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A study of human body temperatures using healthy women showed a mean of \(98.4{ }^{\circ} \mathrm{F}\) and a standard deviation of about \(0.70^{\circ} \mathrm{F}\). Assume the temperatures are approximately Normally distributed. a. Find the percentage of healthy women with temperatures below \(98.6^{\circ} \mathrm{F}\) (this temperature was considered typical for many decades). b. What temperature does a healthy woman have if her temperature is at the 76 th percentile?

Short Answer

Expert verified
a. The representation of healthy women with temperatures below 98.6 degrees depends on the Z-score calculated and the corresponding percentage in the standard normal table. b. The temperature for the 76th percentile woman depends on the Z-score from the percentile and subsequently is calculated using the Z-Score formula to find the corresponding temperature.

Step by step solution

01

Calculate Z-Score for Part A

To find the Z-score noted as \( Z \) , use the formula \( Z =(X - μ )/ σ \) where \( X \) is the value to be analyzed, in this case 98.6 degrees, μ is the mean, and σ is the standard deviation. So, \( Z =(98.6 - 98.4) / 0.70 \). Calculate to find the value of Z.
02

Find Percentage for Part A

The standard normal table is then consulted to find the percentage of women with temperatures below 98.6 degrees. Look up the Z-score calculated in Step 1 in this table or in a calculator, and find the corresponding percentage.
03

Calculate Temperature for Part B

To calculate the temperature at the 76th percentile, first locate the 'Z' value that corresponds to this percentile in the standard normal table. Remember, percentile means the percentage of values that fall below a certain data point – so the 76th percentile represents the temperature below which 76% of the women's temperatures fall.
04

Apply Z-Score formula for Part B

Use the Z-score formula, but this time solve for \( X \) , which is the temperature in this case. The formula is \( X = μ + Zσ \) . Plug in the Z-score found in Step 3, the given mean (98.4), and the given standard deviation (0.70) to find the temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score Calculation
Understanding the Z-score in statistics is like knowing how to read a map in a new city – it gives you an idea of where you are relative to everything else. The Z-score, often called the standard score, quantifies how many standard deviations an element X is from the mean (average) of a dataset.

The formula for calculating a Z-score is: \[ Z = \frac{(X - \mu)}{\sigma} \]
Where:\begin{itemize}\item \( X \) is the data point in question.\item \( \mu \) is the mean of the dataset.\item \( \sigma \) is the standard deviation of the dataset.\end{itemize}
For instance, in our exercise related to body temperatures of healthy women, to find the Z-score for a temperature of \(98.6^\circ F\), we could apply the formula using \(98.4^\circ F\) as the mean and \(0.70^\circ F\) as the standard deviation.

This calculated Z-score can tell us how 'typical' or 'atypical' a temperature is within the scope of our dataset. In the context of normal distribution, a Z-score of 0 would indicate a temperature exactly at the mean, while positive or negative values illustrate temperatures above or below the mean, respectively.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. Think of it as a gauge of how spread out the numbers are in a dataset. A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation implies more widespread data points.

The standard deviation is crucial in the context of normal distribution because it helps define the scale of the 'bell curve' or normal curve. For example, in a dataset of women's body temperatures, a standard deviation tells you how varied individual temperatures are from the average (mean) temperature.

In practice, to calculate the standard deviation, you would typically do two main things:\begin{itemize}\item Calculate the variance, which means finding the average of the squared differences from the mean.\item Take the square root of the variance to get the standard deviation.\end{itemize}
In our problem, we're given a standard deviation of \(0.70^\circ F\), so no calculation is needed. However, understanding its role is key: it's used in the Z-score formula and influences the distribution's shape, impacting conclusions and interpretations about the data.
Percentiles in Statistics
Percentiles are extremely useful in statistics for understanding relative standing within a dataset. Essentially, the nth percentile is a value below which a certain percentage of observations in a dataset fall. For instance, the 50th percentile is the median, standing right in the 'middle' of your data.

Percentiles tell us about the distribution of data. To find a specific percentile, you often start with its corresponding Z-score, especially if the dataset follows a normal distribution. For example, if you want to know the value at the 76th percentile, determine the Z-score that corresponds with 76% of the data falling below it. This involves looking up values in a standard normal distribution table or using a calculator with statistical functions.

In our textbook problem, locating the 76th percentile meant finding the temperature below which 76% of the observed women's temperatures lie. After finding the associated Z-score, we could then use it along with the mean and standard deviation to calculate the exact temperature at this percentile by applying the formula:\begin{itemize}\item The formula to use would be \( X = \mu + Z\sigma \)\end{itemize}Percentiles are a powerful way to communicate statistical data, as it allows one to express how a particular value compares to the rest of the dataset, particularly in areas such as health, education, and psychology.

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Most popular questions from this chapter

Quantitative S \(\Lambda\) T scores are approximately Normally distributed with a mean of 500 and a standard deviation of 100 . Choose the correct StatCrunch output for finding the probability that a randomly selected person scores less than 450 on the quantitative SAT and report the probability as a percentage rounded to one decimal place.

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