between speed and power consumption reflects their adaptations to optimize flight.
  • Wing shape and size contribute significantly to lift and drag, influencing the energy needed to maintain flight.
  • The streamlined body reduces resistance and plays a crucial part in aerodynamics.
These factors showcase the complexity and elegance of natural flight dynamics, as birds have evolved to balance power efficiency with maneuverability and speed. Studying these dynamics in biology helps us design better aeronautical technologies by mimicking or drawing inspiration from these natural adaptations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For communications satellites to work properly, they should appear from the surface of the Earth to remain stationary. That is, they should orbit the Earth exactly once each day. For any satellite, the period \(P\) (the length of time required to complete an orbit) is determined by its mean distance \(A\) from the center of the Earth. For a satellite of negligible mass, \(P\) and \(A\) are related by a power function \(A=c P^{2 / 3}\). a. The moon is 239,000 miles from the center of the Earth and has a period of about 28 days. How high above the center of the Earth should a geostationary satellite be? (Hint: You want the distance \(A\) for a satellite with period \(\frac{1}{28}\) that of the moon. The homogeneity property of power functions is applicable.) b. The radius of the Earth is about 3963 miles. How high above the surface of the Earth should a geostationary satellite be? \({ }^{14}\)

A rock is thrown downward, and the distance \(D\), in feet, that it falls in \(t\) seconds is given by \(D=16 t^{2}+3 t\). Find how long it takes for the rock to fall 400 feet by using a. the quadratic formula. b. the crossing-graphs method.

Consider the power functions \(f(x)=c x^{2}\). On the same screen, make graphs of \(f\) versus \(x\) for \(c=1, c=2, c=3\), and \(c=4\). We suggest a horizontal span of 0 to 5 . A table of values will be helpful in choosing a vertical span. On the basis of the plots you make, discuss the effect of the coefficient \(c\) on a power function when the power is positive.

Enzymes are proteins that act as catalysts converting one type of substance, the substrate, into another type. An example of an enzyme is invertase, an enzyme in your body, which converts sucrose into fructose and glucose. Enzymes can act very rapidly; under the right circumstances, a single molecule of an enzyme can convert millions of molecules of the substrate per minute. The Michaelis-Menten relation expresses the initial speed of the reaction as a rational function of the initial concentration of the substrate: $$ v=\frac{V s}{s+K_{m}}, $$ where \(v\) is the initial speed of the reaction (in moles per liter per second), \(s\) is the initial concentration of the substrate (in moles per liter), and \(V\) and \(K_{m}\) are constants that are important measures of the kinetic properties of the enzyme. \({ }^{74}\) For this exercise, graph the Michaelis-Menten relation giving \(v\) as a function of \(s\) for two different values of \(V\) and of \(K_{m}\). a. On the basis of your graphs, what is the horizontal asymptote of \(v\) ? b. On the basis of your graphs, what value of \(s\) makes \(v(s)=V / 2\) ? How is that value related to \(K_{m}\) ? c. In practice you don't know the values of \(V\) or \(K_{m}\). Instead, you take measurements and find the graph of \(v\) as a function \(s\). Then you use the graph to determine \(V\) and \(K_{m}\). If you have the graph, how will that enable you to determine \(V\) ? How will that enable you to determine \(K_{m}\) ?

A queue, or line, of traffic can form when a feeder road meets a main road with a high volume of traffic. In this exercise we assume that gaps in traffic on the main road (allowing cars to enter from the feeder road) appear randomly and that cars on the feeder road arrive at the intersection randomly also. We let \(s\) be the average rate at which a gap in traffic appears and \(a\) the average arrival rate, both per minute. Assume that \(s\) is greater than \(a\). a. The average length \(L\) of a queue is given by the rational function $$ L=\frac{a^{2}}{s(s-a)} . $$ Explain what happens to average queue length if arrival rate and gap rate are nearly the same. b. The average waiting time \(w\) (the time in minutes spent in the queue) is given by $$ w=\frac{a}{s(s-a)} . $$ If the gap rate is 3 per minute, what arrival rate will result in a driver's average waiting time of 2 minutes?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.