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World War II Bombs In Exercise 1 "Notation" we noted that in analyzing hits by \(\mathrm{V}-1\) buzz bombs in World War II, South London was partitioned into 576 regions, each with an area of \(0.25 \mathrm{~km}^{2}\). A total of 535 bombs hit the combined area of 576 regions. a. Find the probability that a randomly selected region had exactly 2 hits. b. Among the 576 regions, find the expected number of regions with exactly 2 hits. c. How does the result from part (b) compare to this actual result: There were 93 regions that had exactly 2 hits?

Short Answer

Expert verified
The probability is 0.176. The expected number of regions with exactly 2 hits is approximately 101.376. The actual data shows 93 regions had exactly 2 hits.

Step by step solution

01

- Understand the Situation

Given 576 regions with an area of \(0.25 \text{ km}^2\) each, and a total of 535 bombs hitting these regions, find probabilities and expected values for the hits.
02

- Calculate the Average Bombs Per Region

First, compute the average number of bombs per region. This is given by \(\lambda\), which is the ratio of total bombs to total regions: \[ \lambda = \frac{535}{576} \approx 0.9297 \].
03

- Find the Probability of Exactly 2 Hits

We will use the Poisson distribution, where the probability of exactly \(k\) hits in a region is given by \[ P(X=k) = \frac{e^{-\lambda} \lambda^k}{k!} \]. For \(k=2\), \[ P(X=2) = \frac{e^{-0.9297} \times (0.9297)^2}{2!} \approx 0.176 \].
04

- Expected Number of Regions with Exactly 2 Hits

The expected number of regions with exactly \(2\) hits is given by multiplying the probability of exactly \(2\) hits by the total number of regions: \[ E(\text{regions with 2 hits}) = 576 \times 0.176 \approx 101.376 \].
05

- Compare Expected and Actual Results

The actual number of regions with exactly 2 hits is \(93\). Compare this with the expected number \(101.376\). The actual number is slightly less than the expected number, but reasonably close.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
When working with the Poisson distribution, understanding probability calculation is crucial. The Poisson distribution is often used for counting occurrences of events over a fixed period or space. It’s defined by the parameter \( \lambda\ \) (lambda), which represents the average rate of occurrences. In this case, we are analyzing bomb hits in regions of South London during World War II.
To calculate the probability that a randomly selected region was hit exactly 2 times, we need to use the Poisson probability formula:
\[ P(X=k) = \frac e^{-\lambda}\lambda^k \; k!\ \]
Here, \( P(X=2) \) is the probability we are looking for. The computations would look like this:
1. Calculate \ e^{-\lambda} \: \( e^{-0.9297} \)
2. Calculate \ \lambda^2 \: \ (0.9297)^2
3. Compute 2 factorial \: \ 2! = 2
Now, plugging these values into the formula gives:
\[ P(X=2) = \frac e^{-0.9297} \cdot (0.9297)^2 \; 2! \approx 0.176\ \]
This tells us there's approximately a 17.6% chance a randomly selected region had exactly 2 bomb hits.
Expected Value
The expected value helps us understand what we might generally expect in terms of the outcome of an event. In probability theory and statistics, the expected value of a random variable gives a measure of the center of the distribution of the variable. For the Poisson distribution, it’s directly tied to \( \lambda\ \).
In our example, to find the expected number of regions with exactly 2 hits, we multiply the total number of regions by the probability of any one region having exactly 2 hits:
\[ \text{Expected number} = 576 \cdot 0.176 \approx 101.376\ \]
This means we would expect about 101.376 regions out of 576 to have exactly 2 bomb hits. Of course, since the number of regions is discrete, it means we are anticipating about 101 regions under this probability model, but this can vary due to randomness.
Expected values provide a 'long-run' average, which can help create predictions and models in statistics.
World War II Bomb Data Analysis
Analyzing historical data, like the bomb hits in South London during World War II, helps us to understand patterns and to develop predictive models. The Poisson distribution is particularly useful in this context because bomb hits can be considered random events over a fixed space.
SOUTH LONDON CASE STUDY:
  • 576 regions of \(0.25 \ \text{km}^2\)
  • 535 bombs recorded
  • Utilized Poisson distribution for probability analysis

So when we calculated the expected number of regions with exactly 2 hits, we anticipated around 101.376 regions. However, the historical data showed 93 regions had exactly 2 hits. While there's a small difference, this closeness shows the Poisson model's applicability in this context.
Such analyses don't just stay in textbooks. They’ve been used in many fields, from predicting the number of queue lines in a call center to estimating the occurrence of rare diseases in epidemiology. This statistical model's versatility lays in its ability to simplify and decode seemingly random-like patterns into something understandable and predictable.

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