/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Propuct Reuasiumr The proprietor... [FREE SOLUTION] | 91Ó°ÊÓ

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Propuct Reuasiumr The proprietor of Cunningham's Hardware Store has decided to install floodlights on the premises as a measure against vandalism and theft. If the probability is \(.01\) that a certain brand of floodlight will burn out within a year, find the minimum number of floodlights that must be installed to ensure that the probability that at least one of them will remain functional for the whole year is at least .99999. (Assume that the floodlights operate independently.)

Short Answer

Expert verified
The proprietor must install at least \(1163\) floodlights to ensure a probability of at least \(0.99999\) that at least one floodlight will remain functional for the whole year.

Step by step solution

01

Identify given probabilities

The probability that a single floodlight will burn out within a year is given as 0.01. Therefore, the probability that a single floodlight will remain functional for the whole year is 1 - 0.01 = 0.99.
02

Calculating the complementary probability

Let n be the number of floodlights to be installed. We will calculate the probability that all n floodlights burn out within a year using the formula: \(P_{allBurntOut}=(0.99)^n\) The probability that at least one floodlight will remain functional for the whole year is given by: \(P_{atLeastOneWorking}=1-P_{allBurntOut}=1-(0.99)^n\) We need to find the minimum value of n such that this probability is at least 0.99999.
03

Solving for n

Now, we set up the inequality and solve for n: \(1-(0.99)^n \ge 0.99999\) Subtract 0.99999 from both sides: \((0.99)^n \le 0.00001\) Now, we should take the logarithm of both sides to isolate n: \(n\cdot \log(0.99) \le \log(0.00001)\) Apply the change of base formula to have a common base, for example making both logarithms base 10: \(n \cdot \frac{\log_{10}(0.99)}{\log_{10}(10)} \le \frac{\log_{10}(0.00001)}{\log_{10}(10)}\) Divide both sides by the logarithm of 0.99: \(n \ge \frac{\log_{10}(0.00001)}{\log_{10}(0.99)}\) Now, we can use a calculator to compute the value: \(n \ge \frac{-5}{-0.0043}\) \(n \ge 1162.79\)
04

Determine the minimum number of floodlights

Since n must be an integer, we round up to find the smallest integer value that satisfies the inequality: n = 1163 So, the proprietor must install at least 1163 floodlights to ensure that there is at least a 0.99999 probability that at least one floodlight will remain functional for the whole year.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complementary Probability
Complementary probability is an important concept in probability theory. It involves calculating the likelihood of an event not happening by subtracting the probability of the event from one. This is useful when it's easier to calculate the probability of an event not happening than the event itself.
For instance, in our original exercise, we used complementary probability to find the likelihood of at least one floodlight remaining functional. We know the probability of a single floodlight not burning out is 0.99, hence the probability of all floodlights burning out can be expressed as \((0.99)^n\).
  • Complementary probability helps simplify problems by focusing on the opposite event.
  • It is denoted by \(1 - P(A)\) where \(P(A)\) is the probability of the event occurring.
Understanding complementary probability makes it easier to solve problems where the desired outcome is the inverse of the direct calculation.
Logarithms
Logarithms are mathematical functions that help solve equations involving exponential terms. They translate multiplication into addition, making calculations more manageable. In the context of our problem, logarithms were used to isolate the number of floodlights, \(n\), when solving for the inequality:1. Convert the exponential expression to a logarithmic one.2. Use logarithm properties to simplify computations.For example, we used:
  • \(\log((0.99)^n) = n \cdot \log(0.99)\)
  • To solve the inequality, \((0.99)^n \le 0.00001\), it becomes \(n \ge \frac{\log(0.00001)}{\log(0.99)}\)
Using a calculator, this converts complex multiplication into simple division, showing how useful logarithms can be in practical scenarios.
Inequality
An inequality is a mathematical statement that compares quantities, showing how one quantity is less than or greater than another. In this exercise, the inequality \(1-(0.99)^n \ge 0.99999\) was crucial to find the minimum number of floodlights.The steps involved:
  • Transform the expression to make \(\le\) by rearranging terms.
  • Isolate the variable of interest, in this case, \(n\), using logarithms.
  • Find the smallest integer that satisfies the inequality, which is \(n = 1163\).
Inequalities allow us to determine bounds and ranges, rather than exact values, offering practical solutions for real-world problems.
Independent Events
Events are termed independent if the occurrence of one doesn't affect the other. In this exercise, each floodlight functions independently, meaning the probability that one floodlight burns out doesn’t impact any other.Key characteristics of independent events:
  • The probability of both events occurring is the product of their individual probabilities.
  • Independence simplifies calculations because the impact of one event doesn’t alter another event.
For the floodlight scenario, since each operates independently, the probability calculation becomes simplified, using \((0.99)\) for each light over the span of the year: \((0.99)^n\) shows the compound effect of \(n\) lights possibly burning out. Thus, understanding independence helps effectively tackle this and similar problems.

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