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Using set notation, write out the sample space for each of the following random experiments: (a) Three runners \((A, B,\) and \(C\) ) are running in a race (assume that there are no ties). The observation is the order in which the three runners cross the finish line. (b) Four runners \((A, B, C,\) and \(D)\) are running in a qualifying race (assume that there are no ties). The top two finishers qualify for the finals. The observation is the pair of runners that qualify for the finals.

Short Answer

Expert verified
The sample space for three runners participating in a race is \(S_a = \{ABC, ACB, BAC, BCA, CAB, CBA\}\). The sample space for the pair of runners that qualify from four potential runners is \(S_b = \{AB, AC, AD, BC, BD, CD\}\).

Step by step solution

01

Determine the Outcomes for Exercise (a)

For the first situation, with three runners, every single one of them could be in any of the three positions in the race. Therefore, each position can be filled by any of the three runners, resulting in \(3! = 3*2*1 = 6\) different outcomes (permutations). Thus, the sample space is \(S_a = \{ABC, ACB, BAC, BCA, CAB, CBA\}\).
02

Determine the Outcomes for Exercise (b)

For the second situation, with four runners, we're interested in how many ways we can choose two of them to qualify for the finals, regardless of order. This is a combination problem, and the number of combinations can be found using the binomial coefficient \(\(4 choose 2\) = \frac{4!}{2!(4-2)!} = \frac{4*3*2*1}{2*1*2*1} = 6\). Thus, the sample space is \(S_b = \{AB, AC, AD, BC, BD, CD\}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
Permutations are all about arranging a set of items in a specific order. It's like taking the runners in our race and thinking about the different ways they can finish. Each unique sequence counts as a different permutation.
Consider the example with three runners: A, B, and C. To find the permutations, we determine how many ways we can arrange these three in order:
  • The first position can have any of the three runners.
  • After choosing one runner for the first position, only two runners are available for the second position.
  • This leaves only one runner for the final position.
Thus, the number of permutations is calculated as \(3!\), which is \(3 \times 2 \times 1 = 6\).
The sample space using set notation, which lists all possible outcomes, is \( \{ABC, ACB, BAC, BCA, CAB, CBA\} \).
Each arrangement shows a unique order in which the runners could finish the race.
Combinations
Combinations focus on selecting items from a set without worrying about the order. Think of it as picking a group of runners that advance to finals, where the sequence of their names doesn't matter.
In our experiment with four runners, we're interested in the various ways we can choose two runners to advance, regardless of their order at the finish line.
The mathematical tool we use here is the binomial coefficient, often read as "four choose two." This measures how many groups of two can be formed from four:
The formula for combinations is given by:
  • \( \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \)
Hence, the sample space with set notation is \( \{AB, AC, AD, BC, BD, CD\} \), indicating all pairs that could qualify for the finals.
Set Notation
Set notation is a cool way to represent a collection of items. It uses curly brackets to list all possible outcomes or members of a set.
In our exercises, set notation shines by concisely listing each possible outcome of the experiments. For instance, with the three runners first task, every different finishing order of the runners forms part of the set \( \{ABC, ACB, BAC, BCA, CAB, CBA\} \).
This notation helps us visualize and understand all possible outcomes at a glance.
When you deal with combinations, the set notation also provides a clear look at groups formed, such as \( \{AB, AC, AD, BC, BD, CD\} \) for the pairs qualifying among four runners.
Using set notation is essential in probability to clearly state the outcomes.
Probability
Probability is the study of how likely events are to happen. It gives us a way to quantify the uncertainty of different outcomes.
For the permuted race scenario, probabilities could quantify the likelihood of each ordered outcome happening, assuming each order is equally possible.
The probability of each permutation happening in the three-runners problem is \( \frac{1}{6}\), since there are 6 equally likely outcomes.
In the combination scenario, the probability distribution analyzes each possible qualifying pair's chances, with each pair having a probability of \( \frac{1}{6} \) given that all pairs are equally likely.
By understanding the sample space with permutations and combinations, calculating the probability of outcomes can be straightforward. It enables better decision-making in uncertain conditions.

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