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The board of directors of the XYZ Corporation has 15 members. (a) How many different slates of four officers (a President, a Vice President, a Treasurer, and a Secretary) can be chosen? (b) A four-person committee needs to be selected to conduct a search for a new CEO. In how many ways can the search committee be selected?

Short Answer

Expert verified
The number of possible slates of four officers is 32,760 and the number of ways to choose a four-person committee is 1,365.

Step by step solution

01

Calculate the Number of Officer Combinations

The task is to calculate the number of ways to choose 4 officers out of 15 members. Since order matters (a President can't be assumed to be a Vice President), permutations must be used. For any set of \(n\) items, the number of permutations of \(r\) items is given by \( P(n, r) = \frac{n!}{(n-r)!}\)Plugging in \(n = 15\) and \(r = 4\), the formula becomes: \( P(15, 4) = \frac{15!}{(15-4)!}\)
02

Calculate the result of Step 1

After solving the math in Step 1, we get:\( P(15, 4) = \frac{15!}{11!} = 32,760\)
03

Calculate the Number of Committee Combinations

Now, the task is to calculate the number of ways to choose 4 people out of 15 to form a committee. Since in this case order doesn't matter, combinations must be used. For any set of \(n\) items, the number of combinations of \(r\) items is given by \( C(n, r) = \frac{n!}{r!*(n-r)!}\) Plugging in \(n = 15\) and \(r = 4\) into the formula, we get: \( C(15, 4) = \frac{15!}{4!*(15-4)!}\)
04

Calculate the result of Step 3

After doing the math from Step 3, we get:\( C(15, 4) = \frac{15!}{4!*11!} = 1,365\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
Permutations are arrangements where the order of the elements matters. In the context of our exercise, choosing officers for specific roles within a board is a clear example of permutations. Here, each position is distinct: President, Vice President, Treasurer, and Secretary. Thus, swapping the positions of any two members creates a different arrangement.

This is why permutations are used when order is important, unlike combinations. The formula for calculating permutations of selecting \( r \) items out of \( n \) is \( P(n, r) = \frac{n!}{(n-r)!} \).
  • \( n! \) (n factorial): Product of all integers from 1 to \( n \).
  • \( (n-r)! \): Product of all integers from 1 to \( (n-r) \).
Using our example, choosing 4 positions out of 15 members, we plug into the formula:
\( P(15, 4) = \frac{15!}{11!} = 32,760 \). Thus, there are 32,760 possible permutations for the officer positions.
Combinations
Combinations are selections where the order of elements does not matter. This comes into play in the second part of our exercise, where a committee of 4 people is selected from the 15 board members for a task. Since the specific roles of the committee members aren’t specified, any four members form one unique combination regardless of their order.

The combinations formula is given by \( C(n, r) = \frac{n!}{r!\times(n-r)!} \). Here:
  • \( n! \) is the factorial of the total number of items.
  • \( r! \) is the factorial of the number of items chosen.
  • \( (n-r)! \) accounts for the remaining items.
When calculating the combinations for choosing 4 members from 15, we find:
\( C(15, 4) = \frac{15!}{4!\times11!} = 1,365 \). Thus, 1,365 different groups of four can be selected.
Mathematical Problem Solving
Mathematical problem solving often involves recognizing whether the situation demands permutations or combinations. This can be tricky, but identifying whether order matters will guide you to the correct approach.

In permutation problems, think about different roles or positions, like officer posts. Here, the exact spot or title someone fills is crucial. Each different order leads to a new permutation. In contrast, for combination problems, such as forming committees or selecting groups where members are equal in standing, the focus is on selecting members without regard for order.

A simple approach to problem solving involves:
  • Reading the problem carefully to understand requirements.
  • Deciding if order is important (permutations) or not (combinations).
  • Applying the formulas accurately and performing calculations step by step.
This systematic process not only aids in finding the correct solution, but enhances comprehension of fundamental concepts in combinatorics.

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