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Write the given system of linear equations in matrix form. $$ \begin{array}{rr} 3 x_{1}-5 x_{2}+4 x_{3}= & 10 \\ 4 x_{1}+2 x_{2}-3 x_{3}= & -12 \\ -x_{1}+x_{3}= & -2 \end{array} $$

Short Answer

Expert verified
The given system of linear equations in matrix form is: \( Ax = b \), where: \( A = \begin{bmatrix} 3 & -5 & 4 \\ 4 & 2 & -3 \\ -1 & 0 & 1 \end{bmatrix} \), \( x = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} \), and \( b = \begin{bmatrix} 10 \\ -12 \\ -2 \end{bmatrix} \).

Step by step solution

01

Identify the coefficients

In this step, identify the coefficients for each variable in each equation. In the given system, the coefficients for the variables in the three equations are: 1. \( 3x_1 - 5x_2 + 4x_3 = 10 \): The coefficients are 3, -5, and 4. 2. \( 4x_1 + 2x_2 - 3x_3 = -12 \): The coefficients are 4, 2, and -3. 3. \( -x_1 + x_3 = -2 \): The coefficients are -1, 0, and 1 (Note that there is no \( x_2 \) term in this equation, so its coefficient is 0).
02

Create the coefficient matrix

Now that we have identified the coefficients for each equation, create the coefficient matrix (A) by placing the coefficients in the correct order. The coefficient matrix is given by: \[ A = \begin{bmatrix} 3 & -5 & 4 \\ 4 & 2 & -3 \\ -1 & 0 & 1 \end{bmatrix} \]
03

Create the constant matrix(column vector)

Now, separate the constants from the equations and create the constant matrix (b). The constant matrix is given by: \[ b = \begin{bmatrix} 10 \\ -12 \\ -2 \end{bmatrix} \]
04

Write the matrix equation

Lastly, write the system of linear equations in the matrix equation form Ax = b, where x is the column vector containing the variables \( x_1, x_2, x_3 \). The matrix equation is given by: \[ \begin{bmatrix} 3 & -5 & 4 \\ 4 & 2 & -3 \\ -1 & 0 & 1 \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = \begin{bmatrix} 10 \\ -12 \\ -2 \end{bmatrix} \] So, the given system of linear equations in matrix form is: \( Ax = b \), where: \( A = \begin{bmatrix} 3 & -5 & 4 \\ 4 & 2 & -3 \\ -1 & 0 & 1 \end{bmatrix} \), \( x = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} \), and \( b = \begin{bmatrix} 10 \\ -12 \\ -2 \end{bmatrix} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient Matrix
Understanding the coefficient matrix is crucial when learning about systems of linear equations. Imagine you have a collection of linear equations with several variables. The coefficient matrix is like a storage unit for all the numbers in front of those variables, neatly organized in rows and columns.

Each row in the matrix represents one equation from the system, and each column corresponds to a specific variable. For example, in the matrix equation \( Ax = b \) that comes from our initial system of equations, matrix \( A \) is the coefficient matrix. Following the exercise example, the coefficient matrix is:
\[ A = \begin{bmatrix}3 & -5 & 4 \ 4 & 2 & -3 \ -1 & 0 & 1\end{bmatrix} \]
This array neatly encapsulates all the coefficients in front of variables \( x_1, x_2, \) and \( x_3 \) across the three given equations. Why is this helpful? It simplifies the entire system, allowing us to perform matrix operations instead of juggling individual equations.

It's like having a manager organizing a team's effort—ensuring efficiency and clarity. Moreover, understanding how to form a coefficient matrix is the first step toward solving complex systems with methods like matrix inversion or determinant calculation.
Constant Matrix
Moving on from the coefficient matrix, the constant matrix—often denoted as \( b \) in textbooks—is equally important to grasp. This matrix contains all the constant terms (numbers without variables) from the system of equations, and just like in our exercise, it's arranged into a column vector.

The constant matrix from the given example looks like this:
\[ b = \begin{bmatrix}10 \ -12 \ -2\end{bmatrix} \]
Each entry in this vertical array corresponds to the constant in each equation of the system. Picture this: while the coefficient matrix holds the roles and responsibilities of a team, the constant matrix holds their individual targets or goals.

Together, the coefficient matrix and the constant matrix give us a comprehensive picture of the linear system at hand. Each is an indispensable part of the matrix equation, which is often used to find an elegant and sophisticated solution to what could otherwise be a very messy algebra problem. Embracing the constant matrix will help you unlock new strategies in solving linear equations, such as using matrix algebra techniques.
Matrix Equation
Finally, combining what we've learned about coefficient and constant matrices, we reach the concept of a matrix equation. A matrix equation is the compact, matrix form of a system of linear equations. Think of it as a tidy box, with everything you need to solve the system packed inside, ready to be revealed through matrix operations.

The matrix equation from our exercise is written as: \[ Ax = b \]
Here, \( A \) represents the coefficient matrix, \( x \) is the column vector of variables (in our case, \( x_1, x_2, \) and \( x_3 \) ), and \( b \) is the constant matrix. Together, they tell the whole story of the system in a single, concise equation.

Solving the matrix equation can be approached through various methods, such as Gaussian elimination, finding the inverse of the coefficient matrix, or applying Cramer's rule, each offering a systematic process to arrive at the solution. Through this elegant structure, the matrix equation not only streamlines the process of solving systems of equations but also introduces students to the power and versatility of linear algebra.

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Most popular questions from this chapter

Kaitlin and her friend Emma returned to the United States from a tour of four cities: Oslo, Stockholm, Copenhagen, and Saint Petersburg. They now wish to exchange the various foreign currencies that they have accumulated for U.S. dollars. Kaitlin has 82 Norwegian krones, 68 Swedish krones, 62 Danish krones, and 1200 Russian rubles. Emma has 64 Norwegian krones, 74 Swedish krones, 44 Danish krones, and 1600 Russian rubles. Suppose the exchange rates are U.S. \(\$ 0.1651\) for one Norwegian krone, U.S. \$0.1462 for one Swedish krone, U.S. \$0.1811 for one Danish krone, and U.S. \(\$ 0.0387\) for one Russian ruble. a. Write a \(2 \times 4\) matrix \(A\) giving the values of the various foreign currencies held by Kaitlin and Emma. (Note: The answer is not unique.) b. Write a column matrix \(B\) giving the exchange rate for the various currencies. c. If both Kaitlin and Emma exchange all their foreign currencies for U.S. dollars, how many dollars will each have?

Write the given system of linear equations in matrix form. $$ \begin{array}{r} -x_{1}+x_{2}+x_{3}=0 \\ 2 x_{1}-x_{2}-x_{3}=2 \\ -3 x_{1}+2 x_{2}+4 x_{3}=4 \end{array} $$

Hartman Lumber Company has two branches in the city. The sales of four of its products for the last year (in thousands of dollars) are represented by the matrix $$ B=\begin{array}{l} \text { Branch I } \\ \text { Branch II } \end{array} \quad\left[\begin{array}{rrrr} 5 & 3 & C & D \\ 3 & 4 & 6 & 8 \end{array}\right] $$ For the present year, management has projected that the sales of the four products in branch I will be \(10 \%\) more than the corresponding sales for last year and the sales of the four products in branch II will be \(15 \%\) more than the corresponding sales for last year. a. Show that the sales of the four products in the two branches for the current year are given by the matrix \(A B\), where $$ A=\left[\begin{array}{ll} 1.1 & 0 \\ 0 & 1.15 \end{array}\right] $$ Compute \(A B\). b. Hartman has \(m\) branches nationwide, and the sales of \(n\) of its products (in thousands of dollars) last year are represented by the matrix Product $$ \left.B=\begin{array}{c} 1 & 2 & 3 & \cdots & n \\ \text { Branch } 1 \\ \text { Branch 2 } \\ \vdots & a_{11} & a_{12} & a_{13} & \cdots & a_{1 n} \\ a_{21} & a_{22} & a_{23} & \cdots & a_{2 n} \\ \vdots & \vdots & \vdots & & \vdots \\ a_{m 1} & a_{m 2} & a_{m 3} & \cdots & a_{m n} \end{array}\right] $$ Also, management has projected that the sales of the \(n\) products in branch 1 , branch \(2, \ldots\), branch \(m\) will be \(r_{1} \%, r_{2} \%, \ldots, r_{m} \%\), respectively, more than the corresponding sales for last year. Write the matrix \(A\) such that \(A B\) gives the sales of the \(n\) products in the \(m\) branches for the current year.

Find the transpose of each matrix. \(\left[\begin{array}{llll}3 & 2 & -1 & 5\end{array}\right]\)

The Carver Foundation funds three nonprofit organizations engaged in alternate-energy research activities. From past data, the proportion of funds spent by each organization in research on solar energy, energy from harnessing the wind, and energy from the motion of ocean tides is given in the accompanying table. $$ \begin{array}{lccc} \hline && \text { Proportion of Money Spent } \\ & \text { Solar } & \text { Wind } & \text { Tides } \\ \hline \text { Organization I } & 0.6 & 0.3 & 0.1 \\ \hline \text { Organization II } & 0.4 & 0.3 & 0.3 \\ \hline \text { Organization III } & 0.2 & 0.6 & 0.2 \\ \hline \end{array} $$

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