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Atmospheric pressure: The table below gives a measurement of atmospheric pressure, in grams per square centimeter, at the given altitude, in kilometers.17 $$ \begin{array}{|c|c|} \hline \text { Altitude } & \text { Atmospheric pressure } \\ \hline 5 & 569 \\ \hline 10 & 313 \\ \hline 15 & 172 \\ \hline 20 & 95 \\ \hline 25 & 52 \\ \hline \end{array} $$ (For comparison, 1 kilometer is about 0.6 mile, and 1 gram per square centimeter is about 2 pounds per square foot.) a. Plot the data on atmospheric pressure. b. Make an exponential model for the data on atmospheric pressure. c. What is the atmospheric pressure at an altitude of 30 kilometers? d. Find the atmospheric pressure on Earth’s surface. This is termed standard atmospheric pressure. e. At what altitude is the atmospheric pressure equal to 25% of standard atmospheric pressure?

Short Answer

Expert verified
The atmospheric pressure at 30 km is approximately 28 grams/cm². Standard pressure is roughly 1013 grams/cm². 25% of standard pressure occurs near 45 km altitude.

Step by step solution

01

Plotting the Data

First, plot the given data points on a graph. The x-axis represents altitude in kilometers, and the y-axis represents atmospheric pressure in grams per square centimeter. The given data points are: (5, 569), (10, 313), (15, 172), (20, 95), and (25, 52). Plot each of these points on the graph.
02

Finding an Exponential Model

Assume an exponential model for atmospheric pressure as \( P(h) = P_0 e^{-kh} \), where \( h \) is altitude, \( P_0 \) is the initial pressure (pressure at 0 km), and \( k \) is a decay constant. Using the data, try to fit this model by determining \( P_0 \) and \( k \). Using two points, such as (5, 569) and (25, 52), set up equations and solve them to find \( P_0 \) and \( k \).
03

Calculating the Atmospheric Pressure at 30 km

Using the exponential model \( P(h) = P_0 e^{-kh} \), substitute \( h = 30 \) to find the atmospheric pressure at 30 km. Calculate it using the values found for \( P_0 \) and \( k \).
04

Determining the Atmospheric Pressure at Earth's Surface

To find the atmospheric pressure at sea level (0 km), use the model \( P(0) = P_0 \). With the value of \( P_0 \) previously calculated, this gives us the standard atmospheric pressure.
05

Calculating Altitude for 25% of Standard Atmospheric Pressure

Calculate the altitude where the atmospheric pressure is 25% of the standard pressure (\( 0.25 P_0 \)). Rearrange the exponential formula \( 0.25 P_0 = P_0 e^{-kh} \), to \( 0.25 = e^{-kh} \). Solve for \( h \), using natural logarithms to find \( h = -\frac{\ln(0.25)}{k} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atmospheric Pressure
Atmospheric pressure is the force exerted on a surface by the weight of the air above that surface in the Earth's atmosphere. It is an essential factor in various scientific fields, including weather forecasting and aerodynamics.

As you go higher in altitude, there is less air above you, and thus, the atmospheric pressure decreases. It is usually measured in terms like grams per square centimeter or pounds per square foot. Atmospheric pressure also affects how comfortable we feel at different altitudes, as it changes the amount of oxygen available. It is vital for students to understand how pressure varies with altitude since it helps in modeling and predicting atmospheric conditions.
Altitude
Altitude refers to how high something is above a reference point, primarily sea level. It plays a crucial role in determining atmospheric pressure. As altitude increases, atmospheric pressure decreases due to the thinning of the atmosphere.

At 5 kilometers, atmospheric pressure might be around 569 grams per square centimeter, but down at sea level, it would be significantly higher. The higher the altitude, the less air exerts pressure upon the surface, which explains why mountain climbers experience breathing difficulties at high altitudes. This relationship between altitude and pressure is non-linear, which is why exponential models are often used to describe it.
Standard Atmospheric Pressure
Standard atmospheric pressure is the atmospheric pressure at sea level and at a temperature of 0 °C (32 °F), which is about 1013.25 millibars or 101325 Pascals.

This value serves as a reference point for assessing other atmospheric pressures. In many scientific and engineering applications, standard atmospheric pressure is used as a baseline to compare the reduction or increase of pressure at various altitudes. Understanding standard atmospheric pressure is vital in calculating how much atmospheric pressure changes with altitude, as seen in the exponential model of atmospheric pressure.
Data Plotting
Data plotting is a method of representing data points on a coordinate system, often using graphs. For the topic at hand, data plotting helps illustrate how atmospheric pressure changes with altitude.

When you plot atmospheric pressure against altitude, the graph typically shows a decreasing curve, indicating exponential decay. This visual aid is crucial for analyzing trends and making predictions.
  • The x-axis often represents altitude,
  • while the y-axis indicates atmospheric pressure.
By plotting the data points, such as (5, 569) or (25, 52), one can better observe how atmospheric pressure decreases as altitude increases. Data plotting enhances understanding by offering a tangible representation of the relationship between variables.

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Most popular questions from this chapter

Walking in Seattle: It is common in large cities for people to travel to the center city and then walk to their final destination. In Seattle the percent P of pedestrians who walk at least D feet from parking facilities in the center city is given partially in the accompanying table.22 $$ \begin{array}{|c|c|} \hline \text { Distance } D & \begin{array}{c} \text { Percent } P \text { walking } \\ \text { at least } D \text { feet } \end{array} \\ \hline 300 & 60 \\ \hline 500 & 40 \\ \hline 1000 & 18 \\ \hline 1500 & 9 \\ \hline 2000 & 5 \\ \hline \end{array} $$ a. Make a model of \(P\) as an exponential function of \(D\). b. What percentage of pedestrians walk at least 200 feet from parking facilities? c. When models of this sort are made, it is important to remember that many times they are only rough indicators of reality. Often they apply only to parts of the data and may tell very little about extremes of the data. Explain why it is not appropriate to view this as an accurate model for very short distances walked.

Exponential growth with given initial value and growth factor: Write the formula for an exponential function with initial value 23 and growth factor 1.4. Plot its graph.

A bad data point: A scientist sampled data for a natural phenomenon that she has good reason to believe is appropriately modeled by an exponential function N = N (t).Alaboratory assistant reported that there may have been an error in recording one of the data points but is not certain which one. Use the logarithm to find the suspect data point $$ \begin{array}{|c|c|} \hline t & N \\ \hline 0 & 21.3 \\ \hline 1 & 37.5 \\ \hline 2 & 66.0 \\ \hline 3 & 95.3 \\ \hline 4 & 204.4 \\ \hline 5 & 359.7 \\ \hline 6 & 633.1 \\ \hline \end{array} $$

Long-term population growth: Although exponential growth can often be used to model population growth accurately for some periods of time, there are inevitably, in the long term, limiting factors that make purely exponential models inaccurate. If the U.S. population had continued to grow by \(3 \%\) each year from 1790 , when it was \(3.93\) million, until today, what would the population of the United States have been in 2000 ? For comparison, according to census data, the population of the United States in 2000 was \(281,421,906\). The population of the world was just over 6 billion people.

Growth in length: In the fishery sciences it is important to determine the length of a fish as a function of its age. One common approach, the von Bertalanffy model, uses a decreasing exponential function of age to describe the growth in length yet to be attained; in other words, the difference between the maximum length and the current length is supposed to decay exponentially with age. The following table shows the length \(L\), in inches, at age \(t\), in years, of the North Sea sole. \({ }^{40}\) $$ \begin{array}{|c|c|c|c|} \hline t=\text { age } & L \text { = length } & t=\text { age } & L=\text { length } \\ \hline 1 & 3.7 & 5 & 12.7 \\ \hline 2 & 7.5 & 6 & 13.5 \\ \hline 3 & 10.0 & 7 & 14.0 \\ \hline 4 & 11.5 & 8 & 14.4 \\ \hline \end{array} $$ The maximum length attained by the sole is \(14.8\) inches. a. Make a table showing, for each age, the difference \(D\) between the maximum length and the actual length \(L\) of the sole. b. Find the exponential function that approximates \(D\) using the logarithm as a link. c. Find a formula expressing the length \(L\) of a sole as a function of its age \(t\). d. Draw a graph of \(L\) against \(t\).

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