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a. Determine whether (5,-10) is a solution for the following system of equations: $$ \begin{array}{l} 4 x-3 y=50 \\ 2 x+2 y=5 \end{array} $$ b. Explain why (-10,5) is not a solution for the system in \(\operatorname{part}(a)\)

Short Answer

Expert verified
(5, -10) is not a solution because it does not satisfy the second equation. (-10, 5) is not a solution because it does not satisfy the first equation.

Step by step solution

01

Substitute (5, -10) into the first equation

To determine if the point (5, -10) is a solution to the system, substitute the values of x=5 and y=-10 into the first equation: 4x - 3y = 50 4(5) - 3(-10) = 50 20 + 30 = 50 50 = 50 (True)
02

Substitute (5, -10) into the second equation

Now, substitute x=5 and y=-10 into the second equation: 2x + 2y = 5 2(5) + 2(-10) = 5 10 - 20 = -10 -10 ≠ 5 (False)
03

Conclusion for part (a)

Since (5, -10) does not satisfy the second equation, (5, -10) is not a solution to the system of equations.
04

Check (-10, 5) for the first equation

Substitute x=-10 and y=5 into the first equation 4(-10) - 3(5) = 50 -40 - 15 = -55 -55 ≠ 50 (False)
05

Conclusion for part (b)

Since (-10, 5) does not satisfy the first equation, it is not a solution for the system given in part (a).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

solution verification
When working with systems of equations, it's important to verify whether a given point is a solution. This verification process involves substituting the x and y values of the point into each equation of the system.

For instance, the point (5, -10) needs to be checked by substituting into both equations: the first equation is checked as follows:
    \( 4(5) - 3(-10) = 50 \ \text{ which simplifies to:} \ 20 + 30 = 50 \)
and the second equation:
    \( 2(5) + 2(-10) = 5 \ \text{ simplifies to:} \ 10 - 20 = -10 \).
The result from the second equation clearly does not match up, showing that (5, -10) is not a solution.

Similarly, substituting (-10, 5) reveals that this point also fails the verification since
    \( 4(-10) - 3(5) = -55 \) <\ul>does not equal 50.

    Key Takeaway: Substituting points into each equation is crucial in confirming whether they are solutions to the system.
linear equations
Linear equations form the backbone of various algebraic concepts and are represented in the general form:
    \( ax + by = c \).
In simpler terms, this represents a line in a two-dimensional plane, where
    \( a \) and \( b \) are coefficients, \( x \) and \( y \) are variables, and \( c \) is a constant.
Each pair of linear equations, known as a system, can be solved to identify common intersection points.

For example, consider the equations from the original problem:
      \(4x - 3y = 50 \) and \( 2x + 2y = 5 \).
These represent two lines on a Cartesian plane, and finding solutions means identifying points where these lines intersect. Solution verification helps check if any specific points like (5,-10) or (-10,5) lie on these intersecting lines.
substitution method
The substitution method is a technique used to solve systems of linear equations. It involves solving one of the equations for one variable, and then substituting this expression into the other equation. This simplifies the system to a single equation with one variable, making it easier to solve.

Here’s how the substitution method could be applied to our example:
  • Step 1: Solve one of the equations for one variable. For instance, take the second equation: \( 2x + 2y = 5 \) and solve for \( y \):
    • \( y = \frac{5 - 2x}{2} \).
  • Step 2: Substitute this expression for \( y \) into the first equation:
    • \( 4x - 3\frac{5 - 2x}{2} = 50 \),
  • Step 3: Simplify and solve the resulting equation.


  • This method systematically breaks down the complexity of the system, highlighting intersections or solutions in a straightforward manner. It's crucial when direct verification isn't sufficient for understanding or solving problems.

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