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Quantitative S \(\Lambda\) T scores are approximately Normally distributed with a mean of 500 and a standard deviation of 100 . Choose the correct StatCrunch output for finding the probability that a randomly selected person scores less than 450 on the quantitative SAT and report the probability as a percentage rounded to one decimal place.

Short Answer

Expert verified
The probability that a randomly selected person scores less than 450 on the quantitative SAT is \(P(Z < -0.5)\). This is then converted into percentage and rounded to one decimal place

Step by step solution

01

Calculate the Z-score

The Z-score is calculated as: \( Z = \frac{X - \mu}{\sigma} \), where X is the score, \(\mu\) is the average, and \(\sigma\) is the standard deviation. In this case, X=450, \(\mu\)=500, and \(\sigma\)=100.
02

Calculate the value of Z

Substituting these values into the Z-score formula gives: \( Z = \frac{450 - 500}{100} = -0.5 \)
03

Find the Probability

Use the standard normal distribution (Z) table or a tool like StatCrunch to find the probability that a randomly selected person scores less than 450 on the SAT. Since the Z-score for 450 is -0.5, look up -0.5 on the Z-table. This corresponds to the probability which is the desired value.
04

Convert the Probability to Percentage

To report the probability percentage, multiply the probability by 100 and round to a single decimal place.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score calculation
Understanding the concept of a Z-score is vital when working with normal distributions. The Z-score is a statistical measure that tells us how many standard deviations an individual data point (X) is from the mean of the data set. It's a way to quantify the position of a data point within a distribution. This standardization makes it easier to compare scores from different distributions. The formula for calculating a Z-score is: \( Z = \frac{X - \mu}{\sigma} \), where:
  • \(X\) is the value of the data point,
  • \(\mu\) represents the mean of the distribution,
  • \(\sigma\) stands for the standard deviation.
So, in practice, you take the score you are evaluating (like the SAT score of 450 in this case), subtract the mean score, and then divide by the standard deviation to get the Z-score. This tells you where the score lies relative to the average—whether it's below or above it.
In our example, a score of 450 resulted in a Z-score of -0.5, which indicates that 450 is half a standard deviation below the mean score of 500.
Standard Normal Distribution
The standard normal distribution is a specific type of normal distribution. It is a bell-shaped curve that is symmetrical around its mean, which is zero in the case of the standard normal distribution. This distribution has a standard deviation of one. Using the standard normal distribution, we can transform any normal distribution data using Z-scores.
Transforming to a standard normal distribution allows for the use of Z-tables, which provide probability values for different Z-scores.
  • These tables show the area under the standard normal curve to the left of any given Z-score.
  • They are an invaluable tool for finding probabilities and understanding the likelihood of different outcomes.
For example, with our Z-score of -0.5 from the SAT exercise, looking it up in a Z-table or using statistical software like StatCrunch, shows the probability (or area under the curve) that a randomly selected SAT score is less than 450. This process makes data analysis more intuitive and less dependent on complex computations.
Probability and Statistics
Probability and statistics are branches of mathematics that are fundamental to many fields, including data science, economics, and social sciences. Probability is the measure of the likelihood that an event will occur, while statistics involves the collection, analysis, interpretation, and presentation of data.
  • In the context of normal distribution, probability helps us determine the likelihood of a certain score within a distribution.
  • Descriptive statistics give us a way to summarize data sets using measures like mean and standard deviation,
  • While inferential statistics allow us to make predictions or inferences about a population based on sample data.
In our example, we calculated the probability of scoring less than 450 by using the Z-score and finding its corresponding probability value from the standard normal distribution. This is a common practice in statistics, where the goal is to understand and interpret data meaningfully.

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Most popular questions from this chapter

For each question, find the area to the right of the given \(z\) -score in a standard Normal distribution. In this question, round your answers to the nearest \(0.000\). Include an appropriately labeled sketch of the \(N(0,1)\) curve. a. \(z=-4.00\) b. \(z=-8.00\) c. \(z=-30.00\) d. If you had the exact probability for these right proportions, which would be the largest and which would be the smallest? e. Which is equal to the area in part b: the area below (to the left of) \(z=8.00\) or the area above (to the right of) \(z=8.00 ?\)

According to the Centers of Disease Control and Prevention, \(44 \%\) of U.S. households still had landline phone service. Suppose a random sample of 60 U.S. households is taken. a. Find the probability that exactly 25 of the households sampled still have a landline. b. Find the probability that more than 25 households still have a landline. c. Find the probability that at least 25 households still have a landline. d. Find the probability that between 20 and 25 households still have a landline.

Toss a fair six-sided die. The probability density function (pdf) in table form is given. Make a graph of the pdf for the die. $$\begin{array}{lcccccc}\text { Number of Spots } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Probability } & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6\end{array}$$

For each situation, identify the sample size \(n\), the probability of a success \(p\), and the number of success \(x .\) When asked for the probability, state the answer in the form \(b(n, p, x)\). There is no need to give the numerical value of the probability. Assume the conditions for a binomial experiment are satisfied. A 2017 Gallup poll found that \(53 \%\) of college students were very confident that their major will lead to a good job. a. If 20 college students are chosen at random, what's the probability that 12 of them were very confident their major would lead to a good job? b. If 20 college students are chosen at random, what's the probability that 10 of them are not confident that their major would lead to a good job?

Quantitative SAT scores are approximately Normally distributed with a mean of 500 and a standard deviation of \(100 .\) On the horizontal axis of the graph, indicate the SAT scores that correspond with the provided \(z\) -scores. (See the labeling in Exercise 6.14.) Answer the questions using only your knowledge of the Empirical Rule and symmetry. a. Roughly what percentage of students earn quantitative SAT scores greater than \(500 ?\) i. almost all iii. \(50 \%\) \(\mathrm{v}\). about \(0 \%\) ii. \(75 \%\) iv. \(25 \%\) b. Roughly what percentage of students earn quantitative SAT scores between 400 and \(600 ?\) i. almost all iii. \(68 \%\) \(\mathrm{v}\). about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) c. Roughly what percentage of students earn quantitative SAT scores greater than \(800 ?\) i. almost all iii. \(68 \%\) \(\mathrm{v}\). about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) d. Roughly what percentage of students earn quantitative SAT scores les: than \(200 ?\) i. almost all iii. \(68 \%\) \(\mathrm{v}\). about \(0 \%\) ii. \(95 \%\) iv. \(34 \%\) e. Roughly what percentage of students earn quantitative SAT scores between 300 and \(700 ?\) i. almost all iii. \(68 \%\) v. \(2.5 \%\) ii. \(95 \%\) iv. \(34 \%\) f. Roughly what percentage of students earn quantitative SAT scores between 700 and 800 ? i. almost all iii. \(68 \%\) v. \(2.5 \%\) ii. \(95 \%\) iv. \(34 \%\)

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