/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Assume that random guesses are m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that random guesses are made for eight multiple choice questions on an SAT test, so that there are \(n=8\) trials, each with probability of success (correct) given by \(p=0.20 .\) Find the indicated probability for the number of correct answers. Find the probability of no correct answers.

Short Answer

Expert verified
The probability of no correct answers is approximately 0.1678.

Step by step solution

01

Identify the Type of Distribution

This is a binomial distribution problem because it involves a fixed number of trials (8 multiple-choice questions) and each trial has two possible outcomes: correct or incorrect.
02

Set Up the Binomial Probability Formula

The binomial probability formula is used here: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( n = 8 \), \( k = 0 \), and \( p = 0.20 \).
03

Calculate the Binomial Coefficient

The binomial coefficient \( \binom{8}{0} \) is calculated as: \[ \binom{8}{0} = 1 \]
04

Substitute Values into the Formula

Substitute the values \( n = 8 \), \( k = 0 \), and \( p = 0.20 \) into the binomial probability formula: \[ P(X = 0) = 1 \times (0.20)^{0} \times (0.80)^{8} \]
05

Simplify the Expression

Simplify the expression: \[ P(X = 0) = 1 \times 1 \times (0.80)^8 = (0.80)^8 \] Calculate \( (0.80)^8 \): \[ (0.80)^8 \ ≈ 0.1678 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability helps us determine the likelihood of an event occurring. In our example, we want to find the chance of getting no correct answers on a multiple-choice test.

It's important to remember:
  • Probabilities range from 0 (impossible event) to 1 (certain event).
  • The probability of an event plus the probability of its complement (opposite event) equals 1.

So here, we're looking for the probability of correctly guessing zero answers out of eight questions.
Binomial Coefficient
The binomial coefficient is a key part of calculating probabilities in binomial distribution scenarios. It tells us how many ways we can choose 'k' successes out of 'n' trials. In mathematical terms, it's written as \( \binom{n}{k} \).

For our example:
  • 'n' is 8 (total questions)
  • 'k' is 0 (questions we want to get right)

The binomial coefficient \( \binom{8}{0} \) equals 1, because there's only one way to get zero correct answers: by getting all of them wrong!
Multiple Choice Questions
In this scenario, we have a multiple-choice test with eight questions. Each question has one correct answer and multiple wrong ones. We assume random guessing, and the probability of guessing correctly is given as 0.20.

This is a common setup for binomial distribution problems because:
  • There are a fixed number of trials (8 questions).
  • Each trial is independent, meaning the outcome of one question doesn't affect another.
  • Each question has only two possible outcomes: correct or incorrect.

Remember these points next time you encounter multiple-choice problems!
Statistics Calculation
Lastly, we calculate the desired probability by plugging our numbers into the binomial probability formula:
\ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \
Substituting in our values \(n = 8\), \(k = 0\), and \(p = 0.20\):
  • First, calculate the binomial coefficient: \( \binom{8}{0} = 1 \)
  • Second, plug the values in: \( P(X = 0) = 1 \times (0.20)^0 \times (0.80)^8 \)
  • Simplify: \( P(X = 0) = 1 \times 1 \times (0.80)^8 = (0.80)^8 \)
  • Finally, calculate \( (0.80)^8 \): \( (0.80)^8 \approx 0.1678 \)

So, there's about a 16.78% chance of getting no correct answers. Breaking down each step makes understanding easier!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Expected Value for the Ohio Pick 4 Lottery In the Ohio Pick 4 lottery, you can bet \(\$ 1\) by selecting four digits, each between 0 and 9 inclusive. If the same four numbers are drawn in the same order, you win and collect \(\$ 5000\). a. How many different selections are possible? b. What is the probability of winning? c. If you win, what is your net profit? d. Find the expected value for a \(\$ 1\) bet. e. If you bet \(\$ 1\) on the pass line in the casino dice game of craps, the expected value is \(-1.4 \varphi\). Which bet is better in the sense of producing a higher expected value: a \(\$ 1\) bet in the Ohio Pick 4 lottery or a \(\$ 1\) bet on the pass line in craps?

Notation Assume that we want to find the probability that when five consumers are randomly selected, exactly two of them are comfortable with delivery by drones. Also assume that \(42 \%\) of consumers are comfortable with the drones (based on a Pitney Bowes survey). Identify the values of \(n, x, p\), and \(q\).

Assume that random guesses are made for eight multiple choice questions on an SAT test, so that there are \(n=8\) trials, each with probability of success (correct) given by \(p=0.20 .\) Find the indicated probability for the number of correct answers. Find the probability that the number \(x\) of correct answers is at least 4

World War II Bombs In Exercise 1 "Notation" we noted that in analyzing hits by \(\mathrm{V}-1\) buzz bombs in World War II, South London was partitioned into 576 regions, each with an area of \(0.25 \mathrm{~km}^{2}\). A total of 535 bombs hit the combined area of 576 regions. a. Find the probability that a randomly selected region had exactly 2 hits. b. Among the 576 regions, find the expected number of regions with exactly 2 hits. c. How does the result from part (b) compare to this actual result: There were 93 regions that had exactly 2 hits?

Guessing Answers Standard tests, such as the SAT, ACT, or Medical College Admission Test (MCAT), typically use multiple choice questions, each with five possible answers (a, b, c, \(\mathrm{d}, \mathrm{e})\), one of which is correct. Assume that you guess the answers to the first three questions. a. Use the multiplication rule to find the probability that the first two guesses are wrong and the third is correct. That is, find \(P(\mathrm{WWC})\), where \(\mathrm{W}\) denotes a wrong answer and \(\mathrm{C}\) denotes a correct answer. b. Beginning with WWC, make a complete list of the different possible arrangements of two wrong answers and one correct answer, then find the probability for each entry in the list. c. Based on the preceding results, what is the probability of getting exactly one correct answer when three guesses are made?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.