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Assume that random guesses are made for eight multiple choice questions on an SAT test, so that there are \(n=8\) trials, each with probability of success (correct) given by \(p=0.20 .\) Find the indicated probability for the number of correct answers. Find the probability that the number \(x\) of correct answers is at least 4

Short Answer

Expert verified
The probability that the number of correct answers is at least 4 is approximately 0.1045.

Step by step solution

01

Identify the Binomial Distribution Parameters

Given that there are 8 multiple choice questions and each has a probability of 0.20 of being answered correctly, the parameters for the binomial distribution are: Number of trials, \( n = 8 \)Probability of success, \( p = 0.20 \)
02

Define the Binomial Probability Formula

The probability of getting exactly \( x \) successes in \( n \) trials for a binomial distribution is given by:\[ P(X = x) = \binom{n}{x} p^x (1-p)^{n-x} \]Where \( \binom{n}{x} \) is the binomial coefficient.
03

Calculate Binomial Probabilities for \( x = 4, 5, 6, 7, 8 \)

We'll calculate the probabilities for \( x = 4, 5, 6, 7, 8 \) using the binomial formula.For \( x = 4 \):\[ P(X = 4) = \binom{8}{4} (0.20)^4 (0.80)^4 \]For \( x = 5 \):\[ P(X = 5) = \binom{8}{5} (0.20)^5 (0.80)^3 \]For \( x = 6 \):\[ P(X = 6) = \binom{8}{6} (0.20)^6 (0.80)^2 \]For \( x = 7 \):\[ P(X = 7) = \binom{8}{7} (0.20)^7 (0.80)^1 \]For \( x = 8 \):\[ P(X = 8) = \binom{8}{8} (0.20)^8 (0.80)^0 \]
04

Sum the Required Probabilities

To find the probability that the number of correct answers is at least 4, sum the probabilities of getting exactly 4, 5, 6, 7, and 8 correct answers:\[ P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) \]
05

Compute the Final Answer

Using a calculator or statistical software, compute each of the binomial probabilities and sum them. The calculations are as follows:\[ P(X = 4) \approx 0.0881 \]\[ P(X = 5) \approx 0.0147 \]\[ P(X = 6) \approx 0.0016 \]\[ P(X = 7) \approx 0.0001 \]\[ P(X = 8) \approx 0.000003 \]Therefore:\[ P(X \geq 4) \approx 0.0881 + 0.0147 + 0.0016 + 0.0001 + 0.000003 \approx 0.1045 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

binomial probability formula
When dealing with problems involving a fixed number of trials, each with two possible outcomes (success or failure), the binomial probability formula is extremely useful.
The formula calculates the probability of getting exactly a certain number of successes in a fixed number of trials. The binomial probability formula is:\[\begin{equation}P(X = x) = \binom{n}{x} p^x (1-p)^{n-x}\end{equation}\]where:
  • P(X = x) is the probability of getting exactly x successes in n trials
  • \binom{n}{x} is the binomial coefficient, which represents the number of ways to choose x successes from n trials
  • p is the probability of success on an individual trial
  • (1-p) is the probability of failure on an individual trial
  • n is the total number of trials
For example, in the SAT problem, with n=8 and p=0.20, the formula helps us determine the likelihood of various numbers of correctly answered questions.
probability of success
In binomial experiments, the probability of success (denoted as p) is crucial.
It represents the likelihood of a single trial resulting in a success. Here, 'success' is a term used to indicate the desired outcome, which might not always be inherently 'good'.
In our exercise, answering an SAT multiple-choice question correctly is considered a success, with p=0.20. This means there is a 20% chance of choosing the correct answer for any given question when guessing randomly.
Multiple trials and outcomes depend on this probability:
binomial coefficient
The binomial coefficient, denoted as \binom{n}{x}, represents the number of ways to choose x successes from n trials.
It can be calculated using the formula:\[\begin{equation}\binom{n}{x} = \frac{n!}{x! (n-x)!}\end{equation}\]Where n! denotes the factorial of n, which is the product of all positive integers up to n.
For example, in our SAT problem, \binom{8}{4} represents the number of ways to get exactly 4 correct answers out of 8 questions.
The binomial coefficient is essential for determining the different combinations of successes in the binomial probability formula.
It helps us understand the likelihood of various scenarios in repeated trials.
random guesses
Random guessing plays a significant role in the given SAT problem.
When students answer multiple-choice questions purely by guessing, each guess has an independent probability of success. In this exercise, we assume that each guess has a 20% chance of being correct.
Despite low individual success probabilities, the goal is to understand how the distribution of multiple guesses behaves.
By using the binomial probability formula, we can calculate the likelihood of different numbers of correct answers resulting from random guesses, such as finding the probability of getting at least 4 correct answers out of 8 when guessing randomly.
SAT multiple choice questions
Understanding binomial probability is especially useful for standardized tests like the SAT, where questions are often multiple-choice.
In these scenarios, students might resort to random guessing, particularly when unsure of the correct answer.
The SAT problem discussed involves 8 multiple choice questions where each question has a 20% chance of being answered correctly by random guessing. Using the binomial distribution, students can predict their performance based on random guessing behavior.
Educators can also use these principles to design more effective test preparation strategies, emphasizing areas where students are more likely to guess and need further study. By understanding these probabilistic concepts, students can have a better grasp of their test-taking strategies and expectations.

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