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Notation Assume that we want to find the probability that when five consumers are randomly selected, exactly two of them are comfortable with delivery by drones. Also assume that \(42 \%\) of consumers are comfortable with the drones (based on a Pitney Bowes survey). Identify the values of \(n, x, p\), and \(q\).

Short Answer

Expert verified
n = 5, x = 2, p = 0.42, q = 0.58

Step by step solution

01

- Identify the total number of trials (n)

The total number of trials, denoted as n, is the number of consumers selected. According to the problem, five consumers are selected. Hence, n = 5.
02

- Identify the number of successes (x)

The number of successes, denoted as x, is the number of consumers who are comfortable with delivery by drones. The problem states that exactly two consumers are comfortable with delivery by drones. Hence, x = 2.
03

- Identify the probability of success (p)

The probability of success, denoted as p, is the probability that a randomly selected consumer is comfortable with delivery by drones. The problem mentions that 42% of consumers are comfortable with the drones. Therefore, p = 0.42.
04

- Identify the probability of failure (q)

The probability of failure, denoted as q, is the probability that a randomly selected consumer is not comfortable with delivery by drones. Since the sum of the probabilities of success and failure equals 1, q can be calculated using the formula: \( q = 1 - p \). Therefore, q = 1 - 0.42 = 0.58.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

probability of success
The probability of success is a crucial concept in binomial probability. Here, a 'success' means achieving the desired outcome in a single trial. For example, in our exercise, a trial is asking one consumer if they are comfortable with delivery by drones. If the consumer says yes, that's a success. The probability of success, denoted as \( p \), is the likelihood this occurs. In the exercise, we are told \( 42 \% \) of consumers are comfortable with drones, so \( p = 0.42 \. \) This means that in each trial, there is a \( 0.42 \) probability of success.
number of trials
In binomial probability, the number of trials refers to how many times we repeat the experiment or process. The term is represented by the letter \( n \. \) Each trial is an independent event, meaning the outcome of one trial doesn’t affect the outcome of another. In our exercise, we are selecting five consumers to ask about their comfort with drone deliveries, which means there are five trials. So, \( n = 5 \. \) Each trial is important as it contributes to the overall binomial distribution.
probability of failure
The probability of failure represents the likelihood that a trial does not result in a success. In probability terms, 'failure' simply means not achieving the desired outcome. If the probability of success is \( p \), the probability of failure is \( q \. \) They are complementary probabilities, which means together they add up to 1. We calculate \( q \) by using the formula: \( q = 1 - p \. \) So, if \( p = 0.42 \) (42% of consumers are comfortable with drone deliveries), then: \( q = 1 - 0.42 = 0.58. \) This means there's a 58% chance a randomly selected consumer is not comfortable with drone deliveries.
binomial distribution
The binomial distribution is a probability distribution that summarizes the likelihood that a given number of successes will occur within a fixed number of trials. Each trial must be independent and have the same probability of success. In our context, we are interested in the number of consumers, out of five, who are comfortable with drone deliveries. The binomial distribution uses parameters \( n \) (number of trials), \( p \) (probability of success), and \( q \) (probability of failure) to determine the probabilities of different outcomes. We use the binomial formula: \[\binom{n}{x} p^x q^{n-x} \] to calculate the probability of exactly \( x \) successes in \( n \) trials, where \( \binom{n}{x} \) is the binomial coefficient. In our case, we want to know the probability that exactly two out of five consumers are comfortable with drone deliveries.

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