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An cxperiment consists of two independent trials. The outcomes of the first trial are \(A, B\), and \(C\), with probabilitics of occurring cqual to \(.2, .5\), and 3, respectively. The outcomes of the second trial are \(E\) and \(F\), with probabilities of occurring equal to \(.6\) and . \(4 .\) Draw a tree diagram representing this experiment. Use this diagram to find a. \(P(B)\) b. \(P(F \mid B)\) c. \(P(B \cap F)\) d. \(P(F)\) e. Does \(P(B \cap F)=P(B) \cdot P(F)\) ? f. Are \(B\) and \(F\) independent events?

Short Answer

Expert verified
In this experiment, we have a tree diagram representing two independent trials. We find the following probabilities: a. P(B) = 0.5 b. P(F|B) = 0.4 c. P(B∩F) = 0.2 d. P(F) = 0.4 e. Yes, P(B ∩ F) = P(B) * P(F) f. Yes, B and F are independent events.

Step by step solution

01

Draw a tree diagram for the given problem.

The tree diagram is a graphical representation showing the possible outcomes of an experiment. We will have two levels in our tree diagram, the first level represents trial 1 (outcomes A, B, and C), and the second level represents trial 2 (outcomes E and F).
02

Label probabilities on the tree diagram.

We will assign the probabilities for each outcome as given in the exercise: - P(A) = 0.2, P(B) = 0.5, P(C) = 0.3 - P(E) = 0.6, P(F) = 0.4 Since the trials are independent, we will multiply the probabilities along the branches to find the joint probabilities.
03

Calculate P(B)

P(B) is the given probability of event B occurring in the first trial. P(B) = 0.5
04

Calculate P(F|B)

Since the trials are independent, the probability of event F occurring given that event B has occurred is the same as the probability of event F occurring. P(F|B) = P(F) = 0.4
05

Calculate P(B∩F)

P(B ∩ F) is the probability of event B occurring in the first trial and event F occurring in the second trial. Using the tree diagram, we can calculate P(B ∩ F) = P(B) * P(F) = 0.5 * 0.4 = 0.2
06

Calculate P(F)

P(F) is the probability of event F occurring in the second trial. P(F) = 0.4
07

Answer the question e. Does P(B ∩ F) = P(B) * P(F)?

P(B ∩ F) = 0.2, and P(B) * P(F) = 0.5 * 0.4 = 0.2. Therefore, P(B ∩ F) = P(B) * P(F).
08

Answer the question f. Are B and F independent events?

If P(B ∩ F) = P(B) * P(F), then events B and F are independent. Since P(B ∩ F) = P(B) * P(F), as determined in the previous step, events B and F are independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability theory, independent events refer to two or more events that do not affect each other's outcomes. This means that the occurrence of one event does not change the probability of the other occurring. One classic example involves flipping a coin. Each flip of the coin is independent from the previous one, meaning the probability of landing heads or tails remains constant.
In the context of the exercise, two trials are independent if the outcome of the first trial (for example, landing on event B) does not change the likelihood that the second trial results in event F. This was shown by calculating the probability of both events occurring together. If the events are independent, the joint probability is simply the product of their individual probabilities:
  • P(B) = 0.5
  • P(F) = 0.4
Therefore, the joint probability is 0.5 multiplied by 0.4, resulting in 0.2, which confirms their independence.
Tree Diagram
A tree diagram is a visual representation used in probability theory to map out all possible outcomes of an event or series of events. It is a helpful tool for organizing probabilities and understanding complex sequences. Each path in the tree diagram represents a sequence of possible outcomes.
In the exercise, the problem was solved using a tree diagram to show the two independent trials. Each level of the tree indicates a different trial:
  • Level 1 represents the outcomes of the first trial: A, B, C
  • Level 2 represents the outcomes of the second trial: E, F
Probabilities are assigned to each branch, and you can multiply these to calculate joint probabilities for events. The tree diagram helps break down the components of each trial and visualize how the outcomes combine.
Joint Probability
Joint probability is the probability of two events occurring simultaneously. When events are independent, calculating the joint probability is straightforward because you simply multiply the probabilities of the individual events.
For the exercise, we found the joint probability of B and F occurring together, written as \(P(B \cap F)\). Since B and F are proven independent:
  • P(B) = 0.5
  • P(F) = 0.4
Joint probability = 0.5 \(\times\) 0.4 = 0.2. The tree diagram played a crucial role in this calculation by visually pairing the probabilities to identify the outcomes.
Conditional Probability
Conditional probability refers to the probability of an event occurring given that another event has already occurred. It is denoted as \(P(A | B)\), which means "the probability of event A occurring given event B has happened."
In independent events, this concept simplifies because the occurrence of one does not influence the other. For the exercise, the conditional probability \(P(F | B)\) was calculated. Since trials were independent, \(P(F | B)\) simply equals \(P(F)\):
  • P(F) = 0.4
  • Thus, P(F | B) = 0.4
Conditional probability becomes particularly useful in dependent scenarios where the occurrence of one event influences another.

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