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A California license plate starts with a digit other than 0 followed by three capital letters followed by three more digits (0 through 9). (a) How many different California license plates are possible? (b) How many different California license plates start with \(a 5\) and end with a \(9 ?\) (c) How many different California license plates have no repeated symbols (all the digits are different and all the letters are different)?

Short Answer

Expert verified
According to these calculations, (a) there are \(9 * 26^3 * 10^3\) possible California license plates in total, (b) there are \(1 * 9 * 26^3 * 1 * 10\) plates that start with 5 and end with 9, and (c) there are \(9 * 9 * 8 * 7 * 26 * 25 * 24\) plates that have no repeated symbols.

Step by step solution

01

Calculate total possible license plates

A California license plate starts with a digit other than 0 (9 possibilities), followed by three capital letters (26 possibilities each), followed by three more digits (0 through 9, so 10 possibilities each). Using the multiplication rule for counting, we multiply the number of possibilities for each slot. So, the total possible license plates are: \(9 * 26^3 * 10^3\).
02

Calculate plates starting with 5 and ending with 9

In this case, the first and last digits are fixed. So, we only need to consider the possibilities for the remaining 5 slots: one digit (9 possibilities because it can't be 0), three letters (26 possibilities each), and one more digit (10 possibilities). Again, we multiply the number of possibilities for each slot, resulting in: \(1 * 9 * 26^3 * 1 * 10\).
03

Calculate plates with no repeated symbols

The condition here is that no symbol (digit or letter) repeats. We have to consider the decreasing number of possibilities for each slot: the first digit has 9 possibilities, the next digit has 9 remaining possibilities (10 minus the one already used), the next digit has 8 remaining possibilities and so on, down to 7 remaining possibilities for the final digit. For the letters it's the same, with 26 possibilities for the first letter, 25 for the next, and 24 for the last one. Multiplying the possibilities for each slot gives us: \(9 * 9 * 8 * 7 * 26 * 25 * 24\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
The concept of permutations is about arranging items or symbols in a particular order. In mathematics, when we're doing permutations, we are essentially trying to determine all possible ways to order a set of items. This is very useful, especially when arranging sequences like number and letter combinations in a license plate.

Permutations are distinct from combinations in that order matters in permutation. For instance, in a situation where you have to choose 3 letters from the alphabet to come up with unique sequences, you’d not only need to choose which letters, but also decide the order they appear in.

Imagine you have a California license plate that allows 3 letters as part of its sequence. If we are looking at permutations, we calculate how many different orders we can place 26 available letters into those 3 slots:
  • The first letter has 26 possibilities because we can choose any letter from A to Z.
  • The second letter we place has 25 possibilities because it cannot be the same as the first one.
  • The third letter has 24 options, as it cannot repeat either of the first two parts.

The mathematics of this is expressed as 26 * 25 * 24. Each choice, or permutation, is unique because the order changes the outcome.
Multiplication Rule
In combinatorics, the multiplication rule is a principle used to calculate the total number of outcomes of multiple events happening in sequence. It states that if one event can happen in 'x' ways and another, independent event can happen in 'y' ways, then the two events together can happen in x * y ways altogether.

This rule is particularly useful when calculating something as complex as the possible combinations for a license plate. Each element or position has its own set of possibilities, and these are multiplied together.

For example:
  • The first digit of a California license plate has 9 possible options (since it can't be 0).
  • Each of the three letters can be independently selected in 26 different ways, leading to 26 * 26 * 26 combinations.
  • The following three digits, each independent, have 10 options each, multiplying again to give 10 * 10 * 10 possible outcomes.

Therefore, the overall calculation for the total possible combinations of license plate arrangements is done by multiplying all these individual possibilities: 9 * 26^3 * 10^3. This highlights how the multiplication rule enables us to systematically determine the total number of possible outcomes.
License Plate Combinations
The creation of license plate combinations leverages both permutation principles and the multiplication rule. License plates often have specific rules on what can be included, such as certain numbers, letters, at particular positions, and without repetition. Each state or region can have its unique set of rules, making the calculation of possible combinations both tricky and fascinating.

For example, in the California license plate design, we start with a non-zero digit, three letters, and three digits where any digit from 0 to 9 can be used. Constraints like these define how many choices are available per slot and how they combine together.

The potential combinations boil down to:
  • Selective slots where certain ranges of characters (e.g., digits or letters) must be used, such as no zero as the first character.
  • Situations where the order of characters matters, highlighted by the use of permutations to ensure no repetition.
  • Using the multiplication rule to string together distinct sections, like combining the outcomes of digits and letters on a plate.

Thus, once you understand the basics of permutations and how to apply the multiplication rule, determining license plate combinations becomes a matter of applying these mathematical principles to the constraints given by the license plate format.

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Most popular questions from this chapter

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