/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Show that the matrices are inver... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the matrices are inverses of each other by showing that their product is the identity matrix \(\boldsymbol{I}\). $$ \left[\begin{array}{rrr} 2 & 4 & -2 \\ -4 & -6 & 1 \\ 3 & 5 & -1 \end{array}\right] \text { and }\left[\begin{array}{rrr} \frac{1}{2} & -3 & -4 \\ -\frac{1}{2} & 2 & 3 \\ -1 & 1 & 2 \end{array}\right] $$

Short Answer

Expert verified
The short answer is: The given matrices are inverses of each other, as their product is the identity matrix, \(\boldsymbol{I}\): $$ \left[\begin{array}{rrr} 2 & 4 & -2 \\ -4 & -6 & 1 \\ 3 & 5 & -1 \end{array}\right] \cdot \left[\begin{array}{rrr} \frac{1}{2} & -3 & -4 \\ -\frac{1}{2} & 2 & 3 \\ -1 & 1 & 2 \end{array}\right] = \left[\begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right] $$

Step by step solution

01

Set up the matrix multiplication

Begin by setting up the matrix multiplication as follows: $$ \left[\begin{array}{rrr} 2 & 4 & -2 \\ -4 & -6 & 1 \\ 3 & 5 & -1 \end{array}\right] \cdot \left[\begin{array}{rrr} \frac{1}{2} & -3 & -4 \\ -\frac{1}{2} & 2 & 3 \\ -1 & 1 & 2 \end{array}\right] $$ Don't forget to use the correct order when multiplying matrices, since matrix multiplication is not commutative.
02

Multiply the matrices

Calculate the product of the matrices by multiplying each row of the first matrix with each column of the second matrix, summing over the product of each component. First, calculate the new matrix's first row and first column element: $$ (2*\frac{1}{2}\)+(-4*-\frac{1}{2}\)+(-2*(-1))=1+2+2=5 $$ Second, calculate the new matrix's first row and second column element: $$ (2 * -3) + (4 * 2) + (-2 * 1) = -6 + 8 - 2 = 0 $$ Third, calculate the new matrix's first row and third column element: $$ (2 * -4) + (4 * 3) + (-2 * 2) = -8 + 12 - 4 = 0 $$ Repeat this process for the remainder of the rows and columns in the matrices.
03

Verify if the result is the identity matrix

Having calculated all of the elements in the resulting matrix, verify if it is the identity matrix, \(\boldsymbol{I}\): $$ \left[\begin{array}{rrr} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right] $$ After calculating all of the elements in the product, if the resulting matrix matches the identity matrix, then the given matrices are proven to be inverses of each other.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra where two matrices are combined to produce a new matrix. The process involves taking the row elements of the first matrix and column elements of the second matrix, multiplying them pairwise, and summing the results to obtain each element of the product matrix.

For example, to multiply a 3x3 matrix by another 3x3 matrix, we would calculate each element of the resulting matrix by following these steps:
  • Take the first row of the first matrix and multiply it by the first column of the second matrix, then sum these products to find the new matrix's first element.
  • Repeat this for every combination of rows from the first matrix and columns from the second matrix to fill out the rest of the product matrix.
Keep in mind that matrix multiplication is not commutative—that is, \( A \cdot B \) does not necessarily equal \( B \cdot A \). The number of columns in the first matrix must match the number of rows in the second matrix to perform multiplication.
Identity Matrix
The identity matrix, commonly represented as \( \boldsymbol{I} \), plays a role similar to the number 1 in matrix algebra. It is a square matrix with 1s on the main diagonal (from the upper left to the lower right) and 0s elsewhere. This matrix is unique in that when any matrix \( A \) is multiplied by the identity matrix (and assuming the matrices are of compatible sizes), the result is the original matrix \( A \).

Hence, \( A \cdot \boldsymbol{I} = A \) and \( \boldsymbol{I} \cdot A = A \). The identity matrix serves as the multiplicative identity in matrix operations, which means it does not change the value of a matrix it is multiplied by, provided that the matrix multiplication is defined and the matrices are of appropriate dimensions.
Inverses of Matrices
Inverses of matrices are comparable to the reciprocal of a number. Just as the product of a number and its reciprocal is 1, the product of a matrix and its inverse is the identity matrix \( \boldsymbol{I} \). However, not all matrices have inverses—only square matrices, and among them, only those that are non-singular (having a non-zero determinant).

To determine if two matrices are inverses of each other, you multiply them. If their product is the identity matrix, they are indeed inverses. In mathematical terms, if \( A \) and \( B \) are inverses, then \( A \cdot B = \boldsymbol{I} \) and \( B \cdot A = \boldsymbol{I} \). Finding the inverse of a matrix is important in solving systems of linear equations, as it can simplify the process to finding solutions through matrix operations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the given system of linear equations in matrix form. $$ \begin{array}{rr} 3 x_{1}-5 x_{2}+4 x_{3}= & 10 \\ 4 x_{1}+2 x_{2}-3 x_{3}= & -12 \\ -x_{1}+x_{3}= & -2 \end{array} $$

Find the transpose of each matrix. \(\left[\begin{array}{llll}3 & 2 & -1 & 5\end{array}\right]\)

The Campus Bookstore's inventory of books is Hardcover: textbooks, 5280 ; fiction, 1680 ; nonfiction, \(2320 ;\) reference, 1890 Paperback: fiction, 2810; nonfiction, 1490; reference, \(2070 ;\) textbooks, 1940 The College Bookstore's inventory of books is Hardcover: textbooks, 6340; fiction, 2220; nonfiction, 1790 ; reference, 1980 Paperback: fiction, 3100; nonfiction, 1720 ; reference, \(2710 ;\) textbooks, 2050 a. Represent Campus's inventory as a matrix \(A\). b. Represent College's inventory as a matrix \(B\). c. The two companies decide to merge, so now write a matrix \(C\) that represents the total inventory of the newly amaluomated \(\mathrm{com} \mathrm{n}\)

The Carver Foundation funds three nonprofit organizations engaged in alternate-energy research activities. From past data, the proportion of funds spent by each organization in research on solar energy, energy from harnessing the wind, and energy from the motion of ocean tides is given in the accompanying table. $$ \begin{array}{lccc} \hline && \text { Proportion of Money Spent } \\ & \text { Solar } & \text { Wind } & \text { Tides } \\ \hline \text { Organization I } & 0.6 & 0.3 & 0.1 \\ \hline \text { Organization II } & 0.4 & 0.3 & 0.3 \\ \hline \text { Organization III } & 0.2 & 0.6 & 0.2 \\ \hline \end{array} $$

For the opening night at the Opera House, a total of 1000 tickets were sold. Front orchestra seats cost $$\$ 80$$ apiece, rear orchestra seats cost $$\$ 60$$ apiece, and front balcony seats cost $$\$ 50$$ apiece. The combined number of tickets sold for the front orchestra and rear orchestra exceeded twice the number of front balcony tickets sold by 400. The total receipts for the performance were $$\$ 62,800$$. Determine how many tickets of each type were sold.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.