/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Enzymes are proteins that act as... [FREE SOLUTION] | 91Ó°ÊÓ

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Enzymes are proteins that act as catalysts converting one type of substance, the substrate, into another type. An example of an enzyme is invertase, an enzyme in your body, which converts sucrose into fructose and glucose. Enzymes can act very rapidly; under the right circumstances, a single molecule of an enzyme can convert millions of molecules of the substrate per minute. The Michaelis-Menten relation expresses the initial speed of the reaction as a rational function of the initial concentration of the substrate: $$ v=\frac{V s}{s+K_{m}}, $$ where \(v\) is the initial speed of the reaction (in moles per liter per second), \(s\) is the initial concentration of the substrate (in moles per liter), and \(V\) and \(K_{m}\) are constants that are important measures of the kinetic properties of the enzyme. \({ }^{74}\) For this exercise, graph the Michaelis-Menten relation giving \(v\) as a function of \(s\) for two different values of \(V\) and of \(K_{m}\). a. On the basis of your graphs, what is the horizontal asymptote of \(v\) ? b. On the basis of your graphs, what value of \(s\) makes \(v(s)=V / 2\) ? How is that value related to \(K_{m}\) ? c. In practice you don't know the values of \(V\) or \(K_{m}\). Instead, you take measurements and find the graph of \(v\) as a function \(s\). Then you use the graph to determine \(V\) and \(K_{m}\). If you have the graph, how will that enable you to determine \(V\) ? How will that enable you to determine \(K_{m}\) ?

Short Answer

Expert verified
The horizontal asymptote is \( v = V \). The substrate concentration \( s \) at which \( v = \frac{V}{2} \) is \( s = K_{m} \). The graph's horizontal asymptote gives \( V \), and \( s = K_{m} \) can be found where the curve reaches half of this maximum rate.

Step by step solution

01

Understanding the Michaelis-Menten Equation

The Michaelis-Menten equation is given by the formula \( v=\frac{V s}{s+K_{m}} \), where \( v \) is the initial reaction speed, \( V \) is the maximum rate the reaction approaches, \( s \) is the substrate concentration, and \( K_{m} \) is the Michaelis constant, representing the substrate concentration at which the reaction rate is half of \( V \).
02

Graphing the Function for Different Parameters

To graph the Michaelis-Menten equation, choose two sets of constants: \( (V_1, K_{m1}) \) and \( (V_2, K_{m2}) \). Plot \( v \) against \( s \) for each pair using the given formula. Use graphing software or a graphing calculator to visualize these relationships.
03

Identifying the Horizontal Asymptote

Examine the behavior of the graphs as \( s \) approaches infinity. The function \( v=\frac{V s}{s+K_{m}} \) simplifies to \( V \) as \( s \) gets very large. Thus, the horizontal asymptote of these graphs is \( v=V \).
04

Finding the Substrate Concentration for Half-Maximum Reaction Rate

To find the substrate concentration \( s \) that makes \( v(s)=\frac{V}{2} \), set \( \frac{V s}{s+K_{m}}=\frac{V}{2} \). Solving this equation for \( s \) by multiplying both sides by \( s+K_{m} \) and simplifying gives \( s=K_{m} \). This shows that the substrate concentration that gives half the maximum reaction speed is equal to \( K_{m} \).
05

Determining Constants from the Graph

To find \( V \) from the graph, identify the horizontal asymptote, which equals \( V \). To determine \( K_{m} \), find the substrate concentration \( s \) at which \( v=\frac{V}{2} \) as \( s=K_{m} \). These graphical features allow you to estimate \( V \) and \( K_{m} \) from real-world data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enzyme Kinetics
Enzyme kinetics is a critical area of study in biochemistry. It explores how enzymes, which are proteins acting as biological catalysts, facilitate chemical reactions in the body. This field focuses on the rates of enzymatic reactions and how various factors, such as enzyme concentration, substrate concentration, temperature, and pH levels, influence these rates.

The Michaelis-Menten equation, a foundational concept in enzyme kinetics, provides insight into how enzymes work. This mathematical model describes the relationship between the reaction rate and the substrate concentration. It is especially useful for determining key properties such as the maximum reaction rate and the enzyme's affinity for its substrate. Understanding enzyme kinetics helps us design drugs, understand metabolic pathways, and delve deeper into how cells regulate biochemical processes.
Reaction Rate
Reaction rate in the context of enzyme kinetics refers to how quickly a substrate is converted into a product by an enzyme. It is a measure of the enzyme's catalytic activity and is typically expressed in moles per liter per second ( (mol/L imes s eq ).

For many enzymatic reactions, the reaction rate can be influenced by the concentration of the substrate. At low substrate concentrations, the reaction rate is directly proportional to substrate concentration. However, as the substrate concentration increases, the reaction rate approaches a maximum value dictated by the available enzyme molecules.

This behavior is captured by the Michaelis-Menten equation, where at saturation, the reaction rate ( V ) is limited by the enzyme's ability to convert substrate to product.
Substrate Concentration
Substrate concentration plays a crucial role in enzyme activity. It refers to the amount of substrate available for the enzyme to act upon in a given reaction. As substrate concentration increases, the enzyme activity also increases up to a point.

However, beyond a certain concentration, the reaction rate reaches a plateau, as the active sites of the enzyme molecules become fully occupied. This is an important aspect of the Michaelis-Menten kinetics model, where the substrate concentration at which the reaction speed is half of its maximum value is defined as the Michaelis constant ( K_{m} ).
  • At K_{m} , the enzyme is at half its maximum efficiency.
  • Varying substrate concentrations can help in determining the enzyme's affinity for its substrate.
Understanding how enzymes interact with varying concentrations of substrate is crucial for controlling and optimizing chemical reactions, whether in industrial processes or within living organisms.
Graphing Functions
Graphing functions is an essential technique for visualizing mathematical relationships and data, especially in enzyme kinetics. By plotting the Michaelis-Menten equation, you can clearly see how the reaction rate ( v ) changes with varying substrate concentrations ( s ).

Such graphs typically display a hyperbolic curve that asymptotically approaches a horizontal line corresponding to the maximum reaction rate ( V ). At the point where this curve reaches half its maximum height, the substrate concentration equals the Michaelis constant ( K_{m} ).

  • Graphing helps identify key features like the horizontal asymptote, which corresponds to the maximum reaction speed ( V ).
  • It also enables the determination of K_{m} through observation of the substrate concentration at which the reaction rate is half of V .
Utilizing graphing functions simplifies the interpretation of complex biochemical interactions, allowing for a more intuitive understanding of enzyme kinetics.

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Most popular questions from this chapter

It is a consequence of Newton's law of gravitation that near the surface of any planet, the distance \(D\) fallen by a rock in time \(t\) is given by \(D=c t^{2}\). That is, distance fallen is proportional to the square of the time, no matter what planet one may be on. But the value of \(c\) depends on the mass of the planet. For Earth, if time is measured in seconds and distance in feet, the value of \(c\) is 16 . a. Suppose a rock is falling near the surface of a planet. What is the comparison in distance fallen from 2 seconds to 6 seconds into the drop? (Hint: This question may be rephrased as follows: "If time increases by a factor of 3 , by what factor will distance increase?") b. For objects falling near the surface of Mars, if time is measured in seconds and distance in feet, the value of \(c\) is \(6.4\). If a rock is dropped from 70 feet above the surface of Mars, how long will it take for the rock to strike the ground? c. On Venus, a rock dropped from 70 feet above the surface takes \(2.2\) seconds to strike the ground. What is the value of \(c\) for Venus?

Table \(5.3\) gives the length \(L\), in inches, of a flying animal and its maximum speed \(F\), in feet per second, when it flies. \({ }^{27}\) (For comparison, 10 feet per second is about \(6.8\) miles per hour.) $$ \begin{array}{|l|c|c|} \hline \text { Animal } & \text { Length } L & \begin{array}{c} \text { Flying speed } \\ F \end{array} \\ \hline \text { Fruit fly } & 0.08 & 6.2 \\ \hline \text { Horse fly } & 0.51 & 21.7 \\ \hline \begin{array}{l} \text { Ruby-throated } \\ \text { hummingbird } \end{array} & 3.2 & 36.7 \\ \hline \text { Willow warbler } & 4.3 & 39.4 \\ \hline \text { Flying fish } & 13 & 51.2 \\ \hline \text { Bewick's swan } & 47 & 61.7 \\ \hline \text { White pelican } & 62 & 74.8 \\ \hline \end{array} $$ a. Judging on the basis of this table, is it generally true that larger animals fly faster? b. Find a formula that models \(F\) as a power function of \(L\). c. Make the graph of the function in part b. d. Is the graph you found in part c concave up or concave down? Explain in practical terms what your answer means. e. If one bird is 10 times longer than another, how much faster would you expect it to fly? (Use the homogeneity property of power functions.)

The accompanying table shows the relationship between the length \(L\), in centimeters, and the weight \(W\), in grams, of the North Sea plaice (a type of flatfish). \({ }^{32}\) a. Find a formula that models \(W\) as a power function of \(L\). (Round the power to one decimal place.) b. Explain in practical terms what \(W(50)\) means, and then calculate that value. c. If one plaice were twice as long as another, how much heavier than the other should it be? $$ \begin{array}{|c|c|} \hline L & W \\ \hline 28.5 & 213 \\ \hline 30.5 & 259 \\ \hline 32.5 & 308 \\ \hline 34.5 & 363 \\ \hline 36.5 & 419 \\ \hline 38.5 & 500 \\ \hline 40.5 & 574 \\ \hline 42.5 & 674 \\ \hline 44.5 & 808 \\ \hline 46.5 & 909 \\ \hline 48.5 & 1124 \\ \hline \end{array} $$

In southwest Georgia, the average pine pulpwood prices vary predictably over the course of the year, primarily because of weather. From 1993 through 1997, prices followed a similar pattern. In the first quarter of each year, the average price \(P\) was \(\$ 18.50\) per ton. It decreased at a steady rate to \(\$ 14\) in the second quarter and then increased at a steady rate up to \(\$ 18\) by the fourth quarter. \({ }^{51}\) a. Sketch a graph of pulpwood prices as a function of the quarter in the year. b. What type of function is \(P\) from the first to the second quarter? c. What formula for price \(P\) as a function of \(t\), the quarter, describes the price from the first to the second quarter? d. What type of function is \(P\) from the second to the fourth quarter? e. What formula for price \(P\) as a function of \(t\), the quarter, describes the price from the second to the fourth quarter? f. Write a formula for price \(P\) throughout the year as a piecewise-defined function of \(t\), the quarter.

If we view a star now, and then view it again 6 months later, our position will have changed by the diameter of the Earth's orbit around the sun. (See Figure 5.68.) For stars within about 100 light-years of Earth, the change in viewing location is sufficient to make the star appear to be in a different location in the sky. Half of the angle from one location to the next is known as the parallax angle. Even for nearby stars, the parallax angle is very \(\operatorname{small}^{36}\) and is normally measured in seconds of arc. The distance to a star can be determined from the parallax angle. The table below gives parallax angle \(p\) measured in seconds of arc and the distance \(d\) from the sun measured in light-years. $$ \begin{array}{|l|c|c|} \hline \text { Star } & \text { Parallax angle } & \text { Distance } \\ \hline \text { Markab } & 0.030 & 109 \\ \hline \text { Al Na'ir } & 0.051 & 64 \\ \hline \text { Alderamin } & 0.063 & 52 \\ \hline \text { Altair } & 0.198 & 16.5 \\ \hline \text { Vega } & 0.123 & 26.5 \\ \hline \text { Rasalhague } & 0.056 & 58 \\ \hline \end{array} $$ a. Make a plot of \(\ln d\) against \(\ln p\), and determine whether it is reasonable to model the data with a power function. b. Make a power function model of the data for \(d\) in terms of \(p\). c. If one star has a parallax angle twice that of a second, how do their distances compare? d. The star Mergez has a parallax angle of \(0.052\) second of arc. Use functional notation to express how far away Mergez is, and then calculate that value. e. The star Sabik is 69 light-years from the sun. What is its parallax angle?

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