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Let \(A\) be a matrix of size \(m \times n\) and \(B\) be a matrix of size \(s \times t .\) Find conditions on \(m, n, s\), and \(t\) such that both matrix products \(A B\) and \(B A\) are defined.

Short Answer

Expert verified
Both matrix products \(AB\) and \(BA\) are defined if and only if the conditions \(n = s\) and \(t = m\) are met. This means that \(A\) must be a matrix of size \(m \times n\) and \(B\) must be a matrix of size \(n \times m\).

Step by step solution

01

Condition for AB to be defined

For the product \(A B\) to be defined, the number of columns in the matrix \(A\) should be equal to the number of rows in the matrix \(B\). That is, \(n = s\).
02

Condition for BA to be defined

For the product \(B A\) to be defined, the number of columns in the matrix \(B\) should be equal to the number of rows in the matrix \(A\). That is, \(t = m\).
03

Conclusion

Both matrix products \(AB\) and \(BA\) are defined if and only if the following conditions are met: \(n = s\) and \(t = m\). This means that \(A\) must be a matrix of size \(m \times n\) and \(B\) must be a matrix of size \(n \times m\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Dimensions
Understanding matrix dimensions is crucial when working with matrix multiplication. The dimension of a matrix is written as rows by columns, often noted as \(m \times n\). Here, "\(m\)" represents the number of rows while "\(n\)" denotes the number of columns. Therefore, a matrix with a dimension \(3 \times 2\) would have three rows and two columns.

To connect matrices through operations like multiplication, their dimensions must align correctly. This is important because dimensions indicate how many elements are present and in what arrangement they are. When you multiply two matrices, the number of columns in the first matrix needs to match the number of rows in the second matrix. This alignment allows for the proper dot product calculation during multiplication.

Remember, understanding dimensions isn't just about numbers; it's about ensuring that operations like multiplication make logical sense. Each element in the matrix has a specific position based on its dimensions, which informs how matrices interact through operations like their product or sum.
Matrix Algebra
Matrix algebra allows us to perform operations involving matrices, similar to ordinary algebra, but adapted for arrays of numbers. These operations include addition, subtraction, scalar multiplication, and importantly for our case, matrix multiplication. In matrix algebra, matrices behave as the central objects.

To add or subtract matrices, both matrices must be of the same dimension. This means they need to have the same number of rows and columns. Each element in a matrix gets added to or subtracted from the corresponding element in the other matrix.

Scalar multiplication involves multiplying every element in a matrix by a scalar (a single number). This operation changes the size of each of the matrix's entries by the scalar factor.
  • For addition or subtraction: Matrices must be of the same dimension.
  • For scalar multiplication: Every element of the matrix is multiplied by the scalar.
  • For matrix multiplication: Dimensions must align, which brings us to: if \(A\) is \(m \times n\), and \(B\) is \(n \times p\), then the result \(AB\) will be \(m \times p\).
Matrix multiplication is more complex as it involves summing the products of corresponding elements of rows and columns from the matrices involved. This also emphasizes why dimension alignment is necessary for matrix multiplication.
Matrix Products
Matrix products are a cornerstone of matrix algebra; they combine two matrices to produce a new matrix. The feasibility of the product depends on the condition that the number of columns in the first matrix matches the number of rows in the second matrix.

To calculate a matrix product like \(AB\), follow these steps:
  • Match dimensions: \(n=s\) for \(AB\) to be possible and \(t=m\) for \(BA\).
  • Perform dot product: Multiply each element of the rows of the first matrix by the corresponding element in the columns of the second matrix and sum them up to form a new matrix.
  • The result has dimensions \(m \times t\) if \(AB\) and \(t \times m\) if \(BA\).
The product matrix combines elements in a way that can change both dimension and content, which can be particularly useful in applications such as computer graphics, engineering simulations, and economic models, where data is inherently multidimensional.

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Most popular questions from this chapter

\(e\) $$ A=\left[\begin{array}{rr} 2 & 2 \\ -2 & -2 \end{array}\right] $$ Show that \(A^{2}=0\). Compare this with the equation \(a^{2}=0\), where \(a\) is a real number.

Fill in the missing entries by performing the indicated row operations to obtain the rowreduced matrices. $$ \begin{array}{l} \text { }\left[\begin{array}{rrr|r} 0 & 1 & 3 & -4 \\ 1 & 2 & 1 & 7 \\ 1 & -2 & 0 & 1 \end{array}\right] \stackrel{R_{1} \leftrightarrow R_{2}}{\longrightarrow}\left[\begin{array}{rrr|r} \cdot & \cdot & \cdot & \cdot \\ \cdot & \cdot & \cdot & \cdot \\ 1 & -2 & 0 & 1 \end{array}\right]\\\ \stackrel{R_{3}-R_{1}}{\longrightarrow}\left[\begin{array}{ccc|r} 1 & 2 & 1 & 7 \\ 0 & 1 & 3 & -4 \\ \cdot & \cdot & \cdot & \cdot \end{array}\right] \frac{R_{1}+\frac{1}{2} R_{3}}{R_{3}+4 R_{2}}\left[\begin{array}{ccc|c} \cdot & \cdot & \cdot & \cdot \\ 0 & 1 & 3 & -4 \\ \cdot & \cdot & \cdot & \cdot \end{array}\right]\\\ \stackrel{\frac{1}{11} R_{3}}{\longrightarrow}\left[\begin{array}{ccc|c} 1 & 0 & \frac{1}{2} & 4 \\ 0 & 1 & 3 & -4 \\ . & \cdot & . & . \end{array}\right] \frac{R_{1}-\frac{1}{2} R_{3}}{R_{2}-3 R_{3}}\left[\begin{array}{ccc|r} 1 & 0 & 0 & 5 \\ 0 & 1 & 0 & 2 \\ 0 & 0 & 1 & -2 \end{array}\right] \end{array} $$

Solve the system of linear equations using the Gauss-Jordan elimination method. $$ \begin{array}{l} 2 x+3 y-2 z=10 \\ 3 x-2 y+2 z=0 \\ 4 x-y+3 z=-1 \end{array} $$

Write the given system of linear equations in matrix form. $$ \begin{array}{rr} 3 x_{1}-5 x_{2}+4 x_{3}= & 10 \\ 4 x_{1}+2 x_{2}-3 x_{3}= & -12 \\ -x_{1}+x_{3}= & -2 \end{array} $$

Solve the system of linear equations using the Gauss-Jordan elimination method. $$ \begin{array}{r} x+y+z=0 \\ 2 x-y+z=1 \\ x+y-2 z=2 \end{array} $$

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