/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A pair of fair dice is rolled. W... [FREE SOLUTION] | 91Ó°ÊÓ

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A pair of fair dice is rolled. What is the probability that a. The sum of the numbers shown uppermost is less than 5 ? b. At least one 6 is rolled?

Short Answer

Expert verified
a. The probability that the sum of numbers shown uppermost is less than 5 is \( \frac{1}{6} \). b. The probability that at least one 6 is rolled is \( \frac{11}{36} \).

Step by step solution

01

Calculating the probability that the sum of numbers is less than 5

To solve this problem, first, identify all combinations that would result in a sum less than 5. The possible sums are 2, 3 and 4. - There is one scenario with a sum of 2, which is when both dice show 1. - For a sum of 3, there are two scenarios: 1 and 2, 2 and 1. - For a sum of 4, there are three scenarios: 1 and 3, 3 and 1, 2 and 2. Therefore, there are six favorable outcomes. Hence, the probability is \( \frac{6}{36} = \frac{1}{6}\).
02

Calculating the probability of at least one 6 being rolled

All possible outcomes where at least one die shows 6 should be considered. - There are six scenarios where the first die shows 6 and the second die shows 1 to 6. - Similarly, there are six scenarios where the second die shows 6 and the first die shows 1 to 6. - But since both dice showing 6 is included in both the above cases, we should subtract it so that we only count it once to avoid duplication. Therefore, there are 11 favorable outcomes (6 + 6 - 1). Hence, the probability is \( \frac{11}{36} \). So, the answer to the problems are: a. The probability that the sum of numbers shown uppermost is less than 5 is \( \frac{1}{6} \). b. The probability that at least one 6 is rolled is \( \frac{11}{36} \).

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